I have a value stored as Varchar(50) as "2016-07-21 16:35:05". I want to add 5 minutes to it. How do I do it? Expected output "2016-07-21 16:40:05" as a Varchar.
I've so far tried converting the value to DATETIME and adding 5 minutes. But when I try to convert it back to varchar, it doesn't show up in the same format.
SELECT
CAST(DATEADD(MINUTE, 5, CAST([PickTime] AS DATETIME)) AS VARCHAR(50))
FROM
rawdata
Output I get: Jul 21 2016 4:40PM
But I wanted: 2016-07-21 16:40:05
Could anyone guide me ?
Thanks
SELECT FORMAT(DATEADD(MINUTE, 5, cast([PickTime] as datetime)),'yyyy-MM-dd HH:mm:ss')
FROM rawdata
I have column of 24 hr and i need to change it to 12 hr, Please help .
Start time
174300
035800
023100
The result should be
Start time
05.43 PM
03.58 AM
02.31 AM
Use STUFF function to convert string to Time format
SELECT CONVERT(VARCHAR,CAST(STUFF(STUFF(ColumnName,3,0,':'),6,0,':') AS TIME),100)
Using one of the examples above - the following will work.
You need to split the data into hours/minutes and cast it to time format, than convert it to the relevant type:
declare #data int
set #data = 174300
select convert(VARCHAR(15),cast(cast(left(#data, 2 )as varchar(2)) + ':' + cast(substring(cast(#data as nvarchar(6)), 3,2 )as varchar(2) ) as time),100)
Don't store time as varchar, instead alter your table and change the column type to datetime.
SELECT right(convert(varchar(25), Start Time, 100), 7)
The 100 you see in the function specifies the date format mon dd yyyy hh:miAM (or PM), and from there we just grab the right characters.
You can see more about converting datetimes here.
I want to query a subset from a dataset. Each row has a time stamp of the following format:
2014-04-25T17:25:14
2014-04-25T18:40:16
2014-04-25T18:44:57
2014-04-25T19:10:32
2014-04-25T20:22:12
...
Currently, I use the following query to select a time-based subset:
time LIKE '%2014-04-25T18%' OR time LIKE '%2014-04-25T19%'
This becomes quite complicated when you start to filter by mintutes or seconds.
Is there a way to run a query that such as ...
time > '%2014-04-25T18%' AND time < '%2014-04-25T19%'
A regular expression would be okay, too.
The database is a SpatiaLite database. The time column is of type VARCHAR.
If the date is being treated as a string and based on the example above:
time LIKE '%2014-04-25T18%' AND time <> '%2014-04-25T18:00:00:000'
Otherwise, you could convert the date to seconds since midnight and add 60 minutes to that to create the range part of the filter
DECLARE #test DATETIME = '2014-04-25T17:25:14'
SELECT #test
, CONVERT(DATE,#test) AS JustDate
, DATEDIFF(s,CONVERT(DATETIME,(CONVERT(DATE,#test))), #test) AS SecondsSinceMidnight
-- 60 seconds * 60 minutes * 24 hours = 86400
Thanks to your posts and this answer I came up with this solution:
SELECT * FROM data
WHERE DATETIME(
substr(time,1,4)||'-'||
substr(time,6,2)||'-'||
substr(time,9,2)||' '||
substr(time,12,8)
)
BETWEEN DATETIME('2014-04-25 18:00:00') AND DATETIME('2014-04-25 19:00:00');
I got a column called DateOfBirth in my csv file with Excel Date Serial Number Date
Example:
36464
37104
35412
When i formatted cells in excel these are converted as
36464 => 1/11/1999
37104 => 1/08/2001
35412 => 13/12/1996
I need to do this transformation in SSIS or in SQL. How can this be achieved?
In SQL:
select dateadd(d,36464,'1899-12-30')
-- or thanks to rcdmk
select CAST(36464 - 2 as SmallDateTime)
In SSIS, see here
http://msdn.microsoft.com/en-us/library/ms141719.aspx
The marked answer is not working fine, please change the date to "1899-12-30" instead of "1899-12-31".
select dateadd(d,36464,'1899-12-30')
You can cast it to a SQL SMALLDATETIME:
CAST(36464 - 2 as SMALLDATETIME)
MS SQL Server counts its dates from 01/01/1900 and Excel from 12/30/1899 = 2 days less.
tldr:
select cast(#Input - 2e as datetime)
Explanation:
Excel stores datetimes as a floating point number that represents elapsed time since the beginning of the 20th century, and SQL Server can readily cast between floats and datetimes in the same manner. The difference between Excel and SQL server's conversion of this number to datetimes is 2 days (as of 1900-03-01, that is). Using a literal of 2e for this difference informs SQL Server to implicitly convert other datatypes to floats for very input-friendly and simple queries:
select
cast('43861.875433912' - 2e as datetime) as ExcelToSql, -- even varchar works!
cast(cast('2020-01-31 21:00:37.490' as datetime) + 2e as float) as SqlToExcel
-- Results:
-- ExcelToSql SqlToExcel
-- 2020-01-31 21:00:37.490 43861.875433912
this actually worked for me
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-30')
(minus 1 more day in the date)
referring to the negative commented post
SSIS Solution
The DT_DATE data type is implemented using an 8-byte floating-point number. Days are represented by whole number increments, starting with 30 December 1899, and midnight as time zero. Hour values are expressed as the absolute value of the fractional part of the number. However, a floating point value cannot represent all real values; therefore, there are limits on the range of dates that can be presented in DT_DATE. Read more
From the description above you can see that you can convert these values implicitly when mapping them to a DT_DATE Column after converting it to a 8-byte floating-point number DT_R8.
Use a derived column transformation to convert this column to 8-byte floating-point number:
(DT_R8)[dateColumn]
Then map it to a DT_DATE column
Or cast it twice:
(DT_DATE)(DT_R8)[dateColumn]
You can check my full answer here:
Is there a better way to parse [Integer].[Integer] style dates in SSIS?
Found this topic helpful so much so created a quick SQL UDF for it.
CREATE FUNCTION dbo.ConvertExcelSerialDateToSQL
(
#serial INT
)
RETURNS DATETIME
AS
BEGIN
DECLARE #dt AS DATETIME
SELECT #dt =
CASE
WHEN #serial is not null THEN CAST(#serial - 2 AS DATETIME)
ELSE NULL
END
RETURN #dt
END
GO
I had to take this to the next level because my Excel dates also had times, so I had values like this:
42039.46406 --> 02/04/2015 11:08 AM
42002.37709 --> 12/29/2014 09:03 AM
42032.61869 --> 01/28/2015 02:50 PM
(also, to complicate it a little more, my numeric value with decimal was saved as an NVARCHAR)
The SQL I used to make this conversion is:
SELECT DATEADD(SECOND, (
CONVERT(FLOAT, t.ColumnName) -
FLOOR(CONVERT(FLOAT, t.ColumnName))
) * 86400,
DATEADD(DAY, CONVERT(FLOAT, t.ColumnName), '1899-12-30')
)
In postgresql, you can use the following syntax:
SELECT ((DATE('1899-12-30') + INTERVAL '1 day' * FLOOR(38242.7711805556)) + (INTERVAL '1 sec' * (38242.7711805556 - FLOOR(38242.7711805556)) * 3600 * 24)) as date
In this case, 38242.7711805556 represents 2004-09-12 18:30:30 in excel format
In addition of #Nick.McDermaid answer I would like to post this solution, which convert not only the day but also the hours, minutes and seconds:
SELECT DATEADD(s, (42948.123 - FLOOR(42948.123))*3600*24, dateadd(d, FLOOR(42948.123),'1899-12-30'))
For example
42948.123 to 2017-08-01 02:57:07.000
42818.7166666667 to 2017-03-24 17:12:00.000
You can do this if you just need to display the date in a view:
CAST will be faster than CONVERT if you have a large amount of data, also remember to subtract (2) from the excel date:
CAST(CAST(CAST([Column_With_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you need to update the column to show a date you can either update through a join (self join if necessary) or simply try the following:
You may not need to cast the excel date as INT but since the table I was working with was a varchar I had to do that manipulation first. I also did not want the "time" element so I needed to remove that element with the final cast as "date."
UPDATE [Table_with_Date]
SET [Column_With_Excel_Date] = CAST(CAST(CAST([Column_With_Excel_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you are unsure of what you would like to do with this test and re-test! Make a copy of your table if you need. You can always create a view!
Google BigQuery solution
Standard SQL
Select Date, DATETIME_ADD(DATETIME(xy, xm, xd, 0, 0, 0), INTERVAL xonlyseconds SECOND) xaxsa
from (
Select Date, EXTRACT(YEAR FROM xonlydate) xy, EXTRACT(MONTH FROM xonlydate) xm, EXTRACT(DAY FROM xonlydate) xd, xonlyseconds
From (
Select Date
, DATE_ADD(DATE '1899-12-30', INTERVAL cast(FLOOR(cast(Date as FLOAT64)) as INT64) DAY ) xonlydate
, cast(FLOOR( ( cast(Date as FLOAT64) - cast(FLOOR( cast(Date as FLOAT64)) as INT64) ) * 86400 ) as INT64) xonlyseconds
FROM (Select '43168.682974537034' Date) -- 09.03.2018 16:23:28
) xx1
)
For those looking how to do this in excel (outside of formatting to a date field) you can do this by using the Text function https://exceljet.net/excel-functions/excel-text-function
i.e.
A1 = 132134
=Text(A1,"MM-DD-YYYY") will result in a date
This worked for me because sometimes the field was a numeric to get the time portion.
Command:
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-31')
I am using MS webmatrix and razor.
I have a query that uses the expression CAST(GetDate() as INT) to get the current date integer value. However, even though my server and PC are both set on GMT + 12 (Wellington, Auckland), the value returned is 12 hours out - and at 12.00 pm on my PC (and the server) it jumps ahead one day.
How do I trim 12 hours off the value, without having to set the time 12 hours wrong on my machines?
Grateful for any help.
Coercing a date directly into an INT looks quite wrong.
To properly get just the INTEGRAL value of the date, use DATEDIFF directly.
select cast(cast('20120301' as datetime) as int) -- 40967
select cast(cast('20120301 12:30' as datetime) as int) -- 40968, oh noes!
select datediff(d,0,'20120301') -- 40967
select datediff(d,0,'20120301 12:30') -- 40967, yes!