I am converting a date using CONVERT(varchar,DateOfBirth,101) for birthdates.
I want to show these dates with the current year, I've tried REPLACE but you can't use wildcards with it and when I use DATEPART, it doesn't format with the right digits for month and day. I also can't add years because they are wildly different birthdates. Thanks.
If you want to display the date as a string in 101 format for current year, one option uses a direct format():
format(DateOfBirth, 'MM/dd/2020')
You can compute the current date dynamically:
format(DateOfBirth, concat('MM/dd/', year(getdate())))
On the other hand, if you want your result as a date, then you could use datefromparts():
datefromparts(year(getdate()), month(DateOfBirth), day(DateOfBirth))
If it is a datevalue, you can use FORMAT function. If it is a character value, you can use RIGHT and REPLACE.
DECLARE #dateValue DATETIME = '05/12/1999'
DECLARE #dateCharValue VARCHAR(12) = '05/12/1999'
SELECT FORMAT(#dateValue, 'MM/dd/2020')
SELECT REPLACE(#dateCharValue, RIGHT(#dateCharValue,4),2020)
--Result
05/12/2020
This could helped you:
The code CONVERT(varchar(5),GETDATE(),1) return this 05/27 and then just add the year of the date
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + cast(year(getdate()) as varchar)
Or
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + convert(varchar,year(getdate()))
The result of both:
05/27/2020 --(This is my current date n.n )
This work but if you use a string something like your example DateOfBirth will be the variable and if this is a string (DateOfBirth = '5/27/1987') you need to convert the string DateOfBirth to Date:
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + cast(year(GETDATE()) as varchar)
Or
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + convert(varchar,year(GETDATE()))
The Result of Both :
05/27/2020
Related
I want to fetch only month and year from a date column in SQL Server.
Example: if today's date is 02/03/2019, then I want 0319.
Note: I want the result in same order (2 digit month and 2 digit year). Zero should not be removed from month.
As an alternative approach, you could go for:
RIGHT(REPLACE(CONVERT(varchar(8),DateColumn,3),'/',''),4)
You can create a number using:
select month(datecol) * 100 + (year(datecol) % 100)
Prepending the zeros requires a bit more work:
select right('0' + convert(varchar(255), month(datecol) * 100 + (year(datecol) % 100)), 4)
Or, you can use format():
select format(datecol, 'MMyy')
You can try this
substring(convert(nvarchar,#date,12),3,2) + left(convert(nvarchar,#date,12),2)
You can create an user defined function, and then apply to your column/s
create function udf_Getmonthyear(#date as date)
RETURNS nchar(4)
BEGIN
DECLARE #d_format nchar(6) = (select convert(nvarchar,#date,12))
RETURN (select SUBSTRING(#d_format,3,2) + left(#d_format,2))
end
go
Use function DATEPART in TSQL to get any part of a DateTime value. e.g:
DATEPART(yy,datecol) gives you 4 digit year part of a DateTime column (e.g: datecol), using the % (modulus) operator you can get 2 digit year DATEPART(yy,datecol)%100.
DATEPART(mm,datecol) gives you month part of the datecol field.
select Right('0'+cast(DATEPART(mm,datecol) as varchar(2)),2) +
Right('0'+cast(DATEPART(yy,datecol)%100 as varchar(2)),2) MonthYearPart
from MyTable
Regards
Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
Trying to output something like:
2016,11
Using this:
SELECT
CONVERT(VARCHAR(20),YEAR(GETDATE()) + ',' + MONTH(GETDATE())) AS YearMonth
Am I missing something in convert? Because I am getting this error:
Conversion failed when converting the varchar value ',' to data type
int.
Thanks
Try this.
SELECT
CONVERT(VARCHAR(20),YEAR(GETDATE())) + ',' + CONVERT(VARCHAR(20), MONTH(GETDATE())) AS YearMonth
You might use CONVERT with 112 to reach a string without delimiters ("20161110"). Converting this to VARCHAR(*6*) will implicitly cut the day. One (in most cases positiv) side-effect: You will get a low month zero padded (e.g. 2016,04). Then I use STUFF to insert the ,:
SELECT STUFF(CONVERT(VARCHAR(6),GETDATE(),112),5,0,',')
If you do not like the zero padded month, you could replace the 0 in STUFF like this:
DECLARE #d DATETIME={d'2016-04-05'};
SELECT STUFF(CONVERT(VARCHAR(6),#d,112),5,CASE WHEN MONTH(#d)<10 THEN 1 ELSE 0 END,',')
You are missing converting the output of MONTH() to a string. Here is one method:
select datename(year, getdate()) + ',' + cast(month(getdate()) as varchar(255)) as YearMonth
datename() is convenient because it returns a string. Unfortunately, for month it returns the name of the month, rather than the number.
You could also do:
select replace(convert(varchar(7), getdate(), 120), '-', ',')
Or use format() in SQL Server 2012+:
select format(getdate(), 'yyyy,MM')
I have a table with 2 columns: Customer_ID, which is a string, identifying each client and Time_id: a string with 14 characters, identifying timestamp of a transaction. Example:
Customer_id; Time_id
12345; 20140703144504
I want to be able to use datediff in hours datepart, but I can´t seem to be able to convert time_id properly. I use the following query:
update transation_table
set time_id= (
convert(timestamp, time_id)
)
It works, but removes hours datepart, which is what I need. For day datepart I can do it, converting to datetime. How can I keep in the table the hh?
edit: I´m running MS SQL Server 2014.
best regards
Using the convert and string concatenation below, you can use DATEPART on the resulting value.
DECLARE #tmp TABLE(
Customer_id VARCHAR(50),
Time_id VARCHAR(50)
)
INSERT INTO #tmp
SELECT '12345','20140703144504'
select
*,CONVERT(DATETIME,
SUBSTRING(Time_id,5,2) + '/' +
SUBSTRING(Time_id,7,2) + '/' +
SUBSTRING(Time_id,1,4) + ' ' +
SUBSTRING(Time_id,9,2) + ':' +
SUBSTRING(Time_id,11,2) + ':' +
SUBSTRING(Time_id,13,2)
,101
)
from #tmp
Use FORMAT to get a string representation of the value in a supported format (ODBC canonical in the Date and Time styles chart), then use TRY_CONVERT to return an actual datetime value:
SELECT TRY_CONVERT(DATETIME,
FORMAT(CAST('20140703144504' AS BIGINT),
'####-##-## ##:##:##'),
120);
This requires SQL Server 2012+.
As mentioned elsewhere, the data should be stored in a single datetime2 column, or paired date and time columns. The above functions can be used to help convert existing data to the new column(s).
Basically I have 3 separate columns in a table. I will call them SMonth, Sday, Syear. They are stored as numeric values for some reason. I can use the following string to format them into what looks like a date but doesn't allow me to use functions such as sort, order by, datediff or dateadd.
CAST(SMonth AS varchar(2)) + '/' + CAST(SDay varchar(2)) + '/' + CAST(SYear AS varchar(4))
Anyone know how to convert this into a workable date, without changing the table?
It doesn't matter how it looks as long as I can use it ie a date or datetime makes no difference.
Thanks in advance.
Just convert your result into a date or datetime.
DECLARE #SMonth AS INT = 12
DECLARE #SDay AS INT = 31
DECLARE #SYear as INT = 2013
SELECT CONVERT(DATE,CAST(#SMonth AS varchar(2)) + '/' + CAST(#SDay AS varchar(2)) + '/' + CAST(#SYear AS varchar(4)))
you should convert format the string as yyyy/mm/dd in order to make sure that SQL Server uses ODBC canonical format
SELECT CONVERT(date, CONVERT(varchar, Syear) + '/' + convert(VARCHAR, SMonth) + '/' + convert(VARCHAR, SDay ) )
Otherwise it your results could depend on the default dateformat or someone changed it using SET DATEFORMAT, for example:
05/10/2013 could mean
May 10, 2013 if the DATEFORMAT is U.S.
October 5, 2013 if the DATEFORMAT is Brithish / French
see this for complete reference of dateformat