How to split a string in sql server using stored procedure and insert the data to table - sql

Question

<pre>update d
set d.Price = null
from dbo.SalDocumentDetail d
left join dbo.StkWarehouse w on w.WarehouseID = d.WarehouseID
where DocumentID=" + 1 + "
and DocumentTypeID=" + 2 + "
and FiscalYear= " + 2016 + "
and isnull(isPrescription,0) <>1
and w.POSType is null
and ProductName BETWEEN ''C' 'AND' 'M''
and Country LIKE ''%land%'''</pre>
Actually this string is only a sample one my original string is very large . i am not getting a point that if i break this string than how many variables i have to make to capture the data also after splitting the string i want that to be inserted into data table containing columns as Felid and Value?
I want my result like :
<pre>
Felid Value
DocumentID= 1
DocumentTypeID= 2
FiscalYear= 2016
isnull(isPrescription,0) <>= 1
w.POSType is= null
ProductName= C
ProductName= M
Country= land
</pre>

Answer 1

<pre>I Use this function but this function split 'and' not split like what i want in my result i want split 'and,or,like,is,between ' if function find any this split it to two columns (Felid and Value)</pre>
<pre>ALTER FUNCTION [dbo].[fnSplitString]
(#List NVARCHAR(MAX),#Delimiter NVARCHAR(255))
RETURNS #Items TABLE(Felid NVARCHAR(Max),Valu nvarchar(MAx))
WITH SCHEMABINDING
AS BEGIN
DECLARE #ll INT=LEN(#List)+1,#ld INT=LEN(#Delimiter);
WITH a AS
(SELECT
[end]=COALESCE(NULLIF(CHARINDEX(#Delimiter,#List,1),0),#ll),
[VlaueFelid]=SUBSTRING(#List,(select
CHARINDEX('where',#List)+5),COALESCE(NULLIF(CHARINDEX('=', #List,0),0),#ll) ) ,
[Value]=SUBSTRING(#List,(select CHARINDEX('="',#List)+2),(select CHARINDEX('and',#List))-(select C`enter code here`HARINDEX('="',#List)+3))
UNION ALL
SELECT
[end]=COALESCE(NULLIF(CHARINDEX(#Delimiter,#List,[end]+#ld), 0),#ll),
[VlaueFelid]=SUBSTRING(#List,[end]+#ld, COALESCE(NULLIF(CHARINDEX('=',#List, [end]+#ld),0),#ll)-[end]-#ld),
[Value]=SUBSTRING(#List,[end]+#ld+16, COALESCE(NULLIF(CHARINDEX('=',#List,[end]+#ld),0),#ll)-[end]-#ld-5)
FROM a WHERE [end]< #ll) INSERT #Items SELECT[VlaueFelid],[Value] FROM a WHERE LEN([VlaueFelid])>0 RETURN;
END</pre>