I am including a SQLFiddle to show as an example of where I am currently at. In the example image you can see that simply grouping you get up to two lines per user depending on their status and how many of those statuses they have.
http://sqlfiddle.com/#!3/9aa649/2
The way I want it to come out is to look like the image below. Having a single line per user with two totaling columns one for Fail Total and one for Pass Total. I have been able to come close but since BOB only has Fails and not Passes this query leaves BOB out of the results. which I want to show BOB as well with his 6 Fail and 0 Pass
select a.PersonID,a.Name,a.Totals as FailTotal,b.Totals as PassTotals from (
select PersonID,Name,Status, COUNT(*) as Totals from UserReport
where Status = 'Fail'
group by PersonID,Name,Status) a
join
(
select PersonID,Name,Status, COUNT(*) as Totals from UserReport
where Status = 'Pass'
group by PersonID,Name,Status) b
on a.PersonID=b.PersonID
The below picture is what I want it to look like. Here is another SQL Fiddle that shows the above query in action
http://sqlfiddle.com/#!3/9aa649/13
Use conditional aggregation if the number of values for status column is fixed.
Fiddle
select PersonID,Name,
sum(case when "status" = 'Fail' then 1 else 0 end) as failedtotal,
sum(case when "status" = 'Pass' then 1 else 0 end) as passedtotals
from UserReport
group by PersonID,Name
Use conditional aggregation:
select PersonID, Name,
sum(case when Status = 'Fail' then 1 else 0 end) as FailedTotal,
sum(case when Status = 'Pass' then 1 else 0 end) as PassedTotal
from UserReport
group by PersonID, Name;
With conditional aggregation:
select PersonID,
Name,
sum(case when Status = 'Fail' then 1 end) as Failed,
sum(case when Status = 'Passed' then 1 end) as Passed
from UserReport
group by PersonID, Name
Related
I am trying to create a new table by using the dataset in the link below. The return I want to have is like the picture below. Could someone please help?
http://sqlfiddle.com/#!18/766e3/2
You can use conditional aggregation:
SELECT Employeeid,
SUM(CASE WHEN BusinessUniteID = 1 then Scores END) as score_1,
SUM(CASE WHEN BusinessUniteID = 2 then Scores END) as score_2,
SUM(CASE WHEN BusinessUniteID = 3 then Scores END) as score_3
FROM t_d
GROUP BY EmployeeId;
This assumes that you know what all the business unit ids are.
Here is a db<>fiddle.
I want to apply a simple SUM CASE WHEN to a table I have created from CSV (in DB Browser for SQLite). At the moment I have the below code:
Select user_id,
CASE Overall_Result
WHEN 'Fail' then 0
WHEN 'Pass' then 1 else 0
END as "Case When"
from NewTable
This code gives me:
Image
However, now I want to amend the above code so that it SUMS the values in the created CASE WHEN column for every particular user_id. As you can see in e.g. row 1 and 2 of the image, we have the same user_id and the corresponding values in the second column. I want to combine these user_id's so there is just one instance of each in column 1 and then have the SUM of all the corresponding values for this user_id in the second column. GROUP BY doesn't seem to do this..
Do you just want aggregation?
select user_id,
SUM(CASE Overall_Result WHEN 'Fail' then 0 WHEN 'Pass' then 1 else 0
END) as sum_value
from NewTable
group by user_id;
Or, if you just want the number of passes, you can use the shorthand:
SUM(Overall_Result = 'Pass')
just add the sum() and the related group by eg:
Select user_id,
sum( CASE Overall_Result
WHEN 'Fail' then 0
WHEN 'Pass' then 1 else 0
END ) as "Case When"
from NewTable
group by user_id
I have a table STATUSES which contain columns NAME and ACTIVE_FLAG.The column value of NAME may have new, pending, cancel. I want to generate a new output for the count of each NAME with ACTIVE_FLAG=Y
By thinking to use EXISTS to select records for single NAME,
SELECT COUNT(*) AS PENDING
FROM STATUSES
WHERE EXISTS (select NAME from STATUSES where NAME='Pending' and ACTIVE_FLAG = 'Y')
Anyway if I can join other statuses count in a single SQL?
Seems like count and group by
SELECT
name
, count(*)
FROM statuses
WHERE active_flag = 'Y'
GROUP BY name
You can use something like this as i don't see any need to use EXISTS :
SELECT sum(case when name='Pending' then 1 else 0 end) AS PENDING,
sum(case when name='new' then 1 else 0 end) AS NEW,
sum(case when name='cancel' then 1 else 0 end) AS CANCEL
FROM STATUSES
WHERE ACTIVE_FLAG = 'Y'
SQL HERE
I am having trouble formulating a query to get the desired output.
This query involves one table and two columns.
First column bld_stat has 4 different values Private, public, Public-Abandoned, Private-Abandoned the other column bld_type, single_flr, multi_flr, trailer, Whs.
I need to get results that look like this:
So far I can get the first two columns but after that I have not been able to logically get a query to work
SELECT bld_stat, COUNT(grade) AS single_flr
FROM (SELECT bld_stat,bld_type
FROM bld_inventory WHERE bld_type = 'single_flr') AS grade
GROUP BY bld_stat,bld_type,grade
The term you are going for is pivoting. I think this should work...no need for the subquery, and I've changed your group by to only bld_stat
SELECT bld_stat,
sum(case when bld_type = 'singl_flr' then 1 else 0 end) AS single_flr,
sum(case when bld_type = 'multi_flr' then 1 else 0 end) AS multi_flr,
sum(case when bld_type = 'trailer' then 1 else 0 end) AS trailer,
sum(case when bld_type = 'whs' then 1 else 0 end) AS WHS
FROM bld_inventory
GROUP BY bld_stat
I've a table with NAMES and STATUS with C(completed) and N(not completed) status. I want check how many tasks are not completed for each name. I tried the following code and it is returning all '0' values:
select name, (select count(status) from alteon where status= 'n') / (select count(status) from alteon) from alteon group by name;
I'm expecting the result as not completed / total assigned where total assigned = complete+not completed.
as mentioned earlier, I'm getting value as '0' beside each employee name.
I think the following query does what you want:
select name,
sum(case when status = 'n' then 1 else 0 end) as n_status,
avg(case when status = 'n' then 1.0 else 0 end) as n_status_ratio
from alteon;
Here is the query which gives the result as you explained above.
select count(status)as Total_assigned,
sum(IF(status='n', 1, 0)) as Not_completed,name
from alteon group by name ;
Here is the sqlfiddle
You don't have to use multiple select statements. Use CASE to count the incomplete tasks.
select name, count(case when status = 'n' then 1 else null end)/count(status)
from alteon
group by name;
sqlfiddle.