When you type hackisition on Google, it returns the following url as first result:
https://www.hackisition.com/en/
// instead of
https://www.hackisition.com/
I'd like to replace that link by the real homepage. How can I do that? Is there a way to specifically ask Google to show this homepage?
I am getting "https://www.hackisition.com/" as first result for "hackisition". I'm not sure why you're getting such result. Try to clear cookies and turn off VPN/Proxy if you're using one.
We are getting result as you said , so I suggest to clear cache
Maybe that is because of User location.
That mean countries preferred English on search would be able to see /en
and other countries that not prefer English will see the non /en result.
Search your website on
Google.ae
Google.DK
you'll see https://www.hackisition.com in result not https://www.hackisition.com/en.
But if you search in Google.com, Google.eu you'll see the result https://www.hackisition.com/en
Hope this would be the solution of your problem.
Related
This page is returning an empty extract:
https://fr.wikipedia.org/w/api.php?action=query&prop=extracts&titles=Alerte%20Rouge%20%28groupe%29&explaintext&rvprop=content&format=json
But the same query works for other pages:
https://fr.wikipedia.org/w/api.php?action=query&prop=extracts&titles=?action=query&prop=extracts&titles=B%C3%A9rurier_noir&explaintext&rvprop=content&format=json
Adding "&exlimit=max&exintro" as suggested in other topics didn't fix the issue.
Am I doing something wrong?
On French Wikipedia, "Alerte Rouge (groupe)" is a redirect to "Alerte rouge (groupe)".
Requesting extracts on redirects does not work. Thus you have to use the correct title, i.e. https://fr.wikipedia.org/w/api.php?action=query&prop=extracts&titles=Alerte%20rouge%20(groupe)&explaintext&format=json
I am trying to retrieve data from cloudSearch, searching for the word "Person" and adding the following filter:
(prefix field=claimedgalleryid '')
The problem is that I don't know how to create the URL using that exact filter.
Could someone give me a suggestion or some link to Amazon documentation related to this topic?
What I've tried and didn't work:
...search?q=Gallerist&size=10&start=0&fq=(prefix%20field=claimedgalleryid%20%27%27)
...search?q=Gallerist&size=10&start=0&filter=(prefix%20field=claimedgalleryid%20%27%27)
You were close with your first attempt--it looks like you forgot to URI encode the = sign as %3D. Try this instead:
&fq=(prefix+field%3Dclaimedgalleryid+'')
I highly recommend using the "test search" feature to work out the kinks in your query syntax. You can see the results right there, and then use the "View Raw: JSON" link to copy the full request URL and see how characters get escaped and such.
I followed this blog Tips 1and created a crawl rule http://.*forms/allitems.aspx and ran full crawl. I no longer get the results with AllItems.aspx. However, if there is any document with name Something.doc in a Document Library , it no longer gets pulled in the search results.
I think what I desire is a basic functionality, like the user should not get to see Allitems.aspx in the search results but should get the item/document with names entered in the search box.
Please let me know if I am missing anything. I have already put in 24 hours...googled the max I could.
It seems that an Index Reset is required. Here's the steps I did:
1. Add the following crawl rule to exclude: *://*allitems.aspx.
2. Index Reset.
3. Full Crawl.
I could not find a good way to do this using crawl rules. Instead, I opted to set up a restriction on the search results web part.
In the search results web part properties, select "Change Query"
Add a property filter to exclude anything with "AllItems" (and any other exclusions you want in place.
Used Steve Mann's blog as a reference and for the images: http://stevemannspath.blogspot.com/2013/04/sharepoint-2013-search-removing-junk.html
Google Analytics API: how to extract pageviews for a specific page?
I tried using something like
ga:pagePath=~page.php%3fid%3d44 (page.php?id=44)
but it doesn't seem to work... I get "no results found" where I have 20 pageviews for sure
UPDATE
I think I found the solution
ga:pagePath==/website/page.php?id=44
for some reason I had to include the complete path and ==
To use a partial path to match for a page in filters you should use
ga:pagePath=#page.php?id=44
=# tells ga to match a substring.
What you were originally using was incorrect for this.
I think your problem is that you put the hex version of the ? and = characters into your query, which doesn't match how Analytics stores the page paths. If you change these to the normal characters it should work:
ga:pagePath=~page.php?id=44
Your other solution should work as well but is a bit more inflexible in case you wanted to tweak the query to return other pages.
I am making some PHP code which takes a given search phrase and url and searches through the google search results until it finds the url (only first 100 results). My problem is, this is only working for the US. I have tried adding the "&cr=" option, but it still on returns US results.
The full URL I am using for the request is:
https://www.googleapis.com/customsearch/v1?key=API_KEY&cx=CX_VALUE&q=KEYWORD&cr=COUNTRY&alt=JSON
Does anyone have any experience with this? I want to be able to see UK results. Tried inserting &cr=countryUK , but still only does US results.
Thanks :)
Regards,
Stian
Use the gl=<country code> param to limit it to your country of choice (so gl=gb for the uk).
More info here:
http://googleajaxsearchapi.blogspot.com/2009/10/web-search-in-your-country.html