Here is the query I have: I would like to display 6 periods back and 12 periods forward from the value in the PERIOD column:
SELECT
item_id,
min(period),
min(picks_class),
min(vau_class),
min(warehouse_code),
min(stocked)
FROM
(select
i.warehouse_code,
ih.item_id,
ih.picks_class,
ih.period,
ih.vau_class,
ih.stocked,
substr(i.pareto_set, 6, 6) AS "Policy"
from d_item_history ih
join d_item_snapshot i on ih.item_id=i.id
where ih.picks_class='P2'
and i.supplier_code='DC'
and ih.valid_for_calc='Y'
and ih.vau_class in ('C1', 'C2')
and i.warehouse_code='YAFD'
-- and ih.item_id='1427084842208'
order by ih.period asc
)
group by item_id
;
Here is the output of the code: I would like to display the picks class for each one of the ITEM_IDs; 6 periods back from queried period and 12 months forward.
Please let me know if that is at all possible if/or how. All help is appreciated
When you want to calculate 6 periods back or 12 periods forward, Are you looking to move by months ? If so, the following code snippet might help you :
select to_char(add_months(to_date(period,'YYYYMM'),-6),'YYYYMM') PERIOD_6,
to_char(add_months(to_date(period,'YYYYMM'),12),'YYYYMM')PERIOD_12
from dual
Related
I would like to run the below query that looks like this for week 1:
Select week(datetime), count(customer_call) from table where week(datetime) = 1 and week(orderdatetime) < 7
... but for weeks 2, 3, 4, 5 and 6 all in one query and with the 'week(orderdatetime)' to still be for the 6 weeks following the week(datetime) value.
This means that for 'week(datetime) = 2', 'week(orderdatetime)' would be between 2 and 7 and so on.
'datetime' is a datetime field denoting registration.
'customer_call' is a datetime field denoting when they called.
'orderdatetime' is a datetime field denoting when they ordered.
Thanks!
I think you want group by:
Select week(datetime), count(customer_call)
from table
where week(datetime) = 1 and week(orderdatetime) < 7
group by week(datetime);
I would also point out that week doesn't take the year into account, so you might want to include that in the group by or in a where filter.
EDIT:
If you want 6 weeks of cumulative counts, then use:
Select week(datetime), count(customer_call),
sum(count(customer_call)) over (order by week(datetime)
rows between 5 preceding and current row) as running_sum_6
from table
group by week(datetime);
Note: If you want to filter this to particular weeks, then make this a subquery and filter in the outer query.
How do I average the last 6 months of sales within SQL?
Here are my tables and fields:
IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD,
IM_ItemWhseHistoryByPeriod.FISCALCALYEAR,
And I need to average these fields
IM_ItemWhseHistoryByPeriod.DOLLARSSOLD,
IM_ItemWhseHistoryByPeriod.QUANTITYSOLD,
The hard part I'm having is understanding how to average the last whole 6 months, ie. fsicalcalperiod 2-6(inside fiscalcalyear 2017).
I'm hoping for some help on what the SQL command text should look like since I'm very new to manipulating SQL outside of the UI.
Sample Data
My Existing SQL String:
SELECT IM_ItemWhseHistoryByPeriod.ITEMCODE,
IM_ItemWhseHistoryByPeriod.DOLLARSSOLD,
IM_ItemWhseHistoryByPeriod.QUANTITYSOLD,
IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD,
IM_ItemWhseHistoryByPeriod.FISCALCALYEAR
FROM MAS_AME.dbo.IM_ItemWhseHistoryByPeriod
IM_ItemWhseHistoryByPeriod
ScaisEdge Attempt #1
if fiscalyear and fiscalperiod are number you could use
select avg(IM_ItemWhseHistoryByPeriod.DOLLARSSOLD) ,
avg(IM_ItemWhseHistoryByPeriod.QUANTITYSOLD)
from my_table
where IM_ItemWhseHistoryByPeriod.FISCALCALYEAR = 2017
and IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD between 2 and 6
or for each item code
select itemcode, avg(IM_ItemWhseHistoryByPeriod.DOLLARSSOLD) ,
avg(IM_ItemWhseHistoryByPeriod.QUANTITYSOLD)
from my_table
where IM_ItemWhseHistoryByPeriod.FISCALCALYEAR = 2017
and IM_ItemWhseHistoryByPeriod.FISCALCALPERIOD between 2 and 6
group by itemcode
Try the following solution and see if it works for you:
select avg(DOLLARSSOLD) as AvgDollarSod,
avg(QUANTITYSOLD) as AvgQtySold
from IM_ItemWhseHistoryByPeriod
where FISCALCALYEAR = '2017
and FISCALCALPERIOD between 2 and 6
Hi I have source data in a field in different formats like below
1Y3M6D (1 Year, 3 Months, 6 Days) I need to split this into 3 fields Year, Month, Days but the source data format can change like month can come first as 3M1Y6D OR source data can only have 3M with no year and day. How do I write a query to get the preceding number from M, Y or D?
Thanks in advance for help.
Thanks everyone, Unoembre command helped.
select my_value, REGEXP_SUBSTR(my_value,'(\d+)Y',1,1,NULL,1) REG_Y, REGEXP_SUBSTR(my_value,'(\d+)M',1,1,NULL,1) REG_M, REGEXP_SUBSTR(my_value,'(\d+)D',1,1,NULL,1) REG_D from ( select '3M6Y2D' my_value from dual );
I am calling the data query in ssrs like this:
SELECT * FROM [DATABASE].[dbo].[mytable]
So, the current week is the last week from the query (e.g. 3/31 - 4/4) and each number represents the week before until we have reached the 12 weeks prior to this week and display in a point chart.
How can I accomplish grouping all the visits for all locations by weeks and adding it to the chart?
I suggest updating your SQL query to Group by a descending Dense_Rank of DatePart(Week,ARRIVED_DATE). In this example, I have one column for Visits because I couldn't tell which columns you were using to get your Visit count:
-- load some test data
if object_id('tempdb..#MyTable') is not null
drop table #MyTable
create table #MyTable(ARRIVED_DATE datetime,Visits int)
while (select count(*) from #MyTable) < 1000
begin
insert into #MyTable values
(dateadd(day,round(rand()*100,0),'2014-01-01'),round(rand()*1000,0))
end
-- Sum Visits by WeekNumber relative to today's WeekNumber
select
dense_rank() over(order by datepart(week,ARRIVED_DATE) desc) [Week],
sum(Visits) Visits
from #MyTable
where datepart(week,ARRIVED_DATE) >= datepart(week,getdate()) - 11
group by datepart(week,ARRIVED_DATE)
order by datepart(week,ARRIVED_DATE)
Let me know if I can provide any more detail to help you out.
You are going to want to do the grouping of the visits within SQL. You should be able to add a calculated column to your table which is something like WorkWeek and it should be calculated on the days difference from a certain day such as Sunday. This column will then by your X value rather than the date field you were using.
Here is a good article that goes into first day of week: First Day of Week
I have a table that has a date, item, and quantity.
I need a sql query to return the totals per day, but the total is the quantity minus the previous day totals. The quantity accumulates as the month goes on. So the 1st could have 5 the 2nd have 12 and the 3rd has 20.
So the 1st adds 5
2nd adds 7 to make 12
3rd adds 8 to make 20.
I've done something like this in the past, but can not find it or remember. I know i'll need a correlated sub-query.
TIA
--
Edit 1
I'm using Microsoft Access.
Date is a datetime field,
item is a text, and
quantity is number
--
Edit 2
Ok this is what i have
SELECT oos.report_date, oos.tech, oos.total_cpe, oos_2.total_cpe
FROM oos INNER JOIN (
SELECT oos_2.tech, Sum(oos_2.total_cpe) AS total_cpe
FROM oos_2
WHERE (((oos_2.report_date)<#10/10/2010#))
GROUP BY oos_2.tech
) oos_2 ON oos.tech = oos_2.tech;
How do i get the oos.report_date into where i says #10/10/2010#. I thought I could just stick it in there like mysql, but no luck. I'm gonna continue researching.
Sum them by adding one to the date and making the value negative, thus taking yesterday's total from today's:
SELECT report_date, tech, Sum(total_cpe) AS total_cpe
FROM (
SELECT oos.report_date, oos.tech, oos.total_cpe
FROM oos
UNION ALL
SELECT oos.report_date+1, oos.tech, 0-oos.total_cpe
FROM oos
)
WHERE (report_date < #10/10/2010#)
GROUP BY report_date, tech
ORDER BY report_date, tech
Ok, I figured it out.
SELECT o.report_date, o.tech, o.total_cpe,
o.total_cpe - (
SELECT IIf(Sum(oos.total_cpe) is null, 0,Sum(oos.total_cpe)) AS total_cpe
FROM oos
WHERE (((oos.tech)=o.tech) AND ((oos.report_date)<o.report_date))
) AS total
FROM oos o;