TABLE PEDIDO
id_name | ID_cabimento | ID_direction
1 | 4 | 5
2 | 3 | 6
3 | 4 | 5
TABLE USER
id_name | name
1 | João
2 | Maria
3 | António
4 | Manuel
I WANT FOR RESULT
name | cabimento | direction
João | Manuel | Tozé
Maria | António | Joaquim
António | Manuel | Tozé
...
I tried UNION and JOIN but did not get the desired result... because I only can decode 1 ID.
you can join n times on same table, just using n aliases
select n.name as name, c.name as cabimento, d.name as direction
from pedido p
inner join user n on p.id_name = n.id_name
inner join user c on p.id_name = c.id_cabimento
inner join user d on p.id_name = d.id_direction
Related
I'm trying to join my users table with my jobs table based on a mapping table users_jobs:
Here is what the users table looks like:
users
|--------|------------------|
| id | name |
|--------|----------------- |
| 1 | Ozzy Osbourne |
| 2 | Lemmy Kilmister |
| 3 | Ronnie James Dio |
| 4 | Jimmy Page |
|---------------------------|
jobs table looks like this:
|--------|-----------------|
| id | title |
|--------|-----------------|
| 1 | Singer |
| 2 | Guitar Player |
|--------------------------|
And users_jobs table looks like this:
|--------|-------------|-------------|---------------|-------------|
| id | user_id | job_id | column3 | column4 |
|--------|-------------|-------------|---------------|-------------|
| 1 | 1 | 1 | 0 | 1 |
| 2 | 2 | 1 | 1 | 0 |
| 3 | 3 | 1 | 0 | 1 |
| 4 | 4 | 2 | 1 | 0 |
|----------------------|-------------|---------------|-------------|
For example, let's say the ozzy does a query.
Here is what should expect:
|--------|------------------|------------|--------- |
| id | name | column3 | column4 |
|--------|----------------- |------------|----------|
| 1 | Ozzy Osbourne | 0 | 1 |
| 2 | Lemmy Kilmister | 1 | 0 |
| 3 | Ronnie James Dio | 0 | 1 |
|---------------------------|------------|----------|
Basically, he can only see the job in which he is registered (role) and the users included.
I tried to do this:
SELECT u1.*, uj1.colum3, uj1.column4
FROM users AS u1
JOIN users_jobs AS uj1 ON uj1.user_id = 1
JOIN jobs AS j1 ON j1.id = up1.job_id
WHERE uj1.job_id = 1
Any help would be great!
Looks like you need INNER JOIN Try this :
select u.id, u.column3 , u.column4 from users u
inner join user_jobs uj on u.id=uj.user_id
inner join jobs j on j.id=uj.job_id
where uj.job_id=1;
If you need by certain user_id
select u.id, u.column3 , u.column4 from users u
inner join user_jobs uj on u.id=uj.user_id
inner join jobs j on j.id=uj.job_id
where uj.job_id=1
and u.id=1;
I found a solution.
Using #stackFan approach adding an EXISTS clause to make sure that the user is in.
SELECT u.id, u.column3 , u.column4
FROM users u
INNER JOIN user_jobs uj on u.id = uj.user_id
INNER JOIN jobs j on j.id = uj.job_id
WHERE uj.job_id = <job-ID>
AND
EXISTS (
SELECT *
FROM users_jobs AS uj
WHERE uj.job_id = <job-ID>
AND uj.user_id = <user-ID>
);
Try LEFT JOIN. It will display all users, whether they have job or not.
SELECT u.id, u.name, uj.colum3, uj.column4
FROM users AS u
LEFT JOIN users_jobs uj ON uj.user_id = u.id
LEFT JOIN jobs j ON j.id = uj.job_id
Hie
It might be unclear my query in the title,Let me clear you in the description.
I have 2 tables in the DB with name of 'ABC' and 'XYZ'.
ABC table
| ID | name | phone | gender |
1 | dave | 23423 | Male
2 | rayman | 987887 | female
3 | shawn | 6237267 | male
XYZ table
| ID | user-id | blood-group | rh-factor |
1 | 3 | AB | +
2 | 1 |
B | -
As you seen above there are two table, now I want result that user whose gender is Male, blood-group is B and rh-factor is negative.
but output should be
| ID | name | phone | gender |
1 | dave | 23423 | Male
hope you understand what I mean.I don't know there should be user GROUP BY or what.
thanks in advance.
SELECT a.* FROM ABC a JOIN XYZ b ON a.ID=b.ID
WHERE b.Bloodgroup='B' AND a.gender='Male' and b.rh_factor='-'
Try this!..
select abc.id,abc.name,abc.phone,abc.gender from abc inner join xyz
on abc.id = xyz.user-id where abc.gender = 'male' and xyz.blood-group = 'b' and xyz.rh-factor='-'
Regards.
SK
You can simply use INNER JOIN :
SELECT a.* FROM ABC a INNER JOIN XYZ b ON a.ID = b.`user-id`
WHERE b.bood_group = 'B' and b.rh-factor = '-'
Use backtick(`) if your column has hyphen in it like it in your user-id
Hopefully this will be an easy question!
I have two tables, a 'client(s)' table and an individual 'names' table. The basis is that a client can have one or two(max) names. I structured them like this so that each 'name' can have a different title. The tables are:
clients
+------------+-------------+------------+
| clientID | nameID1 | nameID2 |
+------------+-------------+------------+
| 1 | 1 | 2 |
| 2 | 3 | |
| 3 | 4 | |
+------------+-------------+------------+
names
+------------+-------------+------------+------------+
| nameID | surname | initials | titleID |
+------------+-------------+------------+------------+
| 1 | Banks | P | 1 |
| 2 | Smith | W | 2 |
| 3 | Wilson | BT | 2 |
| 4 | Jefferson | JP | 3 |
+------------+-------------+------------+------------+
Where titleID is retrieved from...
titles
+------------+-------------+
| titleID | titleName |
+------------+-------------+
| 1 | Mr |
| 2 | Mrs |
| 3 | Miss |
+------------+-------------+
So for instance clientID = 1 is Mr P Banks '&' Mrs W Smith
The problem is I'm not familiar with querying to get that answer above.
I cannot try:
SELECT
clientID, names.surname, names.initials, titleName
FROM clients, names, titles
WHERE titleID = titleID AND
NameID1 = nameID AND
NameID2 = nameID
How do I correctly join the tables in a query to find, e.g.,
clientID 1 = Mr P Banks '&' Mrs W Smith
You need to join to the Names (and Titles) table twice, once for nameID1, and once for nameID2. I've assumed that the client must have at least one name hence nameID1 is INNER JOIN, and since namedID2 is optional (nullable) it is LEFT OUTER JOIN.
SELECT c.clientID, n1.surname, n1.initials, t1.titleName, n2.surname, n2.initials, t2.titleName
FROM clients c
INNER JOIN names n1 ON nameID1 = n1.nameID
INNER JOIN titles t1 ON n1.titleID = t1.titleID
LEFT OUTER JOIN names n2 ON nameID2 = n2.nameID
INNER JOIN titles t2 ON n2.titleID = t2.titleID
I have two tables i.e.
Users
uid | firstname
1 | John
2 | Bob
3 | Paul
4 | Peter
Calls
cid | assigned_to | caller_id
1 | 2 | 1
2 | 1 | 3
3 | 2 | 4
4 | 4 | 2
assigned_to and caller_id are just the uid in users.
I just want to display the results of each call:
call_id | username(assigned_to) | username(caller_id)
How can I do this in SQL?
Thanks,
Try this:
select
cid as call_id,
A.username, -- assingned to
B.username -- caller id
from calls
left join users A on calls.assigned_to = A.uid
left join users B on calls.caller_id = B.uid
I have three tables
Prospect -- holds prospect information
id
name
projectID
Sample data for Prospect
id | name | projectID
1 | p1 | 1
2 | p2 | 1
3 | p3 | 1
4 | p4 | 2
5 | p5 | 2
6 | p6 | 2
Conjoint -- holds conjoint information
id
title
projectID
Sample data
id | title | projectID
1 | color | 1
2 | size | 1
3 | qual | 1
4 | color | 2
5 | price | 2
6 | weight | 2
There is an associative table that holds the conjoint values for the prospects:
ConjointProspect
id
prospectID
conjointID
value
Sample Data
id | prospectID | conjointID | value
1 | 1 | 1 | 20
2 | 1 | 2 | 30
3 | 1 | 3 | 50
4 | 2 | 1 | 10
5 | 2 | 3 | 40
There are one or more prospects and one or more conjoints in their respective tables. A prospect may or may not have a value for each conjoint.
I'd like to have an SQL statement that will extract all conjoint values for each prospect of a given project, displaying NULL where there is no value for a value that is not present in the ConjointProspect table for a given conjoint and prospect.
Something along the lines of this for projectID = 1
prospectID | conjoint ID | value
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
2 | 1 | 10
2 | 2 | NULL
2 | 3 | 40
3 | 1 | NULL
3 | 2 | NULL
3 | 3 | NULL
I've tried using an inner join on the prospect and conjoint tables and then a left join on the ConjointProspect, but somewhere I'm getting a cartesian products for prospect/conjoint pairs that don't make any sense (to me)
SELECT p.id, p.name, c.id, c.title, cp.value
FROM prospect p
INNER JOIN conjoint c ON p.projectID = c.projectid
LEFT JOIN conjointProspect cp ON cp.prospectID = p.id
WHERE p.projectID = 2
ORDER BY p.id, c.id
prospectID | conjoint ID | value
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
2 | 1 | 10
2 | 2 | 40
2 | 1 | 10
2 | 2 | 40
2 | 1 | 10
2 | 2 | 40
3 | 1 | NULL
3 | 2 | NULL
3 | 3 | NULL
Guidance is very much appreciated!!
Then this will work for you... Prejoin a Cartesian against all prospects and elements within that project via a select as your first FROM table. Then, left join to the conjoinprospect. You can obviously change / eliminate certain columns from result, but at least all is there, in the join you want with exact results you are expecting...
SELECT
PJ.*,
CJP.Value
FROM
( SELECT
P.ID ProspectID,
P.Name,
P.ProjectID,
CJ.Title,
CJ.ID ConJointID
FROM
Prospect P,
ConJoint CJ
where
P.ProjectID = 1
AND P.ProjectID = CJ.ProjectID
ORDER BY
1, 4
) PJ
LEFT JOIN conjointProspect cjp
ON PJ.ProspectID = cjp.prospectID
AND PJ.ConjointID = cjp.conjointid
ORDER BY
PJ.ProspectID,
PJ.ConJointID
Your cartesian product is a result of joining by project Id - in your sample data there are 3 prospects with a project id of 1 and 3 conjoints with a project id of 1. Joining based on project id should then result in 9 rows of data, which is what you're getting. It looks like you really need to join via the conjointprospects table as that it what holds the mapping between prospects and conjoint.
What if you try something like:
SELECT p.id, p.name, c.id, c.title, cp.value
FROM prospect p
LEFT JOIN conjointProspect cp ON cp.prospectID = p.id
RIGHT JOIN conjoint c ON cp.conjointID = c.id
WHERE p.projectID = 2
ORDER BY p.id, c.id
Not sure if that will work, but it seems like conjointprospects needs to be at the center of your join in order to correctly map prospects to conjoints.