I have a query that looks like this:
select id, extension, count(distinct(id)) from publicids group by id,extension;
This is what the results looks like:
id | extension | count
-------------+-------------------------+-------
18459154909 | 12333 | 1
18459154909 | 9891114 | 1
18459154919 | 43244 | 1
18459154919 | 8776232 | 1
18766145025 | 12311 | 1
18766145025 | 1122111 | 1
18766145201 | 12422 | 1
18766145201 | 14141 | 1
But what I really want is for the results to look like this:
id | extension | count
-------------+-------------------------+-------
18459154909 | 12333 | 2
18459154909 | 9891114 | 2
18459154919 | 43244 | 2
18459154919 | 8776232 | 2
18766145025 | 12311 | 2
18766145025 | 1122111 | 2
18766145201 | 12422 | 2
18766145201 | 14141 | 2
I'm trying to get the count field to show the total number of records that have the same id.
Any suggestions would be appreciated
I think you want to count distincts extentions, not ids.
Run this query:
select id
, extension
(select count(*) from publicids p1 where p.id = p1.id ) distinct_id_count
from publicids p
group by id,extension;
This is more or less the same as Pastor's answer. Depending on what the optimizer does it might be faster with higher record count source tables.
select p.id, p.extension, p2.id_count
from publicids p
inner join (
select id, count(*) as id_count
from publicids group by id
) as p2 on p.id = p2.id
Related
I have three tables store, gender, age_group each of these tables have ids. I need to generate table data for each one all possible combinations of the three.
ex. store_id = (1,2,3) gender_id = (1,2,3) age_group_id = (1,2,3)
so that i have a table that looks like this:
|store_id|gender_id|age_group_id|
|:------:|:-------:|:----------:|
| 1 | 1 | 1 |
| 1 | 2 | 1 |
| 1 | 3 | 1 |
| 2 | 1 | 3 |
| 2 | 2 | 3 |
| 3 | 1 | 3 |
| 3 | 2 | 3 |
etc. continuing on until each combination is populated, any suggestions on best approach to do this in SQL
Cross join the three tables:
select
s.Id as store_id,
g.Id as gender_id,
a.Id as age_group_id
from store s
cross join gender g
cross join age_group a
How do I correctly join a table on two columns. My issue is that the result is not correct as it only joins on a single column.
This question started of in this other question: SQL query returns product of results instead of sum . I am creating a new question as there is an other issue I am trying to solve.
I join a table of materials on a table which contains multiple supply and disposal movements. Each movement references a material id. I would like to join the material on each movement.
My query:
SELECT supply_material_refer, disposal_material_refer, material_id, material_name
FROM "construction_sites"
JOIN projects ON construction_sites.project_refer = projects.project_id
JOIN addresses ON construction_sites.address_refer = addresses.address_id
cross join lateral ( select *
from (select row_number() over () as rn, *
from supplies
where supplies.supply_project_refer = projects.project_id) as supplies
full join (select row_number() over () as rn, *
from disposals
where disposals.disposal_project_refer = projects.project_id
) as disposals
on (supplies.rn = disposals.rn)
) as combined
LEFT JOIN materials material ON combined.disposal_material_refer = material.material_id
OR combined.supply_material_refer = material.material_id
WHERE (projects.project_name = 'Project 15')
ORDER BY construction_site_id asc;
The result of the query:
+-----------------------+-------------------------+-------------+---------------+
| supply_material_refer | disposal_material_refer | material_id | material_name |
+-----------------------+-------------------------+-------------+---------------+
| 1 | 1 | 1 | Materialtest |
| 2 | 1 | 1 | Materialtest |
| 2 | 1 | 2 | Dirt |
| 1 | 1 | 1 | Materialtest |
| 2 | 1 | 1 | Materialtest |
| 2 | 1 | 2 | Dirt |
| 1 | (null) | 1 | Materialtest |
| 4 | (null) | 4 | Stones |
+-----------------------+-------------------------+-------------+---------------+
An example line I have issues with:
+------------------------+-------------------------+-------------+---------------+
| supply_material_refer | disposal_material_refer | material_id | material_name |
+------------------------+-------------------------+-------------+---------------+
| 2 | 1 | 1 | Materialtest |
+------------------------+-------------------------+-------------+---------------+
A prefered output would be like:
+------------------------+----------------------+-------------------------+------------------------+
| supply_material_refer | supply_material_name | disposal_material_refer | disposal_material_name |
+------------------------+----------------------+-------------------------+------------------------+
| 2 | Dirt | 1 | Materialtest |
+------------------------+----------------------+-------------------------+------------------------+
I have created a sqlfiddle with dummy data: http://www.sqlfiddle.com/#!17/863d78/2
To my understanding the solution would be to have a disposal_material column and and supply_material column for the material names. I do not know how I can achieve this goal though...
Thanks for any help!
I have two tables, post_categories and posts. I'm trying to select * from post_categories;, but also return a temporary column with the count for each time a post category is used on a post.
Posts
| id | name | post_category_id |
| 1 | test | 1 |
| 2 | nest | 1 |
| 3 | vest | 2 |
| 4 | zest | 3 |
Post Categories
| id | name |
| 1 | cat_1 |
| 2 | cat_2 |
| 3 | cat_3 |
Basically, I'm trying to do this without subqueries and with joins instead. Something like this, but in real psql.
select * from post_categories some-type-of-join posts, count(*)
Resulting in this, ideally.
| id | name | count |
| 1 | cat_1 | 2 |
| 2 | cat_2 | 1 |
| 3 | cat_3 | 1 |
Your help is greatly appreciated :D
You can use a derived table that contains the counts per post_category_id and left join it to the post_categories table
select p.*, coalesce(t1.p_count,0)
from post_categories p
left join (
select post_category_id, count(*) p_count
from posts
group by post_category_id
) t1 on t1.post_category_id = p.id
select post_categories.id, post_categories.name , count(posts.id)
from post_categories
inner join posts
on post_category_id = post_categories.id
group by post_categories.id, post_categories.name
I have the following relations in my database:
Invoice InvoiceMeal
--------------------- ---------------------------
| InvoiceId | Total | | Id | InvoiceId | MealId |
--------------------- ---------------------------
| 1 | 22.32 | | 1 | 1 | 3 |
--------------------- ---------------------------
| 2 | 12.18 | | 2 | 1 | 2 |
--------------------- ---------------------------
| 3 | 27.76 | | 3 | 2 | 2 |
--------------------- ---------------------------
Meal Type
----------------------------------- -------------------
| Id | Name | TypeId | | Id | Name |
----------------------------------- -------------------
| 1 | Hamburger | 1 | | 1 | Meat |
----------------------------------- -------------------
| 2 | Soja Beans | 2 | | 2 | Vegetarian |
----------------------------------- -------------------
| 3 | Chicken | 2 |
-----------------------------------
What I want to query from the database is InvoiceId and Total of all Invoices which consist of at least two Meals where at least one of the Meals is of Type Vegetarian. I have the following SQL query and it works:
SELECT
i."Id", i."Total"
FROM
public."Invoice" i
WHERE
(SELECT COUNT(*)
FROM public."InvoiceMeal" im
WHERE im."InvoiceId" = i."Id" AND
(SELECT COUNT(*)
FROM public."Meal" m, public."Type" t
WHERE im."MealId" = m."Id" AND
m."TypeId" = t."Id" AND
g."Name" = 'Vegetarian') > 0
) >= 2;
My problem with this query is that I can not easily modify the condition that there must at least one vegetarien Meal. I want to be able, for example, to change it to at least two vegetarian meals. How can I achieve this with my query?
I would approach this by joining the tables together and using aggregation. The having clause can handle the conditions:
select i.Id, i.Total
from InvoiceMeal im join
Invoice i
on i.InvoiceId = im.InvoiceId join
Meal m
on im.mealid = m.mealid join
Type t
on m.typeid = t.typeid
group by i.Id, i.Total
having count(distinct im.mealid) >= 2 and
sum(case when t.name = 'Vegetarian' then 1 else 0 end) > 0;
I also see no reason to put double quotes around column names. That just makes the query harder to write and read.
We have a table like this:
+----+--------+
| Id | ItemId |
+----+--------+
| 1 | 1100 |
| 1 | 1101 |
| 1 | 1102 |
| 2 | 2001 |
| 2 | 2002 |
| 3 | 1101 |
+----+--------+
We want to count how many items each guy has, and show the guys with 2 items or more. Like this:
+----+-----------+
| Id | ItemCount |
+----+-----------+
| 1 | 3 |
| 2 | 2 |
+----+-----------+
We didn't count the guy with Id = 3 because he's got only 1 item.
How can we do this in SQL?
SELECT id, COUNT(itemId) AS ItemCount
FROM YourTable
GROUP BY id
HAVING COUNT(itemId) > 1
Use this query
SELECT *
FROM (
SELECT COUNT(ItemId ) AS COUNT, Id FROM ITEM
GROUP BY Id
)
my_select
WHERE COUNT>1
SELECT id,
count(1)
FROM YOUR_TABLE
GROUP BY id
HAVING count(1) > 1;
select Id, count(ItemId) as ItemCount
from table_name
group by Id
having ItemCount > 1