Lets say I have following tables:
Table1
ID Number
1 2
2 34
3 1 <---- Input (ID = 3) ==> (Number = 1)
4 6
5 5
*6* 7 <---- Want to find (Number = 6) because match in Table2
7 22
and Table2
Number Code Att1 Att2 Att3
1 1 1 <-----|
1 2 1 2 <-----|
6 2 f 2 |
6 3 4 3 2 |
2 4 6 |---Match
22 5 2 2 2 |
5 2 h 3 b |
7 1 1 <-----|
7 2 1 2 <-----|
7 h 5 r
So here is my Problem:
I want the IDs from Table1 that have all Code and Attributes from Table2 that a given (variable) input ID has. At the end I want to create a stored procedure/function that gives me all IDs meeting that condition.
As an Example:
Input-ID: 3. Would return ID 6 because Number 7 (mapped from ID 6 in Table1) has the rows Number 1 (mapped from ID 3 in Table1) has. It has more but that doesn't matter, its just important it has all rows the input one has.
(I can't find a solution to comparing a set of rows to another set of rows that is not known before.)
Thanks for any help!
Edit:
To make it more understandible, here what I want in words step-by-step.
Map input ID to Number in Table1
Get All Rows from Table2 having Number from Step 1
Get all Number that have the same (can have more) Rows as from Step 2
Get IDs for that Numbers (and return them)
Try something like this. Haven't tested it, but basically you inner join on all of the attributes that need to match. The HAVING clause is a crude check to make sure that it matched all the rows. Edit: Forgot to add the input ID WHERE clause.
SELECT t1b.ID FROM
Table1 t1a
INNER JOIN Table2 t2a ON t1a.Number = t2a.Number
INNER JOIN Table2 t2b ON t2a.Number <> t2b.Number AND t2a.Code = t2b.CODE AND t2a.Att1 = t2b.Att1 AND t2a.Att2 = t2b.Att2 AND t2a.Att3 = t2b.Att3
INNER JOIN Table1 t1b ON t1b.Number = t2b.Number
WHERE t1a.ID = 3
GROUP BY t1b.ID
HAVING COUNT(*) = (SELECT COUNT(*) FROM Table1 WHERE ID = t1a.ID)
select t11.ID as Id_To_Find,t12.ID as Id_Found
from Table1 t11
join (
select t21.Number as Found,t22.Number as ToFind from Table2 t21
left join Table2 t22 on t21.Code = t22.Code
and t21.Att1 = t22.Att1
and t21.Att2 = t22.Att2
and t21.Att3 = t22.Att3
and t21.Number <> t22.Number
group by t21.Number,t22.Number
having COUNT(*) = (select COUNT(*) from Table2 where Number = t22.Number))
as FindMatches
on t11.Number = FindMatches.ToFind
join Table1 t12 on t12.Number = FindMatches.Found
Kind of hard to understand what you're trying to acheive. As i understood from your example, you want to match the Number for the input ID in Table1 with any column (correct?) in Table2.
With input ID=3, the SELECT will return Number=7. In the IN (...)-condition, you can specify whichever columns in Table2 you want to match to Table1.Number.
DECLARE #Input INT = 3 -- Your input
SELECT DISTINCT t1.Number
FROM Table1 t
INNER JOIN Table2 t2 ON t.Number IN (t2.Number, t2.Code, t2.Att1, t2.Att2, t2.Att3)
INNER JOIN Table1 t1 ON t2.Number = t1.Number AND t.ID <> t1.ID
WHERE t.ID = #Input
Related
I have the following tables:
T1 T2 Desired result
CA CB CA CC CA CB
1 2 1 3 1 4
1 4 1 2 2 1
1 3 1 5 2 3
2 1 2 4
2 3
3 6
3 1
4 ...
I need to make a join between T1 and T2 (using column CA) and return only those rows which the values in CB do not exists in T2.CC
A simple way to achieve that is using the following query:
SELECT T1.* FROM T1 INNER JOIN T2 ON t1.CA = t2.CA AND
t1.CB NOT IN (SELECT CC FROM T2 WHERE T2.CA = T1.CA)
I think the previous query is not very efficient. For that reason I am looking for something better
Any help will be appreciated
Generally, a more efficient means of achieving this sort of result is finding records which fail a simpler join condition. Those can be found by doing an outer join and checking for null, as follows:
select t1.ca, t1.cb
from t1 left outer join t2 on t1.ca=t2.ca and t1.cb=t2.cc
where t2.ca is null;
I think you just want not exists:
select t1.*
from t1
where not exists (select 1
from t2
where t2.ca = t1.ca and t2.cb = t1.cb
);
For performance, you want an index on t2(ca, cb).
I'm not sure how to explain what I need but here's the data first:
Table 1
District
-1
3
2
1
3
Table 2
ID ID_Name
1 Main 1
2 Main 2
3 Main 3
How do I join the tables so that it looks like this?
District
-1
Main 3
Main 2
Main 1
Main 3
I'm assuming the second column is named Name for this, but you can do it with a COALESCE and a LEFT JOIN:
Select Coalesce(T2.Name, Str(T1.District)) As District
From Table1 T1
Left Join Table2 T2 On T1.District = T2.Id
assuming table 2 have
Table 2
ID col2
1 Main 1
2 Main 2
3 Main 3
you could use a left join
select table1.Distric, table2.col2
from table1
left join table2 on table1.dictrict = t2.ID
order by table2 col2
You can use left join:
Select coalesce(t2.col, t1.District) from table1 t1
left join table2 t2 on t1.District = t2.Id
I have three tables which store a simple onet-to-many relationship.
Table1 idT1 Name
1 A
2 B
3 B
Table2 idT2 Value
1 AA
2 BB
3 CC
4 DD
Table3 idT1 idT2
1 4
1 2
2 1
2 4
2 3
3 4
I need to return those rows in Table3 which only have one relationship between Table1 and and some rows from Table2.
Something like this:
If I look for rows that have a relation idT2 = 4, the query should return only this row:
Table3 idT1 idT2
3 4
I figured out this query but I think there must be something easier:
;WITH tb AS(SELECT idT1 FROM Table3 WHERE idT2 IN(4))
SELECT t.idT1 FROM T3 t INNER JOIN tb ON t.idT1 = tb.idT1
GROUP BY idT1 HAVING COUNT(t.idT2) = 1
Any help will be appreciated, what do you think?
One method is to use aggregation and just look for the values that appear once for a given idT2:
select idT1, max(idT2) as idT2
from t3
group by idT1
having min(idT2) = 4 and max(idT2) = 4;
You could also do this using not exists:
select t3.*
from t3
where t3.idT2 = 4 and
not exists (select 1 from t3 tt3 where tt3.idT1 = t3.idT1 and tt3.idT2 <> 4);
I have a question on SQL join which involve multiple condition in second joined table. Below is the table details
Table 1
pId status keyVal
---- ------- ------
100 1 45
101 1 46
Table 2
pId mode modeVal
100 2 5
100 3 6
101 2 7
101 3 8
I have above two tables and I am trying to join based on below condition to get pId's
pId's which has keyVal = 45 and status = 1 joined with table2 which has mode = 2 and modeVal 5 and mode =3 and modeVal = 6
the result I am expecting is to return pid = 100
Can you please help me with a join query ?
One way is to use GROUP BY with HAVING to count that the number of rows found is 2, of which 2 are matching the condition;
WITH cte AS (SELECT DISTINCT * FROM Table2)
SELECT t1."pId"
FROM Table1 t1 JOIN cte t2 ON t1."pId" = t2."pId"
WHERE t1."status" = 1 AND t1."keyVal" = 45
GROUP BY t1."pId"
HAVING SUM(
CASE WHEN t2."mode"=2 AND t2."modeVal"=5 OR t2."mode"=3 AND t2."modeVal"=6
THEN 1 END) = 2 AND COUNT(*)=2
If the values in t2 are already distinct, you can just remove the cte and select directly from Table2.
An SQLfiddle to test with.
SELECT columns
FROM table1 a, table2 B
WHERE a.pid = B.pid
AND a.keyval = 45
AND a.status = 1
AND (
(B.mode = 2 AND B.modeval = 5)
OR
(B.mode = 3 AND B.modeval = 6)
)
Below query should work for you perfectly
select distinct table1.pid FROM table1 JOIN table2
on table1.pid = table2.pid
WHERE table2.modeValue IN (5,6) AND table2.mode IN (2,3) AND table1.keyVal=45 and table1.status=1;
I have two tables. I need to take away from the first table second table. Stim to another table without all the rows of the first table.
Table1
Table2
Result = Table1(value1) – Table2(value1) -----groupe no. 2 or no.1
Result (groupe no. 2)
Result
id value1 groupe
_______________________
1 10 2
2 9 2
3 10 2
5 5 2
6 11 2
7 12 2
I need the result of which I can write the group number and get result for that group.
Try this query:
Select
t1.id,
t1.value1-t2.value1 as value,
t1.groupe from
table1 t1,table2 t2
where t1.id=t2.id and t1.groupe=2;
try this:
SELECT
T1.id, T2.group, T1.valor - T2.valor AS value
FROM
Table1 T1 INNER JOIN
Table2 T2 ON T1.id = T2.id AND T1.group = T2.group
WHERE (T1.group = 2)