I want to combine two columns in such a way that the second column gets added below the first column.
For eg:
Col 1: A B C
Col 2: D E F
Result :
Col : A B C D E F
Do a UNION ALL to get the two columns as one single column:
select col1 from tablename
UNION ALL
select col2 from tablename
If you absolutely want col1 values before col2 values, wrap it up in a derived table and add an ORDER BY:
select col from
(
select col1 as col, 1 as ob from tablename
UNION ALL
select col2, 2 as ob from tablename
) dt
order by ob
SELECT CONCAT(col1, col2) AS col FROM table
Related
I need to remove the duplicates from a table with 139 columns based on 2 columns and load the unique rows with 139 columns into another table.
eg :
col1 col2 col3 .....col139
a b .............
b c .............
a b .............
o/p:
col1 col2 col3 .....col139
a b .............
b c .............
need a SQL query for DB2?
If the "other table" does not exist yet you can create it like this
CREATE TABLE othertable LIKE originaltable
And the insert the requested row with this statement:
INSERT INTO othertable
SELECT col1,...,coln
FROM (SELECT
t.*,
ROW_NUMBER() OVER (PARTITION BY col1, col2 ORDER BY col1) AS num
FROM t) t
WHERE num = 1
There are numerous tools out there that generate queries and column lists - so if you do not want to write it by hand you could generate it with these tools or use another SQL statement to select it from the Db2 catalog table (syscat.columns).
You might be better just deleting the duplicates in place. This can be done without specifying a column list.
DELETE FROM
( SELECT
ROW_NUMBER() OVER (PARTITION BY col1, col2) AS DUP
FROM t
)
WHERE
DUP > 1
You can use row_number():
select t.*
from (select t.*,
row_number() over (partition by a, b order by a) as seqnum
from t
) t;
If you don't want seqnum in the result set, though, you need to list out all the columns.
To find duplicate values in col1 or any column, you can run the following query:
SELECT col1 FROM your_table GROUP BY col1 HAVING COUNT(*) > 1;
And if you want to delete those duplicate rows using the value of col1, you can run the following query:
DELETE FROM your_table WHERE col1 IN (SELECT col1 FROM your_table GROUP BY col1 HAVING COUNT(*) > 1);
You can use the same approach to delete duplicate rows from the table using col2 values.
I need an sql command that would select all rows that don't contain a certain number.
What I have:
Select * from table
Where (col1 != 1 or col2 != 1 or col3 != 1)
The problem is this does not select any rows that have either of the columns empty.
All 3 columns are integer type.
Use is distinct from instead of != for nullable columns:
select *
from my_table
where (
col1 is distinct from 1
or col2 is distinct from 1
or col3 is distinct from 1)
COUNT(DATECREATED)
88708
26625
17092
how to create a select query for viewing this three values in single column as different column names like
COUNT(DATECREATED) COUNT(DATECREATED) COUNT(DATECREATED)
88708 26625 17092
88708
88708
If you just want 1 row with 3 rows as columns, then use this. Here col is the alias for your count statement.
with tbl as
(select rownum as rno,col from
(your existing query) t
)
select (select col from tbl where rno=1) col1 ,
(select col from tbl where rno=2) col2,
(select col from tbl where rno=3 ) col3
from dual
If there are more rows and you want to use them as column, then read about Dynamic pivot in Oracle and you shall get your answer.
Finally i did like this.. Thanks all for quick reply
select sum(colname) as aliasname, sum(colname) as aliasname, sum(colname) as aliasname from
(select count(colname) as colname,0 as colname,0 as colname from cof
union all
select 0,count(colname),0 from cof where colname is not null
union all
select 0,0,count(colname) from cof where colname is not null);
I have a table which contains data as
col1 col2
a b
b a
c d
d c
a d
a c
For me row 1 and row 2 are duplicate because a, b & b, a are the same. The same stands for row 3 and row 4.
I need an SQL (not PL/SQL) query which gives output as
col1 col2
a b
c d
a d
a c
select distinct least(col1, col2), greatest(col1, col2)
from your_table
Edit: for those using a DBMS that does support the standard SQL functions least and greatest this can be simulated using a CASE expression:
select distinct
case
when col1 < col2 then col1
else col2
end as least_col,
case
when col1 > col2 then col1
else col2
end as greatest_col
from your_table
Try this:
CREATE TABLE t_1(col1 varchar(10),col2 varchar(10))
INSERT INTO t_1
VALUES ('a','b'),
('b','a'),
('c','d'),
('d','c'),
('a','d'),
('a','c')
;with CTE as (select ROW_NUMBER() over (order by (select 0)) as id,col1,col2,col1+col2 as col3 from t_1)
,CTE1 as (
select id,col1,col2,col3 from CTE where id=1
union all
select c.id,c.col1,c.col2,CASE when c.col3=REVERSE(c1.col3) then null else c.col3 end from CTE c inner join CTE1 c1
on c.id-1=c1.id
)
select col1,col2 from CTE1 where col3 is not null
I have 1 single table with 3 columns say col1,col2,col3
VALUES:
col1 with values (in individual 3 rows) as a, b, c
col2 with values (in individual 3 rows) as b, c, d
col3 with values (in individual 3 rows) as c, d, e
AIM:
To get distinct list to populate in html drop down box (i.e i want a,b,c,d,e) in alphabetical order ?
Pseudocode:
Select col1 from table
UNION
Select col2 from table
UNION
Select col3 from table