I've looked all over the internet and stackoverflow for an answer to this question, but can't seem to find anything that answers it so here goes...
Is there anything special that needs to be done to a forward slash (/) for them to be included in search queries?
Scenario: I have a query that contains a string being searched for that includes a forward slash. The search term is a dimension of a particular item so it must contain the slash to indicate a fraction. I've tried escaping it with a backslash, but that doesn't work. The query is as follows:
SELECT * FROM ITEMDATA WHERE CONTAINS(dimensions, '3/8')
This query returns 0 results.
Example of data to be searched on:
•Pitch: 3/8"
•Gauge: .050
I also need to get the double quote in the search phrase to specify units, but that's another problem.
Any suggestions?
As the following demonstrates, you can use "/" in a LIKE expression without any tricks:
create table foo(a int, b varchar(32))
go
insert into foo select 1, 'for 3/8 inch';
go
select * from foo where b like '%3/8%';
go
This will result in the single row being found.
If we need to search in sql table column with a particular string, we need to use LIKE command, so that we can use it like in various ways.
1. Returns results having dimensions column value contains the string 3/8
'SELECT * FROM ITEMDATA WHERE dimensions LIKE '%3/8%';`
Returns results having dimensions column value strictly starts with the string 3/8
SELECT * FROM ITEMDATA WHERE dimensions LIKE '3/8%';
Returns results having dimensions column value strictly ends with the string 3/8.
SELECT * FROM ITEMDATA WHERE dimensions LIKE '3/8%';
Disable STOPLIST for full-text:
ALTER FULLTEXT INDEX ON table SET STOPLIST OFF
and try
SELECT * FROM ITEMDATA WHERE CONTAINS (dimensions, '"3/8*"')
Related
i have a table column looks like below.
what is the sql query statement i can use to have multiple partial match conditions?
search by ID or Name
if search abc then list the row A1 , row A2
if search test then list the row A1 , row A2, row 3
if search ghj then list the row A2
i was trying this but nothing return:
SELECT * FROM table where colB LIKE '"ID":"%abc%"'
updating data in text
{"ItemId":"123","IDs":[{"ID":"abc","CodingSystem":"cs1"}],"Name":"test itemgh"}
{"ItemId":"123","IDs":[{"ID":"ghj","CodingSystem":"cs1"}],"Name":"test abc"}
{"ItemId":"123","IDs":[{"ID":"defg","CodingSystem":"cs1"}],"Name":"test 111"}
JSON parsing
Oracle
Looked into the JSON parsing capabilities of Oracle and I managed to make running a query like this:
select * from table t where json_exists(t.colB, '$.IDs[?(#.ID=="abc")]') or json_exists(t.colB, '$.IDs?(#.name=="abc"')
And inside the same JSON query expression:
select * from table t where json_exists(t.colB, '$.IDs[?(#.ID=="abc" || #.name=="abc")]')
The call of function json_exists() is the key to this.
The first parameter can be a VARCHAR2, and I also tried with a BLOB containing text, and it works.
The second parameter is the path to your json object attribute that needs to be tested, with the condition.
I wrote two ORed conditions for the ID and for the Name, but maybe there is a better JSON query expression you can use to include them both.
More information about json_exists() function here.
Postgres
There is a JSON datatype in Postgres that supports parsing in queries.
So, if your colB column is declared as JSON you can do something like this:
select * from table where colB->>'Name' LIKE '%abc%';
And in order to have available the array elements of the IDs array, you should use the function json_array_elements().
select * from table, json_array_elements(colB->'IDs') e where colB->>'Name' LIKE '%abc%' or e->>'ID' = 'abc';
Check an example I created for you here.
Here is an online tool for online testing your JSON queries.
Check also this question in SO.
MSSQL Server 2017
I made a couple of tests also with MS SQL Server, and I managed to create an example searching for partial matching in the name field.
select * from table where JSON_VALUE(colB,'$.Name') LIKE '%abc%';
And finally I arrived to a working query that does partial match to the Name field and full match to the ID field like this:
select * from table t
CROSS APPLY OPENJSON(colB, '$.IDs') WITH (
ID VARCHAR(10),
CodingSystem VARCHAR(10)
) e
where JSON_VALUE(t.colB,'$.Name') LIKE '%abc%'
or e.ID = 'abc';
The problem is that we need to open the IDs array, and make something like a table from it, that can be queried also by accessing its columns.
The example I created is here.
LIKE text query
Your tries are good but you misplace the % symbols. They have to be first and last in your given string:
If you want the ID to be the given value:
SELECT * FROM table where colB LIKE '%"ID":"abc"%'
If the given value can be anywhere, then don't put the "ID" part:
SELECT * FROM table where colB LIKE '%abc%'
If the given value can be only on the ID or Name field then:
SELECT * FROM table where colB LIKE '%"ID":"abc"%' OR colB LIKE '%"Name":"abc"%'
And because you are giving hard-coded identifiers of fields (eg ID and Name) that can be in variable case:
SELECT * FROM table where lower(colB) LIKE '%"id":"abc"%' OR lower(colB) LIKE '%"name":"abc"%'
Assuming that the number of spaces do not vary between the : character and the value or the name of the properties.
For partial matching you can use more % in between like '%"name":"%abc%"%':
SELECT * FROM table where lower(colB) LIKE '%"id":"abc"%' OR lower(colB) LIKE '%"name":"%abc%"%'
Regular Expressions
A different option would be to test with regular expressions.
Consider checking this: Oracle extract json fields using regular expression with oracle regexp_substr
I'm trying to find a working query for using MATCH AGAINST while having a search term containing a single quote.
Example data in the database table:
I'm a freak
Example search term:
I'm
Search queries I tried:
SELECT * FROM table WHERE MATCH (name) AGAINST ('"I\'m"' IN NATURAL LANGUAGE MODE);
SELECT * FROM table WHERE MATCH (name) AGAINST ('"I\'m"' IN BOOLEAN MODE);
SELECT * FROM table WHERE MATCH (name) AGAINST ('I\'m*' IN BOOLEAN MODE);
SELECT * FROM table WHERE MATCH (name) AGAINST ('(I\'m)*' IN BOOLEAN MODE);
...and many more. Nothing is working.
I'm using MariaDB 10.1.33.
Any ideas?
I'm pretty sure contractions are not treated as words.
Instead the apostrophe is treated as a word separator giving you "I" and "m".
But you probably don't have innodb_ft_min_token_size=1, so those two "words" are ignored.
There are limitations of FT; you have encountered one of them.
I would like to ask if it is possible to do this:
For example the search string is '009' -> (consider the digits as string)
is it possible to have a query that will return any occurrences of this on the database not considering the order.
for this example it will return
'009'
'090'
'900'
given these exists on the database. thanks!!!!
Use the Like operator.
For Example :-
SELECT Marks FROM Report WHERE Marks LIKE '%009%' OR '%090%' OR '%900%'
Split the string into individual characters, select all rows containing the first character and put them in a temporary table, then select all rows from the temporary table that contain the second character and put these in a temporary table, then select all rows from that temporary table that contain the third character.
Of course, there are probably many ways to optimize this, but I see no reason why it would not be possible to make a query like that work.
It can not be achieved in a straight forward way as there is no sort() function for a particular value like there is lower(), upper() functions.
But there is some workarounds like -
Suppose you are running query for COL A, maintain another column SORTED_A where from application level you keep the sorted value of COL A
Then when you execute query - sort the searchToken and run select query with matching sorted searchToken with the SORTED_A column
I need to find the '&' in a string.
SELECT * FROM TABLE WHERE FIELD LIKE ..&...
Things we have tried :
SELECT * FROM TABLE WHERE FIELD LIKE '&&&'
SELECT * FROM TABLE WHERE FIELD LIKE '&\&&'
SELECT * FROM TABLE WHERE FIELD LIKE '&|&&' escape '|'
SELECT * FROM TABLE WHERE FIELD LIKE '&[&]&'
None of these give any results in SQLServer.
Well some give all rows, some give none.
Similar questions that didn't work or were not specific enough.
Find the % character in a LIKE query
How to detect if a string contains special characters?
some old reference Server 2000
http://web.archive.org/web/20150519072547/http://sqlserver2000.databases.aspfaq.com:80/how-do-i-search-for-special-characters-e-g-in-sql-server.html
& isn't a wildcard in SQL, therefore no escaping is needed.
Use % around the value your looking for.
SELECT * FROM TABLE WHERE FIELD LIKE '%&%'
Your statement contains no wildcards, thus is equivalent to WHERE FIELD = '&'.
& isn't a special character in SQL so it doesn't need to be escaped. Just write
WHERE FIELD LIKE '%&%'
to search for entries that contain & somewhere in the field
Be aware though, that this will result in a full table scan as the server can't use any indexes. Had you typed WHERE FIELD LIKE '&%' the server could do a range seek to find all entries starting with &.
If you have a lot of data and can't add any more constraints, you should consider using SQL Server's full-text search to create and use and FTS index, with predicates like CONTAINS or FREETEXT
I have a table with column mapping which store record: "IV=>0J,IV=>0Q,IV=>2,V=>0H,V=>0K,VI=>0R,VI=>1,"
What is the sql to check whether or not a substring is in column mapping.
so, I would like this:
if I have "IV=>0J" would return true, because IV=>0J is exact in string "mapping"
if I have "IV=>01" would return false. And so on...
I try this:
SELECT * FROM table WHERE charindex('IV=>0J',mapping)
But when I have "IV=>0", it returns TRUE. But, it should return FALSE.
Thank You..
You can search with commas included. Just also add one at beginning and end of mapping:
SELECT * FROM table WHERE charindex(',IV=>0J,',',' + mapping + ',') <> 0
or
SELECT * FROM table WHERE ',' + mapping + ',' LIKE '%,IV=>OJ,%'
This should do the trick:
SELECT * FROM table
WHERE
mapping LIKE '%,IV=>0J,%'
OR mapping LIKE '%,IV=>0J'
OR mapping LIKE 'IV=>0J,%'
OR mapping = 'IV=>0J'
But you should really normalize the database - you are currently violating the principle of atomicity, and therefore the 1NF. Your current difficulties in querying and the future difficulties with performance that you are about to encounter all stem from this root problem...
While you can search by including a comma in the string, this is a bad design for several reasons.
You are unable to take advantage of indexing
You force a full scan of the table, which will lead to bad performance AND excessive blocking.
You have to make sure that there is always a leading or a trailing comma (depends on what you expect in your LIKE expression).
You are no longer able to edit a single entry, you'll have to replace the entire string each time you want to change even a single mapping.
You open yourself to a concurrency nightmare if more that one users try to update different mappings that just happen to be stored in the same column.
Your table isn't even in 1st normal form any more, which is why you have such difficulties
You should normalize your mapping column, by extracting the data to a different mapping table, with at least the From and To columns you require. You can then add these columns to an index an convert your query using only a single index seek.
You can also add the ID values of your source table to the Mappings table and the index. This will allow you to convert the lookup for a source row to a join between the two tables that takes advantage of indexing
charindex returns the position of the text, not Boolean.
to check if the text exists, compare to 0:
SELECT * FROM table WHERE charindex('IV=>0J',mapping) <> 0
I think you're missing something here, the Charindex function does not return TRUE or FALSE.
It returns the starting point of the substring inside master string, or if the substring is not present, then -1.
So you query should read,
SELECT * FROM table WHERE charindex('IV=>0J',mapping) > 0