select sum statement - sql

I created this select statement I will convert to a view. I need help with this. I need to be able to add the total of Minority that = Yes and No show total on report pages.
select
ps.BidPackage_ID,
ps.Project_ID,
SUM (case ps.Minority when 'Yes' then 1 else 0 end) MinorityTotal,
SUM (case ps.Gender when 'Female' then 1 else 0 end) FemaleTotal,
SUM(case ps.Cleveland_Resident when 1 then 1 else 0 end) ClevelandResidents,
ps.SubContractor
from
PersonnelSummary ps
group by
ps.BidPackage_ID,
ps.Project_ID,
ps.SubContractor

You nearly have it:
...
SUM (case ps.Minority when 'Yes' then 1 else 0 end) AS MinorityYes,
SUM (case ps.Minority when 'No' then 1 else 0 end) AS MinorityNo,
COUNT(*) AS Total,
...
With the Total I'm assuming that every row should be counted. This is what you want if:
The only values that exist in the column are 'Yes' and 'No' or
Values different from 'Yes' and 'No' should also be counted in the total.

You're forcing us to guess what you want. You have a count of the people who said that they were in a minority; do you want a count of the people who said No? Or do you want a count of the number who said 'either "Yes" or "No"' and excluding those who gave 'decline to say' or simply no answer at all?
select
ps.BidPackage_ID,
ps.Project_ID,
SUM (case ps.Minority when 'Yes' then 1 else 0 end) MinorityTotalYes,
SUM (case ps.Minority when 'No' then 1 else 0 end) MinorityTotalNo,
SUM (case ps.Minority when 'Yes' then 1 when 'No' then 1 else 0 end)
AS StatedMinorityTotal,
SUM (case ps.Gender when 'Female' then 1 else 0 end) FemaleTotal,
SUM(case ps.Cleveland_Resident when 1 then 1 else 0 end) ClevelandResidents,
ps.SubContractor
from
PersonnelSummary ps
group by
ps.BidPackage_ID,
ps.Project_ID,
ps.SubContractor

Related

Use a 'in' statement inside a 'case' expression

How can I use IN in my "case expression"?
This is my query where I want count if any match like mumbai found then as mumbai:
select TYPEOFPRODUCT,
SUM(CASE(BRANCH) WHEN IN('Mumbai1' OR 'Mumbai2') THEN 1 ELSE 0 END) AS 'Mumbai'
SUM(CASE(BRANCH) WHEN IN('Delhi1' OR 'DelhiMain') THEN 1 ELSE 0 END) AS 'Delhi'
from los_ext
group by TYPEOFPRODUCT
You were close, you just need to comma separate values for IN rather than using OR, and there are two formats for CASE expressions, putting the field with the criteria after WHEN is more flexible, so I prefer to use it exclusively:
SELECT TYPEOFPRODUCT
,SUM( CASE WHEN BRANCH IN('Mumbai1','Mumbai2') THEN 1 ELSE 0 END) AS Mumbai
,SUM( CASE WHEN BRANCH IN('Delhi1', 'DelhiMain') THEN 1 ELSE 0 END) AS Delhi
FROM los_ext
GROUP BY TYPEOFPRODUCT
Its query select sum of individual branchs
select TYPEOFPRODUCT,
SUM(CASE WHEN (BRANCH = 'Mumbai1' OR BRANCH = 'Mumbai2' ) THEN 1 ELSE 0 END) AS 'Mumbai',
SUM(CASE WHEN (BRANCH = 'Delhi1' OR BRANCH = 'DelhiMain' ) THEN 1 ELSE 0 END) AS 'Delhi'
from los_ext
group by TYPEOFPRODUCT

Update a complex SQL query to add a new column with the sum of two columns

The below SQL query creates a table with n number of columns named in the next line.
...., curr_amount, tax_amount, ....
I am having a very tough time updating the below query to create a new column called total and position it exactly after tax_amount column and the total column should contain the values that are obtained after sum of curr_amount & tax_amount.
I have been working on this from more than one day but couldn't figure it out.
P.S. Still a noob here. Thanks alot for your time.
.
SELECT Isnull(t.total_month, 'Total') total_month,
t.tax_amount,
t.curr_amount,
t.usage_qty,
t.kh_qty,
t.bill_cnt
FROM (SELECT dbo.Sigmadf(bm.posted_date, 'YYYY-MM') total_month,
Sum(CASE
WHEN rr.usage_qty IS NULL THEN 0
ELSE Cast (rr.usage_qty AS NUMERIC(18, 2))
END) usage_qty,
Sum(CASE
WHEN bm.curr_amount IS NULL THEN 0
ELSE bm.curr_amount
END) curr_amount,
Sum(CASE
WHEN bm.adj_amount IS NULL THEN 0
ELSE bm.adj_amount
END) adj_amount,
Sum(CASE
WHEN bm.bal_fwd_amount IS NULL THEN 0
ELSE bm.bal_fwd_amount
END) bal_forward,
Sum(CASE
WHEN bm.tax_amount IS NULL THEN 0
ELSE bm.tax_amount
END) tax_amount,
Sum(CASE
WHEN bm.due_amount IS NULL THEN 0
ELSE bm.due_amount
END) due_amount,
Sum(CASE
WHEN bm.last_total_paid_amount IS NULL THEN 0
ELSE bm.last_total_paid_amount * -1
END) paid_amount,
Sum(CASE
WHEN bm.bill_print = 'Y' THEN 1
ELSE 0
END) pdf_cnt,
Sum(CASE
WHEN Isnull(bm.bill_handling_code, '0') = '0' THEN 1
ELSE 0
END) reg_cnt,
Sum(CASE
WHEN Isnull(bm.bill_handling_code, '0') = '1' THEN 1
ELSE 0
END) ftime_cnt,
Sum(CASE
WHEN Isnull(bm.bill_handling_code, '0') = '9999' THEN 1
ELSE 0
END) ltime_cnt,
Count(*) bill_cnt,
Sum(CASE
WHEN bill_status = '01' THEN 1
ELSE 0
END) canc_cnt,
Sum(CASE
WHEN bill_status = '01' THEN
CASE
WHEN rr.usage_qty IS NULL THEN 0
ELSE Cast (rr.usage_qty AS NUMERIC(18, 2))
END
ELSE 0
END) canc_usg,
Sum(CASE
WHEN vis.kh_qty IS NULL THEN 0
ELSE Cast(vis.kh_qty AS NUMERIC(18, 2))
END) kh_qty
FROM bill_master bm WITH (nolock)
INNER JOIN (SELECT bill_no,
Sum(CASE
WHEN vpb.recurr_charge_type IN ( 'T4',
'SLF' )
THEN
CASE
WHEN vpb.print_qty = 'Y'
AND vpb.usage_qty IS NOT NULL
THEN
Cast (vpb.usage_qty AS
NUMERIC(18, 2))
ELSE 0
END
ELSE 0
END) usage_qty
FROM v_print_bills_all vpb
GROUP BY bill_no) rr
ON rr.bill_no = bm.bill_no
LEFT OUTER JOIN vis_bill_master_cr vis WITH (nolock)
ON bm.bill_no = vis.bill_no
WHERE 1 = 1
AND dbo.Trunc(bm.posted_date) >= '20150101'
AND dbo.Trunc(bm.posted_date) <= '20151124'
AND bm.posted_date IS NOT NULL
AND bm.cust_id NOT IN (SELECT cc.code_type cust_id
FROM code_table cc WITH (nolock)
WHERE cc.code_tabname = 'RptExclCust'
AND cc.code_value = 'cust_id')
GROUP BY dbo.Sigmadf(bm.posted_date, 'YYYY-MM') WITH rollup)t
I must say that the explanation is not so clear.
From my understanding, you want the total of two columns.
So, wrap all your query between parenthesis, call it subQuery, and make the sum of the two columns on top:
SELECT subQuery.total_month as bill_date,
subQuery.curr_amount as amount,
subQuery.tax_amount tax,
subQuery.curr_amount + subQuery.tax_amount as [total],
...
FROM
(..your entire query here..) as subQuery

SQL percentage with rows same table with different where condition

I want to do a query like:
select
count(asterisk) where acción='a'/count(asterisk) where acción='b' * 100
from
same_table
grouped by day
but I don't want use subquery, is it possible with joins?
I`m not sure the syntax is correct, but you can use something like this:
SELECT day,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A,
SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) AS SUM_B,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A / SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) * 100 AS result
FROM your_table
GROUP BY day
The concept is to actually sum the the values that you need, instead of count.

SQLITE How to Divide two count results in the same query

My current code:
SELECT VENDOR.[VENDOR_NAME], DEVICE.[DEVICE_NAME], DEVICE.[PK_DEVICE],MODELDEVICE.[FK_MODELDEVICE_DEVICE],
COUNT(RESULT.[FK_RESULT_COMMAND]) AS TOTAL_TESTS,
COUNT(case when TYPERESULT.[TYPERESULT_NAME]='ERROR' then 1 else null end) as ERROR,
COUNT(case when TYPERESULT.[TYPERESULT_NAME]='OK' then 1 else null end) as OK,
COUNT(case when TYPERESULT.[TYPERESULT_NAME]='SKIP' then 1 else null end) as SKIP,
COUNT(DISTINCT PK_COMMAND) AS COMMAND_COUNT,
COUNT(DISTINCT RESULT_ORDER) AS RESULT_COUNT
The question is that I need another column with the result of dividing total ERROR results in TOTAL_TESTS results, and I don´t know how to do that
I have a preference for using SUM() in this case, rather than COUNT(). I think you will see why, because the average is easy to calculate as well:
COUNT(*) AS TOTAL_TESTS,
SUM(case when TYPERESULT.[TYPERESULT_NAME] = 'ERROR' then 1 else 0 end) as ERROR,
SUM(case when TYPERESULT.[TYPERESULT_NAME] = 'OK' then 1 else 0 end) as OK,
AVG(case when TYPERESULT.[TYPERESULT_NAME] = 'ERROR' then 1.0 else 0 end) as ERROR,
. . .
Note the use of 1.0. This is because SQLite does integer division, so we need to pass in a non-integer value.
Just divide the 2 columns.
SELECT VENDOR.[VENDOR_NAME], DEVICE.[DEVICE_NAME], DEVICE.[PK_DEVICE],MODELDEVICE.[FK_MODELDEVICE_DEVICE],
COUNT(RESULT.[FK_RESULT_COMMAND]) AS TOTAL_TESTS,
COUNT(CASE WHEN TYPERESULT.[TYPERESULT_NAME] = 'ERROR' THEN 1 ELSE NULL END) AS ERROR,
COUNT(CASE WHEN TYPERESULT.[TYPERESULT_NAME] = 'OK' THEN 1 ELSE NULL END) AS OK,
COUNT(CASE WHEN TYPERESULT.[TYPERESULT_NAME] = 'SKIP' THEN 1 ELSE NULL END) AS SKIP,
COUNT(DISTINCT PK_COMMAND) AS COMMAND_COUNT,
COUNT(DISTINCT RESULT_ORDER) AS RESULT_COUNT,
(COUNT(CASE WHEN TYPERESULT.[TYPERESULT_NAME] = 'ERROR' THEN 1.0 ELSE NULL END))/(COUNT(RESULT.[FK_RESULT_COMMAND])) AS DivColumn

Avoiding a divide by zero error in a case statement

I am getting a divide by zero error in my script.
Can anyone please help.
I am trying to divide two records and one of them has zero in it. I dont want to lose the row, please advise.
select DATEPART(Year,Request_date) as "Year",
DATEPART(Month,Request_date) as "Month",
COUNT([MONTH_OF_SUSPENSION]) as "Request" ,
sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end) as "Paid in 24hrs",
COUNT([MONTH_OF_SUSPENSION])/sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end) as "Achieved"
FROM suspension_br
where REQUEST_STATUS = 'OTHERS'
GROUP BY DATEPART(Year,Request_date),DATEPART(Month,Request_date)
You can introduce a second case to check the result of the sum:
case
when sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end) > 0
then COUNT([MONTH_OF_SUSPENSION])/sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end)
else 0 /* a default value that makes sense to you */
end as "Achieved"
Looking at your code I could assume you are using MSSQL and therefore you could use nullif which returns null if two arguments are equal. So for example your code could look like :
COUNT([MONTH_OF_SUSPENSION])/nullif(sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end),0) as "Achieved"
What it does is if the value of the sum operator is equal 0 then the divisor is turn from zero into null and that will result in the entire equation to become null.
use another case statement to check the result of your sum
select DATEPART(Year,Request_date) as "Year",
DATEPART(Month,Request_date) as "Month",
COUNT([MONTH_OF_SUSPENSION]) as "Request" ,
sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) as "Paid in 24hrs",
case
when sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) = 0 then 'whatever you want in this case'
else COUNT([MONTH_OF_SUSPENSION])/sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) as "Achieved"
FROM suspension_br
where REQUEST_STATUS = 'OTHERS'
GROUP BY DATEPART(Year,Request_date),DATEPART(Month,Request_date)
although this is pretty nasty looking, so you could tidy it up a bit with a sub-select:
select
year,
month,
request,
PaidIn24hrs,
case
when PaidIn24hrs = 0 then 'whatever you want in this case'
else request/PaidIn24hrs
end as "Achieved"
from
(
select DATEPART(Year,Request_date) as "Year",
DATEPART(Month,Request_date) as "Month",
COUNT([MONTH_OF_SUSPENSION]) as "Request" ,
sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) as "PaidIn24hrs"
FROM suspension_br
where REQUEST_STATUS = 'OTHERS'
GROUP BY DATEPART(Year,Request_date),DATEPART(Month,Request_date)
)