I have two tables:
METHOD_TYPES
---- ----------------
ID Methods_Type
---- ----------------
1 public
2 ALL_Methods
3 private1235678
4 social
METHOD_TABLE
-------- ----------------- ----------
Ser_ID Ser_Method_Type Emp_Name
-------- ----------------- ----------
1 (null) AAAA
2 (null) BBBB
3 All_Methods Rama
4 social Raja
5 private12345678 Rakesh
I used the below query for the ORDER BY:
SELECT SUBSTR(Methods_Type, 1, 10) AS disMisType
FROM METHOD_TABLE MET
LEFT JOIN METHOD_TYPES TRMT
ON MET.Ser_Method_Type = TRMT.Methods_Type
ORDER BY (NLSSORT(MET.Ser_Method_Type, 'NLS_SORT=binary_ai')) DESC NULLS FIRST;
OUTPUT:
(null)
All_Methods
(null)
social
private12345678
But I need to order all the nulls first.
Kindly provide the exact query.
Using the data you provided - and adding in the extra columns, I get:
with method_types as (select 1 id, 'public' methods_type from dual union all
select 2 id, 'ALL_Methods' methods_type from dual union all
select 3 id, 'private1235678' methods_type from dual union all
select 4 id, 'social' methods_type from dual),
method_table as (select 1 ser_id, null ser_method_type, 'AAAA' emp_name from dual union all
select 2 ser_id, null ser_method_type, 'BBBB' emp_name from dual union all
select 3 ser_id, 'All_Methods' ser_method_type, 'Rama' emp_name from dual union all
select 4 ser_id, 'social' ser_method_type, 'Raja' emp_name from dual union all
select 5 ser_id, 'private12345678' ser_method_type, 'Rakesh' emp_name from dual)
select substr(trmt.methods_type,1,10) as dismistype,
met.*,
trmt.*
from method_table met
left join method_types trmt on (met.ser_method_type = trmt.methods_type)
order by (nlssort(met.ser_method_type, 'NLS_SORT=binary_ai')) desc nulls first;
DISMISTYPE SER_ID SER_METHOD_TYPE EMP_NAME ID METHODS_TYPE
------------------------------ ---------- --------------- -------- ---------- --------------
1 AAAA
2 BBBB
social 4 social Raja 4 social
5 private12345678 Rakesh
3 All_Methods Rama
which is not what your expected output shows, but it does maybe explain why you see nulls apparently out of order in your results - you're selecting the trmt.methods_type column, but ordering by the met.ser_method_type column. If there aren't any rows in the method_types table matching those in the method_table, then of course you will see nulls, but because there IS a value in the method_table, they may well be displayed after rows that do have a value.
Perhaps all you need to do is to change the column being selected
from substr(trmt.methods_type,1,10)
to substr(met.ser_method_type,1,10)
or change the order clause
from nlssort(met.ser_method_type, 'NLS_SORT=binary_ai')
to nlssort(trmt.methods_type, 'NLS_SORT=binary_ai')
I'm not sure why your query is not working, but you can have a more explicit order by:
ORDER BY (CASE WHEN MET.Ser_Method_Type IS NULL THEN 1 ELSE 2 END),
NLSSORT(MET.Ser_Method_Type, 'NLS_SORT=binary_ai') DESC
You can create a CASE Column only for order:
select SUBSTR(Methods_Type,1,10)AS disMisType,
SUBSTR(CASE WHEN Methods_Type IS NULL THEN '0' ELSE Methods_Type END ,1,10) AS disMisTypeORDER
FROM METHOD_TABLE MET
LEFT JOIN METHOD_TYPES TRMT
ON MET.Ser_Method_Type = TRMT.Methods_Type
ORDER BY disMisTypeORDER
Related
Ive been trying to use the GROUP function and also PIVOT but I cannot wrap my head around how to merge these tables and combine duplicate rows. Currently my SELECT statement returns results with duplicate UserID rows but I want to consolidate them into columns.
How would I join TABLE1 and TABLE2 into a new table which would look something like this:
NEW TABLE:
UserID Username ParentID 1 ParentID 2
--------- -------- -------- ----------
1 Dave 1 2
2 Sally 3 4
TABLE1:
UserID Username ParentID
--------- -------- --------
1 Dave 1
1 Dave 2
2 Sally 3
2 Sally 4
Table 2:
ParentID Username
--------- --------
1 Sarah
2 Joe
3 Tom
4 Mark
O r a c l e
The with clause is here just to generate some sample data and, as such, it is not a part of the answer.
After joining the tables you can use LAST_VALUE analytic function with windowing clause to get the next PARENT_ID of the user. That column (PARENT_ID_2) contains a value only within the first row of a particular USER_ID (ROW_NUMBER analytic function). Afterwords just filter out rows where PARENT_ID_2 is empty...
Sample data:
WITH
tbl_1 AS
(
Select 1 "USER_ID", 'Dave' "USER_NAME", 1 "PARENT_ID" From Dual Union All
Select 1 "USER_ID", 'Dave' "USER_NAME", 2 "PARENT_ID" From Dual Union All
Select 2 "USER_ID", 'Sally' "USER_NAME", 3 "PARENT_ID" From Dual Union All
Select 2 "USER_ID", 'Sally' "USER_NAME", 4 "PARENT_ID" From Dual
),
tbl_2 AS
(
Select 1 "PARENT_ID", 'Sarah' "USER_NAME" From Dual Union All
Select 2 "PARENT_ID", 'Joe' "USER_NAME" From Dual Union All
Select 3 "PARENT_ID", 'Tom' "USER_NAME" From Dual Union All
Select 4 "PARENT_ID", 'Mark' "USER_NAME" From Dual
)
Main SQL:
SELECT
*
FROM (
SELECT
t1.USER_ID "USER_ID",
t1.USER_NAME "USER_NAME",
t1.PARENT_ID "PARENT_ID_1",
CASE
WHEN ROW_NUMBER() OVER(PARTITION BY t1.USER_ID ORDER BY t1.USER_ID) = 1
THEN LAST_VALUE(t1.PARENT_ID) OVER(PARTITION BY t1.USER_ID ORDER BY t1.USER_ID ROWS BETWEEN CURRENT ROW AND 1 FOLLOWING)
END "PARENT_ID_2"
FROM
tbl_1 t1
INNER JOIN
tbl_2 t2 ON(t1.PARENT_ID = t2.PARENT_ID)
)
WHERE PARENT_ID_2 Is Not Null
... and the Result ...
-- USER_ID USER_NAME PARENT_ID_1 PARENT_ID_2
-- ---------- --------- ----------- -----------
-- 1 Dave 1 2
-- 2 Sally 3 4
The windowing clause in this answer
ROWS BETWEEN CURRENT ROW AND 1 FOLLOWING
takes curent and next row and returns the value defined by the analytic function (LAST_VALUE) taking care of grouping (PARTITION BY) and ordering of the rows. Regards...
This is mySql ver 5.6. Create a concatenated ParentID using group concat then separate the concatenated ParentID (1,2) and (3,4) into ParentID 1 and Parent ID 2.
SELECT t1.UserID,
t1.Username,
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(t1.ParentID), ',', 1), ',', -1) AS `ParentID 1`,
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(t1.ParentID), ',', 2), ',', -1) as `ParentID 2`
FROM TABLE1 t1
INNER JOIN TABLE2 t2 on t1.ParentID = t2.ParentID
GROUP BY t1.UserID
ORDER BY t1.UserID;
Result:
UserID Username ParentID 1 ParentID 2
1 Dave 1 2
2 Sally 3 4
Hoping someone can help.
I have data as follows in two seperate columns in a table called StudentRace
Student_ID RaceCD
---------- ------
123456 1
123456 2
589645 4
987654 3
987654 4
I am looking for a way to combine the data for the students by student id to output into 00000 format. example: Student_ID 123456 RACE: 12000; Student_ID 589645 Race: 00040; Student_ID 987654 Race = 00340. I need to have it be a sub query as it is part of a large report that pulls 50+ fields. If anyone is able to help I would greatly appreciate it. I am using Toads Data Point for Oracle to create my query.
The result can be achieved with a single group by without any joins.
Setup
CREATE TABLE studentrace
(
Student_ID,
RaceCD
)
AS
SELECT 123456, 1 FROM DUAL
UNION ALL
SELECT 123456, 2 FROM DUAL
UNION ALL
SELECT 589645, 4 FROM DUAL
UNION ALL
SELECT 987654, 3 FROM DUAL
UNION ALL
SELECT 987654, 4 FROM DUAL;
Query
SELECT student_id, LPAD (SUM (racecd * POWER (10, 5 - racecd)), 5, '0') AS race
FROM studentrace
GROUP BY student_id;
Result
STUDENT_ID RACE
_____________ ________
589645 00040
987654 00340
123456 12000
You can use a partitioned outer join:
SELECT t.Student_id,
LISTAGG( COALESCE( t.raceCD, 0 ) ) WITHIN GROUP ( ORDER BY r.race )
AS RaceCDs
FROM ( SELECT LEVEL AS race
FROM DUAL
CONNECT BY LEVEL <= 5 ) r
LEFT OUTER JOIN table_name t
PARTITION BY ( t.Student_ID )
ON ( r.race = t.RaceCD )
GROUP BY t.student_id
Which, for your test data:
CREATE TABLE table_name ( Student_ID, RaceCD ) AS
SELECT 123456, 1 FROM DUAL UNION ALL
SELECT 123456, 2 FROM DUAL UNION ALL
SELECT 589645, 4 FROM DUAL UNION ALL
SELECT 987654, 3 FROM DUAL UNION ALL
SELECT 987654, 4 FROM DUAL
Outputs:
STUDENT_ID | RACECDS
---------: | :------
123456 | 12000
589645 | 00040
987654 | 00340
db<>fiddle here
ID Name dep_id
1 A 1
2 B 2
3 A 1
4 A 2
5 B 2
6 A 2
I think you want to have such a SQL
with tab( ID, Name, dep_id) as
(
select 1,'A',1 union all
select 2,'B',2 union all
select 3,'A',1 union all
select 4,'A',2 union all
select 5,'B',2 union all
select 6,'A',2
)
select name,
count(dep_id) as dept_count
from tab t
group by name
having count(name)>1;
NAME DEPT_COUNT
---- ----------
A 4
B 2
Due to you last edit( which you wanted to add to this answer ), consider grouping also by dept_id :
with tab( ID, Name, dep_id) as
(
select 1,'A',1 union all
select 2,'B',2 union all
select 3,'A',1 union all
select 4,'A',2 union all
select 5,'B',2 union all
select 6,'A',2
)
select name, dept_id,
count(dept_id) as dept_count
from tab t
group by name, dept_id
having count(name)>1;
NAME DEPT_ID DEPT_COUNT
---- ------ ----------
A 2 2
A 1 2
B 2 2
How can I fetch this table as expected in Oracle. I'm try to do this like below select but its not give me the right result. What I expect is fetch only the unique ones and exclude if these is a record like different values. Sorry for if asked before but I couldn't find it.
SELECT *
FROM ...
WHERE number IN ( SELECT name
FROM (SELECT *
FROM table
WHERE number IN ('Mel','Jose','Kim')
) ds
GROUP BY number
HAVING COUNT (*) = 1)
Current result:
number name
aaa Mel
asd Jose
fsa Jose
xdf Jose
zzz Kim
zzz Kim
Expected result:
aaa Mel
zzz Kim
You're close - I think you were just missing the distinct in the count in your having clause.
E.g.:
WITH your_table AS (SELECT 100 nmbr, 'Mel' NAME FROM dual UNION ALL
SELECT 112 nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 212 nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 313 nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 101 nmbr, 'Kim' NAME FROM dual UNION ALL
SELECT 101 nmbr, 'Kim' NAME FROM dual)
-- end of mimicking data in your table
-- you already have this table, so you would just need the below sql:
SELECT min(nmbr) nmbr,
NAME
FROM your_table
GROUP BY NAME
HAVING COUNT(DISTINCT nmbr) = 1;
NMBR NAME
---------- ----
101 Kim
100 Mel
Just to prove that it doesn't matter whether the nmbr column is of NUMBER or VARCHAR2 datatype:
WITH your_table AS (SELECT 'aaa' nmbr, 'Mel' NAME FROM dual UNION ALL
SELECT 'asd' nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 'fsa' nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 'xfd' nmbr, 'Jose' NAME FROM dual UNION ALL
SELECT 'zzz' nmbr, 'Kim' NAME FROM dual UNION ALL
SELECT 'zzz' nmbr, 'Kim' NAME FROM dual)
-- end of mimicking data in your table
-- you already have this table, so you would just need the below sql:
SELECT min(nmbr) nmbr,
NAME
FROM your_table
GROUP BY NAME
HAVING COUNT(DISTINCT nmbr) = 1;
NMBR NAME
---- ----
zzz Kim
aaa Mel
You can do by nested sql with the inner part eliminate repeating ones with respect to id & name, and in the outer part eliminate repeating ones with only name like in the following statement :
SELECT MAX(id),name
FROM (SELECT id,name FROM mytable GROUP BY id, name)
GROUP BY name
HAVING COUNT(1) = 1
ORDER BY MAX(id);
OUTPUT:
ID NAME
----- ------
100 Mel
101 Kim
D e m o 1
exactly the same sql works for your second case :
D e m o 2
Say I have a table like the following (I'm on Oracle 10g btw)
NAME VALUE
------ ------
BOB 1
BOB 2
BOB 4
SUZY 1
SUZY 2
SUZY 3
How can I select all rows where value is closest to, but not greater than, a given number. For example if I want to find all the rows where value is closest to 3 I would get:
NAME VALUE
------ ------
BOB 2
SUZY 3
This seems like it should be simple... but I'm having no luck.
Thanks!
SELECT name, max(value)
FROM tbl
WHERE value <= 3
GROUP BY name
This works (SQLFiddle demo):
SELECT name, max(value)
FROM mytable
WHERE value <= 3
GROUP BY name
Based on hagensofts answer:
SELECT name, max(value)
FROM tbl
WHERE value <= 3 AND ROWNUM <=2
GROUP BY name
With ROWNUM you can limit the output rows, so if you want 2 row, then you can limit the rownum.
WITH v AS (
SELECT 'BOB' NAME, 1 value FROM dual
UNION ALL
SELECT 'BOB', 2 FROM dual
UNION ALL
SELECT 'BOB', 4 FROM dual
UNION ALL
SELECT 'SUZY', 1 FROM dual
UNION ALL
SELECT 'SUZY', 2 FROM dual
UNION ALL
SELECT 'SUZY', 3 FROM dual
)
SELECT *
FROM v
WHERE (name, value) IN (SELECT name, MAX(value)
FROM v
WHERE value <= :num
GROUP BY name)
;