I am using vb.net for making a game. I have a ball (not actually, but supposedly) in the center of the screen. It moves towards another object, which has a circular surface and is supposed to reflect back in correct direction and angle.
Many games are based on the bouncing back of an object (most of them are based on advanced languages). But, I am not really able to make out how.
So, I tried to look at some things, like getting an angle from where it started by calculating the pixels from the initial point and sending it that many pixels in the opposite direction. A code which I tried for this is:
Dim x1, y1 as integer
x1 = object.left
y1 = object.top
This stores the object's co-ordinates at the starting, when it is in the center of the screen. While the following code tries to achieve what actually is required:
Dim a, b as integer
a = x1-object.left
b = x2-object.top
I have got the number of pixels it has moved, but I have no clue how to reflect back in the same angle using this, and whether this technique will even work or not.
So, basically what I want is:
Now, two situations arise:
How to reflect object from a plain surface?
How to reflect it from circular surface?
Bouncing a ball off of another ball works exactly as bouncing it off a flat surface. As the balls only touch at one point, there is no difference to the moving ball if that point is part of a curved or a flat surface.
The ball acts just as if it was bouncing off of a flat plane, which is the tangent of the reflecting objects curve at that point (and also the tangent of the moving objects curve):
The reflection movement is the angle mirrored around a line that is perpendicular to the plane, and goes through the center of the ball. (When the reflecting object is a ball, the line goes through the center of that too, which may help when you want to calculate it.)
Related
I am attempting to come up with a quick and efficient means of translating a 3d mesh into a projected AABB. In the end, I would like to accomplish something similar to figure 1 wherein only the area of the screen covered by the cube is located inside the bounding box highlighted in red. ((if it is at all possible, getting the area as small as possible, highlighted in blue, would increase efficiency down the road.))
Figure 1. https://i.imgur.com/pd0E20C.png
Currently, I have tried:
Calculating the point position on the screen using camera.unproject_position(). this failed largely due to my inability to wrap my head around the pixel positions trending towards infinity. I understand it has something to do with Tan, but frankly, it is too late for my brain to function anymore.
Getting the area of collision between the view frustum and the AABB of the mesh instance. This method seems convoluted, and to get it in a usable format I would need to project the result into 2d coordinates again.
Using the MeshInstance VisualInstance to create a texture wherein a pixel is white if it contains the mesh instance, and black otherwise. Visual instances in general just baffle me, and I did not think it would be efficient to have another viewport just to output this texture.
What I am looking for:
An output that can be passed to a shader informing where to complete certain calculations. Right now this is set up to use a bounding box, but it could easily be rewritten to also use a texture. It also could be rewritten to use polygons, but I am trying to keep calculations to a minimum in the shader.
Certain solutions I have tried before have worked, slightly, but this must be robust. The camera interfacing with the 3d object will be able to move completely around and through it, meaning at times the view will be completely surrounded by the 3d model with points both in front, and behind.
Thank you for any help you can provide.
I will try my best to update this post with information if needed.
First off, I am not sure if this is the right place so I apologize if this belongs elsewhere - please let me know if it does. I am currently doing some prototyping with this in VB so that's why I come here first.
My Goal
I am trying to make a program to be able to log different types of information for a video game that I play. I would like to be able to map out the entire game with my program and add locations for mobs, resources, etc.
What I have
The in game map can be downloaded so I have literally just stuck this in as a background image on the form (just for now). The map that I get downloaded though is not exactly as the map appears in the game though since the game will add extra water around everything when scrolling around. This makes it a bit tricky to match up where the origin for the map is in game compared to where it would be on the downloaded map.
The nice thing though is that while I am in the game I can print my current coordinates to the screen. So I thought that maybe I can somehow use this to get the right calculation for the rest of the points on the map.
Here is an example image I will refer to now:
In the above map you will see a dotted bounding box. This is an invisible box in the game where once you move your mouse out of the longitude and latitude points will no longer show. This is what I refer to above when I mean I can't find the exact point of origin for the in game map.
You will also see 2 points: A and B. In the game there are teleporters. This is what I would use to get the most accurate position possible. I am thinking I can find the position (in game) of point A and point B and then somehow calculate that into a conversion for my mouse drag event in VB.
In VB the screen starts at top-left and is 0,0. I did already try to get the 2 points like this and just add or subtract the number to the x and y pixel position of the mouse, but it didn't quite line up right.
So with all this information does anyone know if it is possible to write a lon/lat conversion to pixels based on this kind of data?
I appreciate any thoughts and suggestions and if you need any clarification of any information I have posted please let me know and I will be happy to expand on it. I am really hoping I can get this solved!
Thanks!
EDIT:
I also want to mention I am not sure if there is an exact pixel to lat/lon point for the in game map. I.e. the in game map could be 1 pixel = 100 latitude or something. So I might also need to figure out what that conversion number is?
Some clarifications about conversion between the pixel location to 'latitude and longitude'.
First the map in your game is in a geometry coordinate system, which means everything lies in 2D and you can measure the distance between two points by calculate the pixel position.
But when we talk about longitude and latitude, we are actually talking about a geography coordinate system, which is a '3D' model of the sphere oabout the surface of the earth. All the maps on earth are abstracted from 3D to 2D through one step called projection. Like google maps or your GPS. In this projection process, the 3D model converted to 2D model but there is always some part of the map will be tortured, so that same distance in pixels on a map could be different in length in reality.
So if you don't care about the accuracy then you can consider the geometry point as geography point. Otherwise, you need to implement some GIS library to handle the geodesic distance and calculate the geography point based on the projection coordinate system.
Hi stackoverflow community,
This is a continuation of a question I asked 6 months regarding calculating the area and position of dynamically formed rectangles. The solution provided for that worked a treat but now I want to take this a step further.
Some background - I'm working on a puzzle game using Cocos2D/Box2D were the player draws lines on the screen. Depending on were the player draws, I want to then work out the area and position of polygons that appear as a result of the drawn lines.
In the following image, the black border represents a playing area, this will always be the same shape. The grey lines are player drawn and will always be straight. The green square is an obstacle. The obstacle objects will be convex shapes. The formed polygons (3 in this case) are the blue areas and are the shapes I'm trying to get the coordinates and area for.
I think I'll be fine with working out the area of a polygon using determinants but before that, I need to work out the coordinates of the blue polygons and I'm not sure how to do this.
I've got the lines (x,y) coordinates for both ends, the coordinates for the obstacle and the corner coordinates for the black border. Using those, is it possible to work out the coordinates of the blue polygons or am I approaching this the wrong way?
UPDATE - response to duffymo
Thanks for your answer. To explain further, each object mentioned is defined and encapsulated in a class i.e. I've got a Line/Obstacle/PlayingArea object. My polygon object is encapsulated in a 'Rectangle' object. Each one of these objects has it's own properties associated with it such as its coordinates/area/ID/state etc...
In order to keep track of all the objects, I've got an over-seeing singleton object which holds all of the Line objects / Obstacle objects etc in their own respective array. This way, I can loop through say all Lines and know were each one has been drawn by the player.
The game is a bit like classic JezzBall so I need to be able to create these polygon shapes when a user draws a line because the polygon shape will be used as my way of detecting if that particular area contains a ball. If not the area needs to be filled.
Since you already have the nodes and edges for your polygons, I'd recommend that you calculate the centroids, perimeters, and areas using contour integration You can express the centroids and areas as contour integrals using Green's theorem.
You can use Gaussian quadrature to do piecewise integration along each edge.
It'll be fast and accurate; it'll work on polygons of arbitrary complexity.
UPDATE: Objective-C is an object-oriented language. I don't know it myself, but I believe it's based on ideas from C and C++. Since that's the case, I'd recommend that you start writing more in terms of objects. Arrays of coordinates? They need to encapsulated together. I'd suggest a Point abstraction that encapsulates a point (id, x, y) together. Make a Grid that has a List of Points.
It sounds like users supply the relationship between Points to form Polygons. That's not clear from your description, so it's not a surprise that you're having trouble implementing it.
Let's say I have a rectangle-shaped object. I want to move it along a path. Is it possible to position this object according to not only one point, but two points on it? For example, the point A on the object is at 125,220, in this case I want point B to be at 140,235.This way I want to set the direction of the object.
In Objective-c (and I assume in other languages too) when we say "Position of a graphical object" we think of only one point, which is usually the bottom-left corner. But positioning
an object according to only that point will just redraw the object with the lower left corner in another point, and the rest part will be determined according to the height and the width of the object, which does not do what I want.
EDIT:
As you can see (and probably it's what you naturally expect) the object will move as a box from one point to another, because there's only one point determining it's position. You ask why I need a different thing. Because I have a timer and a curved path. Each time the timer ticks I need my object to be at a different location(the next position in an array of dumped points). So, instead of adding to X and Y coordinates, I explicitly tell the object to be at certain place. This way I want to achieve normal movement of my object along the curved path. When the front part of the object moves to some point, I need the rear part to move to a certain point as well.
I finally found a way to do do it. I have to rotate the object according the prior and the next points. So, assume there are points A,B,C,D,E,F,G,H on the path that the object will travel along. If the car is at point D, to calculate the rotation angle I do the following:
myObject.rotation=-atan((D.y-C.y)/(D.x-C.x))/3.141592*180;
As you can see it's just maths. A fine tuning can be applied to get a better, smoother rotation. Here for instance I subtract the Y of the previous position from the Y of the current position, then I do the same thing for X and then I get the minus arctangance of their ratio. But you can do
-atan((E.y-C.y)/(E.x-C.x))/3.141592*180;
Choosing the right positions to subtract their x and y coordinates will result in the right and smooth rotation.
I think you can guess that 3.141592 is M_PI;
I'm trying to make a little archer game, and the problem I'm having has to do with 2 pixels in particular, I'll call them _arm and _arrow. When a real archer is pulling back an arrow, he doesn't immediately pull the arrow back as far as his strength allows him, the arrow takes a little bit of time to be pulled back.
The _arm's angle is equal to the vector from a point to where the user touched on the screen. The rotation is perfect, so the _arm is good. The _arrow needs to be on the same line as _arrow, they are 1 pixel wide each so it looks as though the _arrow is exactly on top of the _arm.
I tried to decrement from the x/y coordinates based on a variable that changes with time, and I set the _arrow's location equal to the _arm's location, and tried to make it look like the _arrow was being pulled back. however, if you rotated, the x/y would mess up because it is not proportional on the x and y axis, so basically _arrow will either be slightly above the arm or slightly below it depending on the angle of the vector, based on touch.
How could I used the x/y position of _arm and the vector of touch to make the arrow appear as though it was being pulled back by a small amount, yet keep the arrow on top of the _arm sprite so that it's position would be similar to the arm, but slightly off yet still on top of the _arm pixel at all times. If you need anymore info, just leave a comment.
I'm not sure I've fully understood, but I'll have a go at answering anyway:
To make the arrow move and rotate to the same place as the consider adding the arrow as a child of the arm. You can still render it behind if you like by making its z is less than one: [arm addChild:arrow z:-1]
To then make the arrow move away from the arm as the bow is drawn, you then just set the position of the arrow with respect to the arm.
The problem I do see with this solution however is that this grouping of the sprites may be a little unusual after the arrow leaves the bow. Here you probably don't want the arrow to be a child of the arm as the coordinate systems are no longer related.
Even though they're sure what I "suggested would have solved [the] problem" here is the
Poster's solution
I had to get the x and y coords of the arm based of angle, then I got the sin/cos of a number that was based of the same angle as the arm and subtraced from that.