I have a table with 2 columns: Customer_ID, which is a string, identifying each client and Time_id: a string with 14 characters, identifying timestamp of a transaction. Example:
Customer_id; Time_id
12345; 20140703144504
I want to be able to use datediff in hours datepart, but I can´t seem to be able to convert time_id properly. I use the following query:
update transation_table
set time_id= (
convert(timestamp, time_id)
)
It works, but removes hours datepart, which is what I need. For day datepart I can do it, converting to datetime. How can I keep in the table the hh?
edit: I´m running MS SQL Server 2014.
best regards
Using the convert and string concatenation below, you can use DATEPART on the resulting value.
DECLARE #tmp TABLE(
Customer_id VARCHAR(50),
Time_id VARCHAR(50)
)
INSERT INTO #tmp
SELECT '12345','20140703144504'
select
*,CONVERT(DATETIME,
SUBSTRING(Time_id,5,2) + '/' +
SUBSTRING(Time_id,7,2) + '/' +
SUBSTRING(Time_id,1,4) + ' ' +
SUBSTRING(Time_id,9,2) + ':' +
SUBSTRING(Time_id,11,2) + ':' +
SUBSTRING(Time_id,13,2)
,101
)
from #tmp
Use FORMAT to get a string representation of the value in a supported format (ODBC canonical in the Date and Time styles chart), then use TRY_CONVERT to return an actual datetime value:
SELECT TRY_CONVERT(DATETIME,
FORMAT(CAST('20140703144504' AS BIGINT),
'####-##-## ##:##:##'),
120);
This requires SQL Server 2012+.
As mentioned elsewhere, the data should be stored in a single datetime2 column, or paired date and time columns. The above functions can be used to help convert existing data to the new column(s).
Related
I need to change the numeric format into 'AM/PM' format in CONCAT function (I use SSMS v 18.5.1)
Here is my formula. RCLDTE - is a date and RCLTIM is time. I basically need to leave RCLDTE as it is and change the format of RCLTIM from numeric to date and convert to AM/PM format.
How the column looks right now
Format of RCLTIM - numeric
CONCAT(c.RCLDTE, ' & ', MAX(c.RCLTIM)) AS 'Date & Time',
When I tried to use CONVERT function as I tend to use, it raised an error.
CONCAT(c.RCLDTE, ' & ', CONVERT(varchar(15),CAST( MAX(c.RCLTIM) AS TIME),100))
Error
Explicit conversion from data type numeric to time is not allowed.
The number for the date can be concatenated to the number for the time stuffed with colons. So that it can be converted to a DATETIME.
And by using FORMAT the DATETIME can be put in a specific format.
(But use CONVERT if it has the format.)
Test snippet
declare #test table (
ID INT IDENTITY PRIMARY KEY,
RCLDTE int,
RCLTIM int
);
insert into #test (RCLDTE, RCLTIM) values
(20220119, 215250)
, (20220304, 070809)
;
select
FORMAT(TRY_CAST(CONCAT(c.RCLDTE, ' ', STUFF(STUFF(FORMAT(MAX(c.RCLTIM),'000000'),5,0,':'),3,0,':')) AS DATETIME)
, 'd/M/yyyy hh:mm:ss tt') AS [Date & Time]
from #test c
group by RCLDTE;
Date & Time
19/1/2022 09:52:50 PM
4/3/2022 07:08:09 AM
Test on db<>fiddle here
What you're attempting to do is very fragile, but I presume your source system gives you few options.
Converting like this has potential problems with DST & the language in use at the time of running.
Your question lost some of the detail regarding formats, so I can't see the time type you are using, but it looks like a decimal again.
Essentially, you need to put the the numerics in a string and then into datetime columns, but to get there you have to match a string conversion format the sqlserver.
Fortunately you are not far off the us format default.
Something like this will get you a date field, you can then amend the output format if you really need 12hr rather than 24hr.
SET LANGUAGE us_english
DECLARE #rcldte NUMERIC, #rcltim numeric
SET #rcldte=20220119
SET #rcltim = 015250
SELECT
CONVERT(DATETIME, CAST (#rcldte AS VARCHAR)+ ' ' +
LEFT( left('000000', 6-LEN(CAST ( #rcltim AS VARCHAR)))+CAST ( #rcltim AS VARCHAR),2)
+ ':' + substring( left('000000', 6-LEN(CAST ( #rcltim AS VARCHAR)))+CAST ( #rcltim AS VARCHAR),3,2)
+ ':' + RIGHT( left('000000', 6-LEN(CAST ( #rcltim AS VARCHAR)))+CAST ( #rcltim AS VARCHAR),2))
Which will give you:
(No column name)
2022-01-19 01:52:50.000
It's rather ugly though.
If you can guarantee the hours are zero padded then you could remove the complexity associated with that.
And if you're really going to use it then split into proper UDFs...
DECLARE #RCLDTE CHAR(8) = '20220119';
DECLARE #RCLTIM CHAR(6) = '215250';
select CONVERT(VARCHAR(21), (cast(#RCLDTE as DATETIME) + cast(substring(#RCLTIM,1,2)+':'+substring(#RCLTIM,3,2)+':'+substring(#RCLTIM,5,2) as DATEtime) ), 22);
output: 01/19/22 9:52:60 PM
For different formats of the DATETIME, see the docs of the CONVERT function:
https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql?view=sql-server-ver15
NOTE: When specifying another format the value 21 in VARCHAR(21) might need a change...
I am converting a date using CONVERT(varchar,DateOfBirth,101) for birthdates.
I want to show these dates with the current year, I've tried REPLACE but you can't use wildcards with it and when I use DATEPART, it doesn't format with the right digits for month and day. I also can't add years because they are wildly different birthdates. Thanks.
If you want to display the date as a string in 101 format for current year, one option uses a direct format():
format(DateOfBirth, 'MM/dd/2020')
You can compute the current date dynamically:
format(DateOfBirth, concat('MM/dd/', year(getdate())))
On the other hand, if you want your result as a date, then you could use datefromparts():
datefromparts(year(getdate()), month(DateOfBirth), day(DateOfBirth))
If it is a datevalue, you can use FORMAT function. If it is a character value, you can use RIGHT and REPLACE.
DECLARE #dateValue DATETIME = '05/12/1999'
DECLARE #dateCharValue VARCHAR(12) = '05/12/1999'
SELECT FORMAT(#dateValue, 'MM/dd/2020')
SELECT REPLACE(#dateCharValue, RIGHT(#dateCharValue,4),2020)
--Result
05/12/2020
This could helped you:
The code CONVERT(varchar(5),GETDATE(),1) return this 05/27 and then just add the year of the date
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + cast(year(getdate()) as varchar)
Or
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + convert(varchar,year(getdate()))
The result of both:
05/27/2020 --(This is my current date n.n )
This work but if you use a string something like your example DateOfBirth will be the variable and if this is a string (DateOfBirth = '5/27/1987') you need to convert the string DateOfBirth to Date:
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + cast(year(GETDATE()) as varchar)
Or
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + convert(varchar,year(GETDATE()))
The Result of Both :
05/27/2020
I would like to store dates in the format CCYYMMDD in Teradata, but I fail to do so. Find below what I tried so far:
query 1:
SEL CAST(CAST(CURRENT_DATE AS DATE FORMAT 'YYYYMMDD') AS VARCHAR(8))
-- Output: 20191230 ==> this works!
query 2:
SEL CAST(CAST(CURRENT_DATE AS DATE FORMAT 'CCYYMMDD') AS VARCHAR(8))
-- output: SELECT Failed. [3530] Invalid FORMAT string 'CCYYMMDD'.
It seems that the CCYYMMDD is not available in Teradata right away. Is there a workaround?
Tool used: Teradata SQL assistant
Internally, dates are stored as integers in Teradata. So when you say you want to store them in a different format, I don't think you can do that. But you can choose how to display / return the values.
I'm sure there's a cleaner way to get the format you want, but here's one way:
WITH cte (mydate) AS (
SELECT CAST(CAST(CURRENT_DATE AS DATE FORMAT 'YYYYMMDD') AS CHAR(8)) AS mydate
)
SELECT
CAST(
(CAST(SUBSTRING(mydate FROM 1 FOR 2) AS INTEGER) + 1) -- generate "century" value
AS CHAR(2) -- cast value as string
) || SUBSTRING(mydate FROM 3) AS new_date -- add remaining portion of date string
FROM cte
SQL Fiddle - Postgres
You'd have to add some extra logic to handle years before 1000 and after 9999. I don't have a TD system to test, but give it a try and let me know.
I have a date saved in an nvarchar type and I want to split the day, month and year into separate nvarchar variables (that means three variables). The date looks as follows: exposure_date ='2018-12-04' and the format is yyyy-dd-mm
any help please?
My whole project is stuck on this.
The "correct" answer here is to fix your datatype. When storing data always choose an appropriate data type for the data you're storing. For a date (with no time part) then the correct datatype is date. if you're storing numerical data, then use a numerical datatype, such as int or decimal. (n)varchar is not a one size fits all datatype and using it to store data that has a data type designed for it is almost always a bad choice. I'm storing the data as an (n)varchar because I need it in a specific format is never an excuse; have your presentation layer handle to display format, not your RDBMS.
The first step, therefore would be to change your string representation yyyy-dd-MM of a date to the ISO format yyyyMMdd by doing:
UPDATE YourTable
SET exposure_date = LEFT(exposure_date,4) + RIGHT(exposure_date,2) + SUBSTRING(exposure_date,6,2);
Now you have a unambiguous representation, you can change the data type of your column without concerns of incorrect implicit casts or error:
ALTER YourTable ALTER COLUMN exposure_date date;
Then, finally, you can treat your data as what it is, a date, and use the DATEPART function:
SELECT DATEPART(YEAR,exposure_date) AS Exposure_Year,
DATEPART(MONTH,exposure_date) AS Exposure_Month,
DATEPART(DAY,exposure_date) AS Exposure_Day
FROM YourTable;
You can also try the following
Declare #myDate date
select #myDate= Cast(substring('2011-29-12', 1, 4)
+ '-' + substring('2011-29-12', 9, 2)
+ '-' + substring('2011-29-12', 6, 2)
as Date) --YYYY-MM-DD
Select #myDate as DateTime,
datename(day,#myDate) as Date,
month(#myDate) as Month,
datename(year,#myDate) as Year,
Datename(weekday,#myDate) as DayName
The output is as shown below
DateTime Date Month Year DayName
--------------------------------------------
2011-29-12 29 12 2011 Thursday
You can find the live demo here
You can try below -
select concat(cast(year(cast('2018-12-04' as date)) as varchar(4)),'-',
cast(month(cast('2018-12-04' as date)) as varchar(2)), '-',
cast(day(cast('2018-12-04' as date)) as varchar(2)))
from tablename
If you have fixed format, then you could use this simple query with substring method:
select substring(dt, 1, 4) + '-' +
substring(dt, 9, 2) + '-' +
substring(dt, 6, 2) [YYYY-MM-DD]
from (values ('2018-31-12')) tbl(dt)
Let's go directly to the main issue, which is you are using the wrong datatype to store dates, you should store them as DATE, the datatypes are there for a reason and you need to choose a proper one for your column.
So, you need to ALTER your table and change the column datatype to DATE instead of NVARCHAR datatype.
ALTER <Table Name Here>
ALTER COLUMN <Column Name Here> DATE;
Then all things will easy, you just run the following query to get the desired output
SELECT YEAR(<Column Name Here>) TheYear,
MONTH(<Column Name Here>) TheMonth,
DAY(<Column Name Here>) TheDay
FROM <Table Name Here>
Which is the right and the best solution.
You can also (if you are not going to alter your table) do as
CREATE TABLE Dates(
StrDate NVARCHAR(10)
);
INSERT INTO Dates VALUES
(N'2018-12-04'),
(N'Invalid');
SELECT LEFT(StrDate, 4) StrYear,
SUBSTRING(StrDate, 6, 2) StrMonth,
RIGHT(StrDate, 2) StrDay
FROM Dates;
OR
SELECT YEAR(StrDate) StrYear,
MONTH(StrDate) StrMonth,
DAY(StrDate) StrDay
FROM (
SELECT TRY_CAST(StrDate AS DATE) StrDate
FROM Dates
)T
I am working on a project in which dates and times ar stored as a varchar e.g. "30-11-2017,7:30" first date in dd-mm-yyy format and then time separated with a comma. I am trying to filter on it but it is not working correctly kindly guide me how to filter data on date.
select *
from timetrack
where startDateAndTime >= '30-11-2017,7:30'
In attached image records have been shown. When I apply above query it shows no records
You can easily convert your date to SQL datatype datetime uisng parse function, for example select parse('30-11-2017,7:30' as datetime using 'it-IT').
So, in your case, you can apply this function in where clause, so you can easily apply comparison between dates:
select *
from timetrack
where parse(startDateAndTime as datetime using 'it-IT') >= '2017-11-30 07:30:00.000'
Your format is apparently italian :) But you have to specify your own date in the format convertable to datetime, as I have done in above example.
NOTE: parse is available starting with SQL Management Studio 2012.
Unless you are using ISO date format (yyyy-MM-dd HH:mm:ss or close) applying ordering (which inequalities like greater than or equal use) will not work: the date order is disconnected from the string ordering.
You'll need to parse the date and times into a real date time type and then compare to that (details of this depend on which RDBMS you are using).
If, you want to just filter out the date then you could use convert() function for SQL Server
select *
from timetrack
where startDateAndTime >= convert(date, left(#date, 10), 103)
Else convert it to datetime as follow
select *
from timetrack
where startDateAndTime >= convert(datetime, left(#date, 10)+' ' +
reverse(left(reverse(#date), charindex(',', reverse(#date))-1)), 103)
You need the date in a datetime column, Otherwise you can't filter with your current varchar format of your date.
Without changing the existing columns, this can be achieved by making a computed column and making it persisted to optimize performance.
ALTER TABLE test add CstartDateTime
as convert(datetime, substring(startDateAndTime, 7,4)+ substring(startDateAndTime, 4,2)
+ left(startDateAndTime, 2) +' '+ right(startDateAndTime, 5), 112) persisted
Note: this require all rows in the column contains a valid date with the current format
Firstly, you need to check what is the data that is entered in the 'startDateAndTime' column,then you can convert that varchar into date format
If the data in 'startDateAndTime' column has data like '30-11-2017,07:30', you would then have to convert it into date:
SELECT to_date('30-11-2017,07:30','dd-mm-yyyy,hh:mm') from dual; --check this
--Your query:
SELECT to_date(startDateAndTime ,'dd-mm-yyyy,hh:mm') from timetrack;