I have table like this:
Now I want to see sum of hour for each week for each project .How can i query that.
I tried with query
select CurrentData.STATUS,
sum(CurrentData.HOURS), CurrentData.WEEKS
from CURRENT_DATA CurrentData
group by currentData.HOURS, CurrentData.STATUS, CurrentData.WEEKS, CurrentData.PROJECT_ID
having currentData.WEEKS = CurrentData.WEEKS
order by CurrentData.WEEKS;
But still each week coming as separate rows.Not sure how to do it
Do not use HOURS in group by. The are in the group function SUM:
SELECT PROJECT_ID, STATUS, YEARS, WEEKS, SUM (CurrentData.HOURS)
FROM CURRENT_DATA
GROUP BY PROJECT_ID, STATUS, Years, WEEKS
ORDER BY Years, WEEKS
And what is in the having clause. That is always true. Do you want a certain week and year? And you can get rid of "CurrentData.". You have only one table and you don't need alias for this table.
Here filtered for year 2016 and summed for all project id :
SELECT STATUS, WEEKS, SUM (CurrentData.HOURS)
FROM CURRENT_DATA
WHERE Years = 2016
GROUP BY STATUS, WEEKS
ORDER BY WEEKS
Related
I have a table with SentDate and RefundAmounts. I would like to sum up the amounts on each row from the date until a year into the future for every line.
In the example below I would like to add a column that says sum for the year.
This sum should be for the first line the sum of refunds from '2006-12-14' until '2007-12-14' which would be 3696,22 as there were no refunds during that period.
The second row would be from '2007-12-24' until '2008-12-24' which would be 463,05
SentDate YearAhead RefundAmount
2006-12-14 2007-12-14 3696,22
2007-12-24 2008-12-24 394,35
2008-12-18 2009-12-18 44,33
2008-12-19 2009-12-19 24,37
2009-12-16 2010-12-16 21,88
I have tried something along the lines of
select SentDate, dateadd(year,1,sentdate) YearAhead, SumRefund
from table
but I have no idea how to get the annual future sum for each row
Thanks for the suggestion. The final result should look as follows:
SentDate YearAhead RefundAmount SumForYear
2006/12/14 2007/12/14 3696,22 3696,22
2007/12/24 2008/12/24 394,35 463,05
2008/12/18 2009/12/18 44,33 90,58
2008/12/19 2009/12/19 24,37 46,25
2009/12/16 2010/12/16 21,88 21,88
You need to join with a BETWEEN to gather all rows that compose that period, then use GROUP BY with SUM to the result.
select
T.SentDate,
dateadd(year, 1, T.SentDate) YearAhead,
SUM(P.SumRefund) AS TotalOverYear
from
YourTable AS T
INNER JOIN YourTable AS P ON P.SentDate BETWEEN T.SendDate AND DATEADD(YEAR, 1, T.SendDate)
GROUP BY
T.SentDate
Something like this should suite your needs if you always need a complete year:
select sum(refund) as refundAmounts,year(min(SentDate)) as year from yourTable group by year(SentDate)
the year function gets only the year part from a datetime row and with group by you can split the aggregation of sum and min function to different groups.
I have a view that produces the result shown in the image below. I need help with the logic.
Requirement:
List of all employees who achieved no less than 100% target in ALL Quarters in past two years.
"B" received 90% in two different quarters. An employee who received less than 100% should NOT be listed.
Notice that "A" didn't work for Q2-2016. An employee who didn't work for that quarter should NOT be listed.
"C" is the only one who worked full two years, and received 100% in each quarter.
Edit: added image link showing Employee name,Quarter, Year, and the score.
https://i.imgur.com/FIXR0YF.png
The logic is pretty easy, it's math with quarters that is a bit of a pain.
There are 8 quarters in the last two years, so you simply need to select all the employee names in the last two years with a target >= 100%, group by employee name, and apply a HAVING clause to limit the output to those employees with count(*) = 8.
To get the current year and quarter, you can use these expressions:
cast(extract('year' from current_date) as integer) as yr,
(cast(extract('month' from current_date) as integer)-1) / 3 + 1 as quarter;
Subtract 2 from the current year to find the previous year and quarter. The code will be clearer if you put these expressions in a subquery because you will need them multiple times for the quarter arithmetic. To do the quarter arithmetic you must extract the integer value of the quarter from the text values you have stored.
Altogether, the solution should look something like this:
select
employee
from
(select employee, cast(right(quarter,1) as integer) as qtr, year
from your_table
where target >= 100
) as tgt
cross join (
select
cast(extract('year' from current_date) as integer) as yr,
(cast(extract('month' from current_date) as integer)-1) / 3 + 1 as quarter
) as qtr
where
tgt.year between qtr.yr-1 and qtr.yr
or (tgt.year = qtr.yr - 2 and tgt.qtr > qtr.quarter)
group by
employee
having
count(*) = 8;
This is untested.
If you happen to be using Postgres and expect to be doing a lot of quarter arithmetic you may want to define a custom data type as described in A Year and Quarter Data Type for PostgreSQL
I am working on my Database in MS Access 2010
and i Need to build a query to Calculate the month salary for each Employee
it goes like this :
Input from user , which Year
Input from user again , which Month
Show Every Employee's Salary for the Input date
There are 2 Tables in the Query : Shifts , Employees
Shifts has a field for EmployeeID and a field for Day
Day field format is : Short Date
The problem is i don't know how to access the Month and the Year only !
I know that this is completely wrong , but i wanna do something like this:
SELECT
FROM EmployeesTBL INNER JOIN ShiftsTBL ON EmployeesTBL.EmployeeID = ShiftsTBL.EmployeeID
WHERE
Year(ShiftsTBL.Day)=[Enter Year]
AND
Month(ShiftsTBL.Day)=[Enter Month]
;
What do i need to write after SELECT to get the Sum of all Shifts and divide it by number of days the emp worked
Note : in the Shifts Table , i have EntryDate and ExitDate for every shift
Access has a bunch of built in date functions. I believe Month(date) and Year(date) will give you what you need.
Something like
SELECT EmpName
FROM Employees, Shifts
WHERE Employees.EmployeeID = Shifts.EmployeeID
AND
Month(Shifts.Day) = INPUT2.VALUE
AND
Year(Shifts.Day) = INPUT1.VALUE
should get you what you want!
EDIT: Aggregation: how this works will depend on how your database is set up. I think I understand you want to sum the hours worked and divide by the number of days?
If so, you will use Sum() and Count(). And you will Group By EmployeeID
SELECT Sum(Shifts)/Count(DaysWorked) AS SumDividedByCount
FROM EmployeesTBL INNER JOIN ShiftsTBL
ON EmployeesTBL.EmployeeID = ShiftsTBL.EmployeeID
WHERE
Year(ShiftsTBL.[Day])=[Enter Year]
AND
Month(ShiftsTBL.[Day])=[Enter Month]
GROUP BY EmployeeID
I used the WHERE clause because I think the results need to be filtered before they're grouped. If the results needed to be filtered after they were grouped, the HAVING clause would be used (and would go AFTER the GROUP BY)
I am calling the data query in ssrs like this:
SELECT * FROM [DATABASE].[dbo].[mytable]
So, the current week is the last week from the query (e.g. 3/31 - 4/4) and each number represents the week before until we have reached the 12 weeks prior to this week and display in a point chart.
How can I accomplish grouping all the visits for all locations by weeks and adding it to the chart?
I suggest updating your SQL query to Group by a descending Dense_Rank of DatePart(Week,ARRIVED_DATE). In this example, I have one column for Visits because I couldn't tell which columns you were using to get your Visit count:
-- load some test data
if object_id('tempdb..#MyTable') is not null
drop table #MyTable
create table #MyTable(ARRIVED_DATE datetime,Visits int)
while (select count(*) from #MyTable) < 1000
begin
insert into #MyTable values
(dateadd(day,round(rand()*100,0),'2014-01-01'),round(rand()*1000,0))
end
-- Sum Visits by WeekNumber relative to today's WeekNumber
select
dense_rank() over(order by datepart(week,ARRIVED_DATE) desc) [Week],
sum(Visits) Visits
from #MyTable
where datepart(week,ARRIVED_DATE) >= datepart(week,getdate()) - 11
group by datepart(week,ARRIVED_DATE)
order by datepart(week,ARRIVED_DATE)
Let me know if I can provide any more detail to help you out.
You are going to want to do the grouping of the visits within SQL. You should be able to add a calculated column to your table which is something like WorkWeek and it should be calculated on the days difference from a certain day such as Sunday. This column will then by your X value rather than the date field you were using.
Here is a good article that goes into first day of week: First Day of Week
Am looking for a query to sum values in a particular time duration say an year or a particular month in an year using MySQL syntax. Note that my transaction_date column stores daily amount transacted.
Am example of a query that returns total sales in an year query would look something like this
SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR)
Am example of a query that returns total sales in an particular month and year would look something like this
SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR)(MONTH)
How achievable is this?
SELECT SUM(transaction_amount)
WHERE YEAR(transaction_date) = '2008'
GROUP BY YEAR(transaction_date)
The second line may not be needed, depending on what you want exactly.