I need to strip out part of a date (stored in my database table as a datetime field) in the form 'YYYYMMDD'. I would like the output to be an integer.
For example the datetime 2017-03-28 20:44:35.000 would convert to 20170328.
This is my attempt so far:
CAST(
CAST(DATEPART(year,transcriptCreationDateUTC) AS varchar(4))
+ CAST(DATEPART(month,transcriptCreationDateUTC) AS varchar(4))
+ CAST(DATEPART(day,transcriptCreationDateUTC) AS varchar(4))
AS int)
This is ugly to say the least, and also has the issue that it strips out leading zeros in the month and day fields, so for example 2017-03-28 20:44:35.000 converts to 2017328 not 20170328 as I would like.
There must be a better way, any help appreciated!
CONVERT with style 112 (which is YYYYMMDD format):
SELECT CONVERT(VARCHAR(8),transcriptCreationDateUTC,112)
If you really need the result as an INT, wrap in a CAST(... AS INT):
SELECT CAST(CONVERT(VARCHAR(8),transcriptCreationDateUTC,112) AS INT)
Huh? Just convert to a date:
select cast(transcriptCreationDateUTC as date)
If you want this as a string:
select format(transcriptCreationDateUTC, 'yyyyMMdd')
If you are using a pre-2012 version of SQL Server, you can do:
select convert(varchar(10), transcriptCreationDateUTC, 112)
If you want these as an integer (which is not obvious given that your query returns a string), just convert these to an integer:
select cast(format(transcriptCreationDateUTC, 'yyyyMMdd') as int)
Or, use this arithmetic:
select (year(transcriptCreationDateUTC) * 10000 +
month(transcriptCreationDateUTC) * 100 +
day(transcriptCreationDateUTC)
) as yyyymmdd
Related
I am converting a date using CONVERT(varchar,DateOfBirth,101) for birthdates.
I want to show these dates with the current year, I've tried REPLACE but you can't use wildcards with it and when I use DATEPART, it doesn't format with the right digits for month and day. I also can't add years because they are wildly different birthdates. Thanks.
If you want to display the date as a string in 101 format for current year, one option uses a direct format():
format(DateOfBirth, 'MM/dd/2020')
You can compute the current date dynamically:
format(DateOfBirth, concat('MM/dd/', year(getdate())))
On the other hand, if you want your result as a date, then you could use datefromparts():
datefromparts(year(getdate()), month(DateOfBirth), day(DateOfBirth))
If it is a datevalue, you can use FORMAT function. If it is a character value, you can use RIGHT and REPLACE.
DECLARE #dateValue DATETIME = '05/12/1999'
DECLARE #dateCharValue VARCHAR(12) = '05/12/1999'
SELECT FORMAT(#dateValue, 'MM/dd/2020')
SELECT REPLACE(#dateCharValue, RIGHT(#dateCharValue,4),2020)
--Result
05/12/2020
This could helped you:
The code CONVERT(varchar(5),GETDATE(),1) return this 05/27 and then just add the year of the date
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + cast(year(getdate()) as varchar)
Or
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + convert(varchar,year(getdate()))
The result of both:
05/27/2020 --(This is my current date n.n )
This work but if you use a string something like your example DateOfBirth will be the variable and if this is a string (DateOfBirth = '5/27/1987') you need to convert the string DateOfBirth to Date:
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + cast(year(GETDATE()) as varchar)
Or
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + convert(varchar,year(GETDATE()))
The Result of Both :
05/27/2020
Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
Trying to output something like:
2016,11
Using this:
SELECT
CONVERT(VARCHAR(20),YEAR(GETDATE()) + ',' + MONTH(GETDATE())) AS YearMonth
Am I missing something in convert? Because I am getting this error:
Conversion failed when converting the varchar value ',' to data type
int.
Thanks
Try this.
SELECT
CONVERT(VARCHAR(20),YEAR(GETDATE())) + ',' + CONVERT(VARCHAR(20), MONTH(GETDATE())) AS YearMonth
You might use CONVERT with 112 to reach a string without delimiters ("20161110"). Converting this to VARCHAR(*6*) will implicitly cut the day. One (in most cases positiv) side-effect: You will get a low month zero padded (e.g. 2016,04). Then I use STUFF to insert the ,:
SELECT STUFF(CONVERT(VARCHAR(6),GETDATE(),112),5,0,',')
If you do not like the zero padded month, you could replace the 0 in STUFF like this:
DECLARE #d DATETIME={d'2016-04-05'};
SELECT STUFF(CONVERT(VARCHAR(6),#d,112),5,CASE WHEN MONTH(#d)<10 THEN 1 ELSE 0 END,',')
You are missing converting the output of MONTH() to a string. Here is one method:
select datename(year, getdate()) + ',' + cast(month(getdate()) as varchar(255)) as YearMonth
datename() is convenient because it returns a string. Unfortunately, for month it returns the name of the month, rather than the number.
You could also do:
select replace(convert(varchar(7), getdate(), 120), '-', ',')
Or use format() in SQL Server 2012+:
select format(getdate(), 'yyyy,MM')
I have a table with 2 columns: Customer_ID, which is a string, identifying each client and Time_id: a string with 14 characters, identifying timestamp of a transaction. Example:
Customer_id; Time_id
12345; 20140703144504
I want to be able to use datediff in hours datepart, but I can´t seem to be able to convert time_id properly. I use the following query:
update transation_table
set time_id= (
convert(timestamp, time_id)
)
It works, but removes hours datepart, which is what I need. For day datepart I can do it, converting to datetime. How can I keep in the table the hh?
edit: I´m running MS SQL Server 2014.
best regards
Using the convert and string concatenation below, you can use DATEPART on the resulting value.
DECLARE #tmp TABLE(
Customer_id VARCHAR(50),
Time_id VARCHAR(50)
)
INSERT INTO #tmp
SELECT '12345','20140703144504'
select
*,CONVERT(DATETIME,
SUBSTRING(Time_id,5,2) + '/' +
SUBSTRING(Time_id,7,2) + '/' +
SUBSTRING(Time_id,1,4) + ' ' +
SUBSTRING(Time_id,9,2) + ':' +
SUBSTRING(Time_id,11,2) + ':' +
SUBSTRING(Time_id,13,2)
,101
)
from #tmp
Use FORMAT to get a string representation of the value in a supported format (ODBC canonical in the Date and Time styles chart), then use TRY_CONVERT to return an actual datetime value:
SELECT TRY_CONVERT(DATETIME,
FORMAT(CAST('20140703144504' AS BIGINT),
'####-##-## ##:##:##'),
120);
This requires SQL Server 2012+.
As mentioned elsewhere, the data should be stored in a single datetime2 column, or paired date and time columns. The above functions can be used to help convert existing data to the new column(s).
how do i convert/cast a column contains strings e.g. Jan.08,Feb.08.. into date format so that i can sort them?
Greatest Thanks!
I'd just format as a convertible string for the first of the relevant month, and then cast to datetime, e.g.
CAST('1.' + YourMonthAndYearColumnName AS DATETIME)
...is an expression that will yield a datetime that should be sortable, so:
SELECT
YourMonthAndYearColumnName
FROM
YourTable
ORDER BY
CAST('1.' + YourMonthAndYearColumnName AS DATETIME)
...should do what you're looking for.
If you can make the assumption that all dates will be within the last ten years, you can use the following code:
select convert(datetime, replace('Jan.08', '.', ' 20'))
select convert(datetime, replace('Dec.08', '.', ' 20'))
That formats the string into the format "Jan 2008", which is unambiguous. "Dec.08" could be "8th December this year" or "The month of december 2008".
Or you could use Matt Gibson's suggestion of prepending a "1." to your date before conversion. That removes the ambiguity, and has the advantage of using whatever defaults that SQL server has for dates (i.e. 50 is 1950 and 49 is 2049).
select convert(datetime, '1.' + 'Jan.08')
select convert(datetime, '1.' + 'Dec.49')
select convert(datetime, '1.' + 'Jan.50')