Could anyone provide a code to calculate week no from current date in current quarter? E.g. today is Oct 6 2022, it lies in quarter 4, so week no is 1. Code should be in big query sql.
Considering 13 weeks per quarter and using ISO week number, you can try this:
SELECT EXTRACT(ISOWEEK FROM CURRENT_DATE()) - (13 * (EXTRACT(QUARTER FROM CURRENT_DATE())-1))
Output:
1
Related
I google data studio, I have a field called week that contains the week number the value is string 'Week 2' for example. How can I extract the last day of the week based on the week number. In this case I want to get 2023-01-14 which is the last day of week 2?
enter image description here
Have you tried the last_day function?
I would build from the using the date using last_day, because from the week number it would require a bit more code.
SELECT *,
LAST_DAY(today, WEEK) AS last_day_of_week,
EXTRACT(WEEK FROM today) AS week_number
FROM (SELECT CURRENT_DATE() AS today)
But if you need to go with just the week number, I recommend taking a look into this other question How to create date based on year, week number and day in bigquery .
The following code works:
DATEtime_ADD(DATEtime_TRUNC(DATEtime_ADD(DATEtime_TRUNC(date, WEEK), INTERVAL (week-1) * 1 DAY), WEEK), INTERVAL 6 DAY)
I have a weekly report that uses these date parameters:
SELECT *
FROM TABLE
WHERE DATE_FIELD BETWEEN (CURRENT DATE - 8 DAYS) AND (CURRENT DATE - 2 DAYS)
This runs on Mondays to gather the previous week's data (Sun-Sat). What I want now is to run this for the same week of the previous year.
So for example, if the code above runs on Mon 29/06/20, it returns data from Sun 21/06/20 - Sat 27/06/20, i.e. week 26 of 2020. I want it to return data from Sun 23/06/19 - Sat 29/06/19, i.e. week 26 of 2019.
The report runs automatically so I can't just plug in the exact dates each time. I also can't just offset the date parameters to -357 and -367 days, as this gets thrown off by leap years.
I've searched for solutions but they all seem to rely on the DATEADD function, which my DB2 database doesn't recognise.
Does anyone know how I can get the result I'm looking for, please? Any advice would be appreciated! :)
The easiest way to do this is to build a calendar or dates table...(google sql calendar table)
Among the columns you'd have would be
date
year
month
quarter
dayofWeek
startOfWeek
endOfWeek
week_nbr
You can use the week() or week_iso() functions when loading the table, pay attention to the differences and pick the best fit for you.
Such a calendar table makes it easy to compare current period vs prior period.
If you assume that all years have 52 weeks, you can use date arithmetic:
SELECT *
FROM TABLE
WHERE DATE_FIELD BETWEEN (CURRENT DATE - (8 + 364) DAYS) AND (CURRENT DATE - (2 + 364) DAYS)
Because you want the week to start on a Monday, this doesn't have to take leap years into account. It is subtracting exactly 52 weeks -- and leap years do no affect weeks.
This gets more complicated if you have to deal with 52 or 53 week years.
A little bit complicated, but it should work. You may run it as is or test your own date.
SELECT
YEAR_1ST_WEEK_END + WEEKS_TO_ADD * 7 - 6 AS WEEK_START
, YEAR_1ST_WEEK_END + WEEKS_TO_ADD * 7 AS WEEK_END
FROM
(
SELECT
DATE((YEAR(D) - 1)||'-01-01')
+ (7 - DAYOFWEEK(DATE((YEAR(D) - 1)||'-01-01'))) AS YEAR_1ST_WEEK_END
, WEEK(D) - 2 AS WEEKS_TO_ADD
FROM (VALUES DATE('2020-06-29')) T(D)
);
The intermediate column YEAR_1ST_WEEK_END value is the 1-st Sat (end of week) of previous year for given date.
WEEKS_TO_ADD is a number of weeks to add to the YEAR_1ST_WEEK_END date.
I have to generate year wise, weekly reports for some data. Now When I aggregate date on week number, and week number is calculated from extract from creation date.
Now the problem is these both queries return week number 52.
SELECT EXTRACT(WEEK FROM TIMESTAMP '2006-01-01');
SELECT EXTRACT(WEEK FROM TIMESTAMP '2006-12-31');
First query return 52 (52nd week of 2005) and 2nd query return 52 (52nd week of year 2006). thats documented behavior.
But I want to Calculate local week number, and results for first query should be 1 and other query would return 53.
You can't do this with the exctract() function, it only supports ISO weeks.
But the to_char() function has an option for this:
SELECT to_char(DATE '2006-01-01', 'WW')::int` --> 1
SELECT to_char(DATE '2006-12-31', 'WW')::int` --> 53
For date 2006-01-01 end week is start in 2005 year, that same problem is 1999 year.
Clausule EXTRACT(WEEK getting year where week is started not ending.
You can use this code:
SELECT floor(EXTRACT(doy FROM TIMESTAMP '2006-01-01')/7 + 1);
SELECT floor(EXTRACT(doy FROM TIMESTAMP '2006-12-31')/7 + 1);
I need some help in writing an SQL in SQL Server where I need to count number of rows group by weeks. There is a tricky description of week which is following
- For any date before 08/13/2015 the week is of 7 days (i.e. from Thu through Wed)
- For date 08/13/2015 the week is consider a 9 day week (i.e. from Thursday through Friday so its between 08/13/2015 through 08/21/2015)
- For date 08/22/2015 the week is back to 7 days (i.e. Sat through Friday)
Now having said all the above the result I want to see in my report is the following way . NOTE: WE column in the below attached image is the last day of the week for the range.
Sample Result Image
Just write a case statement for the 3 different options. You can find the start day with something like this:
DATEADD(week, DATEDIFF(day, 3,getdate()) / 7, 3) -- Thursdays
DATEADD(week, DATEDIFF(day, 5,getdate()) / 7, 5) -- Saturdays
The numbers 3 and 5 come from the fact that day 0 (=1.1.1900) is Monday.
If you use this a lot, it might be a good idea to write a inline table valued function to return the dates you need.
What is the correct expression to use for todays date plus 1 year.
I assume it starts with Now()+ but im unsure from there
This page has lots of great examples, including:
=DateAdd(DateInterval.Month, 6, Parameters!StartDate.Value)
From that and the example before it, it looks like you want:
=DateAdd(DateInterval.Year, 1, Today())
this should be what your looking for:
--midnight last day of last month
select DateAdd(mm,-0,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month
select DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of last month 1 year ago
select DateAdd(yy,-1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month 1 year ago
select DateAdd(yy,-1,DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)))))