I wanna get rid of isql six digits limitation. How can i overcome this ?
" isql displays only six digits of float or real data after the decimal point, rounding off the remainder."
If WE get it from sql advantage we can see all digits after comma. But if we start it from batch file we can not see the rest after six digits.
You can see different result from the screenshot below
Click Screenshot
Any suggestion ?
Kind Regards,
Related
I have created a column with
day_endnav double precision
When I insert a number: 58.320856084100 in database its stored as 58.3208560841 .
The 2 zeros at the end are removed.
Is there any way to say to mariadb to keep what is entered as it is. Not to roundof or removed zeros at the end?
The two zeros were not "removed". DOUBLE has 53 significant bits, which is about 16 significant decimal digits. The display of the number probably decided they were irrelevant. What tool displayed them?
Whether you insert 58.320856084100 or 58.32085608410000000000000, you will get the same value stored into DOUBLE.
Trailing zeros (at least after the decimal point) have no mathematical meaning to FLOAT or DOUBLE. If you have some meaning, then I guess you need to store it as a string, or DECIMAL.
DECIMAL(mm, 12) will store and display 58.320856084100 (if mm >= 14). However, DECIMAL is "fixed-point". That is, DECIMAL(20,12) will always have exactly 12 decimal places, no more, no fewer.
Please state your goal; maybe I have not touched on that point yet.
Why is Power BI doing this to my values? (see video below) It is setting them to 1.00 in the visualization even though they are 99.61, 99.74, etc. in the query table. What is happening? I have tried setting the type to percentage, decimal, and fixed decimal and the same thing always happens. Also the values are set to "don't summarize" in the visualization table.
https://www.youtube.com/watch?v=bNHzelJTW7g&feature=youtu.be
See video to understand what I'm talking about.
Here are a couple screenshots from the video:
In your query editor you have the following values:
99.79%, 99.91%, 99.74%, 99.82%, 99.74%, 99.61%
These are in percent format as is clear by the "%" symbol next to your column name.
When you close and load, you put in in a table which is not formatted as a percent and shows only two decimal places. When rounded to two decimal places the value rounds up to 1.00 for all of these. (Note that your total rounds to 5.99 though.)
If you want them formatted as percentages, use the modeling tab to set the format for the column. (The format you set in the query editor doesn't necessarily carry through to your visualizations.)
Click on your visual, then, in Format visual, go to call-out value and change display units to none and change Value decimal places to the amount of decimals you need.
I am using this
Format(Evaluate(strg), "standard")
but it's not exactly what I want.
If there is not decimal needed I don't want to see ".00" tacked onto the end.
If the decimal can go out further than 2 digits I would like to see more accuracy than 2 digits. Not limited to 2.
I like all the commas for 1000's
I am pulling financial data into Matlab from SQL, where it is unfortunately stored as a 'Real' (which is an approximate data-type).
For example, a value got loaded into SQL as "96.194" which is the correct value (this could have any number of decimals 1-5). I know in SQL it is stored as something like 96.19400024 because it is an approximation, but SQL Server somehow knows to display it as 96.194.
When I pull it into matlab, it gets pulled in as 96.194, which is what I want. Unfortunately, it turns out it's not actually 96.194, as demonstrated:
>>price
price =
96.194
>> price==96.194
ans =
0
>> class(price)
ans =
single
>> double(price)
ans =
96.1940002441406
So my question is, is there a way to convert a single to a double exactly as it appears as a single (i.e. truncate all the decimals which are the approximation? Note: I cannot just round it because I don't know how many decimals it's supposed to have.
The vpa function lets you specify a number of significant (nonzero) digits that is different from the current digits setting. For example:
vpa(price, num_of_digits_required)
or in your case:
vpa(double(price),7)
(6 or 8 significant digits will yield the same result)
Edit
To use vpa you'll need the Symbolic Math Toolbox, there are alternatives found on the web, such as this FEX file.
Single precision floating point values have only about 7 digits of precision (23 bit fractional component, log10(2^24) ≈ 7.225 decimal digits) so you could round off all but the 7 most significant digits.
I'm using SQL Server 2005. And I'm using ROUND T-SQL function to round a decimal column value. But it seems that the rounded value is incorrect.
PRINT ROUND(1890.124854, 2) => 1890.120000
As shown the ROUND function is returning 1890.12 where as it should be 1890.13. Does anyone encountered this and what should be the correct way of rounding so that I get the expected value 1890.13..?
Thanks.
ROUND() is working as it was intended to. You specified to round to 2 decimal places, and that's what you got.
Returns a numeric value, rounded to the specified length or precision.
Rounding means that a digit of 5 or above goes up to nearest, less than 5 down to nearest.
so,
PRINT ROUND(1890.125000, 2)
produces 1890.130000
Whereas
PRINT ROUND(1890.124999, 2)
produces 1890.120000
Your rounding issue is related to the rounding algorithm used by SQL Server. I believe SQL Server uses the "Round to Even" (sometimes known as Banker's Rounding) algorithm.
In Banker's Rounding, a digit get rounded down if the least significant digit to the right of it is less than five or rounded up if the least significant digit to the right of it is greater than five.
If the least significant digit to the right of it is equal to five, then the digit to the left of the five is rounded up to the nearest even number.
In your example of 1890.124854, as the rounding begins at the right-most digit and works to the left, the 8 causes the 4 to the left of it to get rounded up to 5. The five has an even number (2) to the left of it so, since it's already even, it leaves it alone. Thus, rounding to two decimal places should yield 1890.12.
However, if your example was instead 1890.134854, then as the rounding works from right to left, the 8 rounds the 4 up to 5 and then the 3 next to the 5 gets rounded up to the next even number which is 4. The result of rounding to two decimal places should then yield 1890.14.
The theory is that 1890.125 is neither closer to 1890.12 or 1890.13. It is exactly in between. Therefore, to always round up every digit to the left of a 5 would give an undesired upward bias that can skew calculations toward an artificially high result. This bias upward becomes more exaggerated in complex calculations or those involving multiple iterations where a five as the least-significant digit may be encountered numerous times. However, in general calculations, the number to the left of 5 is statistically just as likely to be odd as even. Because of this, rounding to the even number causes the calculation to statistically hover close to the true mean of the rounded number.
Anymore, almost everything uses this "Round to Even" algorithm. Many years ago, I used to develop in a programming language that didn't. It used the more "traditional" rounding where everything to the left of a 5 got rounded up, regardless of being odd or even. We ran into the biasing problem I mentioned above.