I am trying to run a query to display results between 2 dates, and then display the results from those same dates but a year prior. This is what I have-
where (a.Invdate between '11/1/2015' and '11/30/2015')
will eventually use parameters so it would look like
where (a.Invdate between #StartDate and #EndDate)
But I then want to be able to run the same query with the same date range but 11/1/2014 and 11/30/2014 instead.
How can I go about achieving this?
DATEADD is the best way to do this. also you can use the log way, to parse each datepart so:
convert(VARCHAR(2),datepart(mm,'11/30/2015')) + '/' + convert(VARCHAR(2),datepart(dd,'11/30/2015')) + '/' + convert(VARCHAR(4),convert(INTEGER,datepart(yy,'11/30/2015')) - 1) AS newDate
(I vot you + because you are new user) and please be careful next time then post a question
Related
In a SQL Server query, I am currently using the clause
WHERE
DAY(trade_date) = DAY(GETDATE()) - 1
AND MONTH(trade_date) = MONTH(GETDATE())
AND YEAR(trade_date) = YEAR(GETDATE())
to query my data from the previous day.
It is working fine right now but my question is if, for example, on 8/1/2021, SQL Server will try to get data from 8/0/2021 or if it will know to get data from 7/31/2021.
If this query won't work what could I use instead? Thanks!
I would recommend using proper date comparison logic - instead of breaking it down to day, month and year. Also, it is recommended to use proper date arithmetic functions like DATEADD instead of just - 1 on your date values (never sure what that -1 stands for: minus one day? Week? Month? Hour?).
And lastly - I would also recommend using SYSDATETIME() instead of GETDATE() since the latter always returns a DATETIME datatype - which should be on its way out, and you should use DATE (if you don't need to time portion), or DATETIME2(n) (if you do need the time portion) since those are more efficient and have fewer limitations compared to DATETIME.
If your trade_date is a DATE column (as it probably should be), just use:
WHERE
trade_date = DATEADD(DAY, -1, SYSDATETIME())
and if it's not a DATE - just cast it to a date as needed:
WHERE
CAST(trade_date AS DATE) = DATEADD(DAY, -1, CAST(SYSDATETIME() AS DATE))
Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
I have a date in following format in my DB.
10/16 - mm/yy
I need to convert it to:
October/16
Is this possible?
If it's not possible then please tell me why.
This is not a date, it's missing the day, it's a bad way to store year/month. There should be a 4 digit year to avoid confusion and the year should be listed first to enable correct sorting, e.g. '2016/10' or a numeric value 201610.
You can cast it to a DATE first and then use a FORMAT to disply only month/year:
set dateformat myd;
select format(cast(mystupidcolumn + '/1' as date), 'MMMM/yy')
Or SUBSTR the month part and use a CASE.
try this format,
SELECT DATENAME(month, DATEADD(month, #mydate-1, CAST('2008-01-01' AS datetime)))
You can display date by using this code
select datename(month, YourColumnName) + '/' + right(YEAR(YourColumnName),2)
FROM yourTableName
Simply change yourColumnName with name of your table column and yourTableName with name of table.
Yes you can, and it depend in what database you use to call date functions
If you column Datetime format
SQL server DATENAME(Month, GETDATE())
MySQL database MONTHNAME(now())
otherwise
convert it will in your choice at database or you code logic
split the value and lookup at month enum or fake the date to be accepted and complete date format like 01/10/16
so do something like SELECT DATENAME(Month, datecolumn) + '/' + YEAR (datecolumn)
also you can use instead of Year function DATEPART(yy,datecolumn)
the way you do it with format will look like
CONVERT(VARCHAR(11),GETDATE(),106)
but excepted to get first 3 char of month JUN
I have a script that I am using to populate a time dimension table and I would like to have a column for the time in 12 hour format.
I know this can be done by doing something along the lines of
SELECT CONVERT(varchar(15),[FullTime],100)
Where [FullTime] is a column containing a TIME field in HH:MM:SS format.
But this gives the following result 2:30pm and I would like 2:30:47PM, note the inclusion of seconds.
I know I could build this up using substrings etc. but I wondered if there was a prettier way of doing it.
Thanks
SELECT GETDATE() 'Today',
CONVERT(VARCHAR(8), [FullTime], 108) 'hh:mi:ss'
Taken from here
This will give you a column 'today' followed by the time value you seek 'hh:mi:ss'
If having also milliseconds is not a problem for you, you can use
SELECT CONVERT(VARCHAR, [FullTime], 109)
Declare #tstTime datetime
set #tstTime = GetDate()
Select
#tstTime
,CONCAT(SUBSTRING(CONVERT(varchar(26), #tstTime, 109),1,20),RIGHT(CONVERT(varchar(26), #tstTime, 109),2))
I am writing a query in which I have to get the data for only the last year. What is the best way to do this?
SELECT ... FROM ... WHERE date > '8/27/2007 12:00:00 AM'
The following adds -1 years to the current date:
SELECT ... From ... WHERE date > DATEADD(year,-1,GETDATE())
I found this page while looking for a solution that would help me select results from a prior calendar year. Most of the results shown above seems return items from the past 365 days, which didn't work for me.
At the same time, it did give me enough direction to solve my needs in the following code - which I'm posting here for any others who have the same need as mine and who may come across this page in searching for a solution.
SELECT .... FROM .... WHERE year(*your date column*) = year(DATEADD(year,-1,getdate()))
Thanks to those above whose solutions helped me arrive at what I needed.
Well, I think something is missing here. User wants to get data from the last year and not from the last 365 days. There is a huge diference. In my opinion, data from the last year is every data from 2007 (if I am in 2008 now). So the right answer would be:
SELECT ... FROM ... WHERE YEAR(DATE) = YEAR(GETDATE()) - 1
Then if you want to restrict this query, you can add some other filter, but always searching in the last year.
SELECT ... FROM ... WHERE YEAR(DATE) = YEAR(GETDATE()) - 1 AND DATE > '05/05/2007'
The most readable, IMO:
SELECT * FROM TABLE WHERE Date >
DATEADD(yy, -1, CONVERT(datetime, CONVERT(varchar, GETDATE(), 101)))
Which:
Gets now's datetime GETDATE() = #8/27/2008 10:23am#
Converts to a string with format 101 CONVERT(varchar, #8/27/2008 10:23am#, 101) = '8/27/2007'
Converts to a datetime CONVERT(datetime, '8/27/2007') = #8/27/2008 12:00AM#
Subtracts 1 year DATEADD(yy, -1, #8/27/2008 12:00AM#) = #8/27/2007 12:00AM#
There's variants with DATEDIFF and DATEADD to get you midnight of today, but they tend to be rather obtuse (though slightly better on performance - not that you'd notice compared to the reads required to fetch the data).
Look up dateadd in BOL
dateadd(yy,-1,getdate())
GETDATE() returns current date and time.
If last year starts in midnight of current day last year (like in original example) you should use something like:
DECLARE #start datetime
SET #start = dbo.getdatewithouttime(DATEADD(year, -1, GETDATE())) -- cut time (hours, minutes, ect.) -- getdatewithouttime() function doesn't exist in MS SQL -- you have to write one
SELECT column1, column2, ..., columnN FROM table WHERE date >= #start
I, like #D.E. White, came here for similar but different reasons than the original question. The original question asks for the last 365 days. #samjudson's answer provides that. #D.E. White's answer returns results for the prior calendar year.
My query is a bit different in that it works for the prior year up to and including the current date:
SELECT .... FROM .... WHERE year(date) > year(DATEADD(year, -2, GETDATE()))
For example, on Feb 17, 2017 this query returns results from 1/1/2016 to 2/17/2017
For some reason none of the results above worked for me.
This selects the last 365 days.
SELECT ... From ... WHERE date BETWEEN CURDATE() - INTERVAL 1 YEAR AND CURDATE()
The other suggestions are good if you have "SQL only".
However I suggest, that - if possible - you calculate the date in your program and insert it as string in the SQL query.
At least for for big tables (i.e. several million rows, maybe combined with joins) that will give you a considerable speed improvement as the optimizer can work with that much better.
argument for DATEADD function :
DATEADD (*datepart* , *number* , *date* )
datepart can be: yy, qq, mm, dy, dd, wk, dw, hh, mi, ss, ms
number is an expression that can be resolved to an int that is added to a datepart of date
date is an expression that can be resolved to a time, date, smalldatetime, datetime, datetime2, or datetimeoffset value.
declare #iMonth int
declare #sYear varchar(4)
declare #sMonth varchar(2)
set #iMonth = 0
while #iMonth > -12
begin
set #sYear = year(DATEADD(month,#iMonth,GETDATE()))
set #sMonth = right('0'+cast(month(DATEADD(month,#iMonth,GETDATE())) as varchar(2)),2)
select #sYear + #sMonth
set #iMonth = #iMonth - 1
end
I had a similar problem but the previous coder only provided the date in mm-yyyy format. My solution is simple but might prove helpful to some (I also wanted to be sure beginning and ending spaces were eliminated):
SELECT ... FROM ....WHERE
CONVERT(datetime,REPLACE(LEFT(LTRIM([MoYr]),2),'-
','')+'/01/'+RIGHT(RTRIM([MoYr]),4)) >= DATEADD(year,-1,GETDATE())
Here's my version.
YEAR(NOW())- 1
Example:
YEAR(c.contractDate) = YEAR(NOW())- 1
For me this worked well
SELECT DATE_ADD(Now(),INTERVAL -2 YEAR);
If you are trying to calculate "rolling" days, you can simplify it by using:
Select ... FROM ... WHERE [DATE] > (GETDATE()-[# of Days])