Get Week Before Last - sql

Hi I am trying to pull data which will excluded the previous 2 weeks and include the 2 weeks beofre that.
so for example if today is the 31st of the month i want to exclude all data between the 15th and 31st and want to see only the 1st to the 15th
AND E.EventCreatedDateD between DATEADD(day,-14,GETDATE()) AND DATEADD(day,-31,GETDATE())

You are getting 0 values from your statement because the dates are backwards. Put the earlier date first:
AND E.EventCreatedDateD between DATEADD(day, -31, GETDATE()) AND DATEADD(day, -14, GETDATE())
The order of the expressions for the between is important. The lower value always needs to be first and the higher value second.

Related

DATEADD to return data in the last 3 months but I want full month of data

So my query aims to grab all data in the last 3 months, but only returns data when it is a full month.
I have tried:
WHERE Created_Date > DATEADD(MONTH, -3, GETDATE())
or
WHERE Created_Date > DATEADD(DAY, -90, GETDATE())
Both ways return the data in the last 3 months starting from current date. But the thing is, since my query wants to get aggregated data, so if today is 8th Aug, 3 months dating back means May has not got the full month of data (from 1st to 31st), so the aggregated data is not fully reported in the results. Does this make sense?
Is there any other way to return the full month data?
I know that we can use #startOfCurrentMonth like in here but this is 3 months we are aiming to get.
To get the days of the current month plus three full months back, simply subtract four months and get that month's last day. Then take any dates after that day.
WHERE created_date > EOMONTH(DATEADD(MONTH, -4, GETDATE()))
If created_date is a misnomer and contains datetimes instead of dates, add a day and include that:
WHERE created_date >= DATEADD(DAY, 1, EOMONTH(GETDATE(), -4)))

not getting previous month record using datepart in sybase

Using below depart syntax to fetch for previous month record, it is working fine till previous year,however it is giving 0 value in January month.How can we get pervious month with date part even if year is change ?
DATEPART(month(GETDATE()) -1
I understand that I used another type of DB, but I want to give a hint. I am using sql server 2019.
Firstly, you need to substitute date and only then take datepart from it.
Queries:
--dateadd -1 would subtract 1 from current month
--(Jan - 1 2022), would be December 2021
select datepart(month, dateadd(month, -1, getdate()))
--also date add covers internally the problem with 30,31 days.
--May always has 31 days, April 30. So -1 subtraction from 31th of May,would result in 30th of April.
select dateadd(month, -1, cast('2021-05-31 10:00:00' as datetime))

Report that updates yearly

I have created a report that is supposed to look at the number of baptisms at our church for the ministry year. The Ministry year runs from Aug 1 - July 31. I currently have the report set to tell me the names of anyone that has a baptism date greater than 8/1/2016. But I would need to change that year each year for it to report properly. so I wanted to use a Case statement to have it update each year, but i am getting an error message with this: (The error is in the where clause, so I didn't include the entire report)
WHERE (P.organization_id = 1) AND
((CandidateProcesses_BaptismDate68.datetime_value) between (
case
When datepart(month, getdate()) < 8 then ('8/1/'+ datepart(year, getdate()))
When datepart(month, getdate()) >7 then ('8/1/'+
datepart((year,getdate())-1))End) and Getdate())
Does anyone see why I am getting an error?
Thanks!
You are getting an error trying to add a string and a number. You could fix that using datename() rather than datepart(). But, I think this is a simpler approach:
WHERE (P.organization_id = 1) AND
year(dateadd(month, -7, CandidateProcesses_BaptismDate68.datetime_value)) = year(dateadd(month, -7, getdate()))
This subtract 7 months to get the "ministry year" and then compares that to the current date minus seven months. That is, it subtracts 7 months and then normalizes on the calendar year.
This is a bit more expensive than your version, because it cannot use an index on CandidateProcesses_BaptismDate68(datetime_value). However, I doubt the database of baptisms is so large that the query will take very long anyway. (If that is an issue, then your version can be made to work with some simple modifications.)

How to subtract one month from a Date Column

I know about Dateadd and datediff, but I cannot find any information how to use these functions on an actual date column rather than something like today's date with SQL Server.
Say I have the following Column
Dated
06/30/2015
07/31/2015
Now I want to add the following derived column that subtracts one month from every row in the Dated column.
Dated Subtracted
06/30/2015 05/31/2015
07/31/2015 06/30/2015
Thank you
The short answer: I suspect this is what you want:
dateadd(day, -datepart(day, Dated), Dated)
However, if you want "regular" subtract one month behavior in tandem with sticking to the end of month, having June 30 fall back to May 31 is slightly trickier. There's a discrepancy between the title or your question and the example where it appears you want the final day of month to stay anchored. It would be helpful for you to clarify this.
dateadd(month, -1, ...) doesn't handle that when the previous month has more days than the starting month although it works the other way around. If that's truly what you need I think this should handle it:
case
when datediff(month, Dated, dateadd(day, 1, Dated)) = 1
then dateadd(day, -datepart(day, Dated), Dated)
else dateadd(month, -1, Dated)
end
There's also a flavor of several date functions in that expression and a sense of how this date stuff can get complicated. The condition in the when looks to see if Dated is the last day of the month by checking that the following day is in a different calendar month. If so we extract the day of month and subtract that many days to jump back to the last day of the previous month. (Months start at one not zero. So for example, counting backward 17 days from the 17th lands in the month before.) Otherwise it uses regular dateadd(month, -1, ...) calculations to jump backward to the same day of month.
Of course if all your dates fall on the end of the month then this simple version will be adequate by itself because it always returns the last day of the previous month (regardless of where it falls in the starting month):
dateadd(day, -datepart(day, Dated), Dated) /* refer back to the top */
dateadd(day, -day(Dated), Dated) /* same thing */
And just for fun and practice with date expressions, another approach is that you could start on a known month with 31 days and calculate relative to that:
dateadd(month, datediff(month, '20151231', Dated) - 1, '20151231')
This finds the number of months between your date and a reference date. It works for all dates since it doesn't matter whether the difference is positive or negative. So then subtracting one from that difference and adding that many months to the reference point is the result you want.
People will come up with some pretty crazy stuff and I'm often amazed (for differing reasons) at some of the variations I see. chancrovsky's answer is a good example for closer examination:
dateadd(month, datediff(month, -1, Dated) - 1, -1)
It relies on the fact that date -1, when treated as implicitly converted to datetime, is the day before January 1, 1900, which does happen to be a month of 31 days as required. (Note that the - 1 in the middle is regular arithmetic and not a date value.) I think most people would advise you to be careful with that one as I'm not sure that it is guaranteed to be portable when Microsoft deprecates features in the future.
Why don't you just get the last day of the previous month? If this solve your problem, here's the sql server syntax, just replace the variable #yourDate with your column name.
DECLARE #yourDate DATE = '20160229'
select DATEADD(MONTH, DATEDIFF(MONTH, -1, #yourDate)-1, -1)
This also works if you're looking to find dates exactly 6 months behind.
Example:
DATEADD(DAY, DATEDIFF(DAY, -1, dates)-184, -31)

I want to find first day and any other in a month in SQL query

I want to find first day month of month and also like 3rd day or 5th day ,15th day or any day of the month .So how to find through query.I know how to find first day and last day of month.Mainy I want find other days.
For those of you following along who may not know how to get the First Day of the month in SQL Server you can do so with something like this. This will also give you the 5th, 10th or whatever you need.
DECLARE #FirstDay DATETIME
SET #FirstDay = (DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE()) - 1, -1) + 1)
SELECT GETDATE() AS CurrentDay
, #FirstDay AS FirstDay
, DATEADD(d, 10, #FirstDay-1) AS TenthDay
The -1 after the #FirstDay in the DateAdd is because the DateAdd will add the numbers of days onto the firstday, which will give you the 11th in that example. Of course you could just add one less day to make it work without the -1 but I prefer including it. Suit yourself.
If you know how to find the first day of a month, you can add the 2-day, the 4-day or the 14-day interval to the first day of the month to get, respectively, the 3rd, the 5th or the 15th day of the month.
Similarly you can get any day of the month by simply adding the proper number of days.
Different RDBMSs may offer different syntax to achieve the goal. Assuming #MonthBeginning to be a date or datetime value representing the first day of a month, here's how you can get, for example, the 5th day of the same month in Microsoft SQL Server:
SELECT DATEADD(day, 4, #MonthBeginning) AS FifthDay
Again, it may not be the way you should do that if your RDBMS is not MS SQL Server.