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I'm trying to figure out how to write this block method in swift. I can't seem to get the closure syntax right:
[self.colorPickerView setDidChangeColorBlock:^(UIColor *color){
self.selectedColor.backgroundColor = self.colorPickerView.color;
}];
Thanks in advance!
What i tried:
self.colorPickerView.didChangeColorBlock({
(color: UIColor) in self.selectedColorView.backgroundColor = self.colorPickerView.color
})
Final Solution:
self.colorPickerView.didChangeColorBlock = {
(color: UIColor!) in
self.selectedColorView.backgroundColor = color
}
You probably need to use
self.colorPickerView.didChangeColorBlock = { ...
instead of
self.colorPickerView.didChangeColorBlock({ ...
Since didChangeColorBlock is a property, not a method.
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I want to have an awk function to compute the median of an array (may not be sorted).
median of column with awk
The above is a similar post but it is not the same as this one because the input on the above post is a sorted stream.
Could anybody show me the function to compute the median of an array?
I got the following solution. I am not sure if it would fail in a corner case. If it does, please let me know.
function median(x, n, d) {
n = asort(x, d, "#val_num_asc")
if(n == 0) return "NA"
if(n%2) {
return d[(n+1)/2]
} else {
return (d[n/2] + d[n/2+1])/2
}
}
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Why can't you specify a val or var type in for loop's in Kotlin. For example, I would like to be able to do
for (var i in 0...data.size - 1) {
for (j in 0..bytes.size - 1) {
bytes[j] = data[i++]//cant do i++ in current kotlin because "i" is val
}
//do stuff
}
But instead I have to do this
var i = 0
while (i < data.size) {
for (j in 0..bytes.size - 1) {
bytes[j] = data[i++]
}
//do stuff
}
Your example is slightly different from Java's typical for(int i=0;i<data.size;i++) example.
In the Kotlin version 'i' is actually an element of the range in which case i++ doesn't make sense. It just so happens that the range you have is a list of indexes.
The way you are using the Kotlin for loop is much closer to Java's foreach loop for(i : indexes).
I think that because Kotlin is a language that tries to make easy to respect most of the functional programming concepts, it prefers to prohibit that sort of behaviour. Also, a possible problem that your initial code could encount is an OutOfBoundException in the situation where the bytes array has more elements than the data array.
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Can anyone help me to understand that Is 2^(n^2 )=Θ(2^(n^3 )) ? it will be great if also provide the proof for this. As per my view this does not need to be equal.
The given assumption is not true:
First of all, 2^(n^2) is a function and Theta(2^(n^3)) is a set of functions, so it would be correct to say that 2^(n^2) ∈ Theta(2^(n^3)). The = is just a common abuse of notation, but it actually means ∈. To find out whether that statement is true, solve the following limit:
lim (n->infinity) of (2^(n^2)) / (2^(n^3))
If the result is 0 or infinite then the function does not belong to that particular Theta class. If it is some other value, it does belong to that class.
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Found this bit of code...
if(fabs([tempPlacemark getCoordinate].latitude-latitude) < latDelta && fabs([tempPlacemark getCoordinate].longitude-longitude)<longDelta )
...
refers to this in Math.h:
extern float fabsf(float);
extern double fabs(double);
extern long double fabsl(long double);
So what am I looking at?
double fabs( double ) - returns the absolute value of the argument
NSLog(#"res: %.f", fabs(10)); //result 10
NSLog(#"res: %.f", fabs(-10)); //result 10
found here.
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int RandomSource_next(int bits, double* seed) {
*seed = (((long long) *seed * 0x5DEECE66DLL) + 0xBLL) & ((1LL << 48) - 1);
return (int)((signed long long) *seed >> (48 - bits));
}
I think it got something to do with the address.
Most probably you are passing incorrect address as seed. Maybe you're passing not an address but a value?
The following should work
double seed = 0;
RandomSource_next(48, &seed);
The following should crash
RandomSource_next(48, 0);