MDX Rank of Dimension unioned with itself - mdx

I am trying to list the row numbers for a dimension unioned with itself, however I continue to get duplicate row numbers instead of a unique one for each row.
For example, I am trying to list the days of the week (Sunday - Saturday) twice such that I have rows 1-14. I'm getting repeating row numbers since i'm using the same dimension in my union (both instances of Monday = 1 instead of 1 and 8).
How do I get unique row numbers?
Thanks in advance
WITH
MEMBER [Measures].[Row Number] AS
Rank(
StrToTuple(
"( " +
Generate (
Head ( Axis(0),
Axis(1).Item(0).Count
) AS RN,
"Axis(1).Item(0).Item(" +
CStr(RN.CurrentOrdinal -1) +
").Hierarchy.CurrentMember",
","
) + ")"
),
Axis(1)
)
SET [AllMembers2] AS
UNION([Date].[Day Name].ALLmembers , [Date].[Day Name].ALLMembers, ALL)
select ([Measures].[Row Number]) on columns
,[AllMembers2] on rows
from [Adventure Works]

Related

Number or Results and WITH MEMBER Calculation interacting weird

In our MDX Queries, we use a template like the following WITH MEMBER . SELECT SUBSET . FROM (SELECT . FROM .) a lot.
What this particular query should do (and does!) is list all product variants matching a filter, and give the sales amount for it for a month in time. On the same row, we have the sales total of all variants of this product.
We need only a subset of the result (for paging), and the results need to ordered to allow paging of course. Then there is a non empty, so only product variants that were sold in the time period qualify.
This works just fine. Paging also works: putting 30, 60, 90 for Start in SUBSET is gives the correct results.
However, if I put a 1 as Count (SUBSET(..., x, 1)) the result of the "Price all" goes to (null) for each and any row I select with x. If I return two or more rows it works just fine, and all rows have their correct values.
Two results and the correct value in the rightmost column (in case you are wondering how the total of all variants, 67, can be lower than the sales of one particular variant (280): I picked a bad example - there was a return (so a negative sale) for another variant of this product, for 213. The 67 is correct and desired!)
One Row and a (null) result
I do not understand how or why the SUBSET count would interfere with the Tuple I select in the WITH MEMBER. If it does it for 30 rows at a time, why not for one?
*edit
I just tried, what would happen if I filter in a way that only one result matches (and SUBSET paging is set to "working values" of 0, 30): The same as in the 2nd screenshot, for one result row the WITH MEMBER evaluates to (null).
So it is not that SUBSET is the problem, but more general: When there is only one result row!
Could this be a bug in our SQL Server Version? It is SQL 2012 with SP4 and all latest security patches.
WITH
MEMBER [DIM Date].[HI Year_Month_Day].[CURRENT_MONTH] AS
[DIM Date].[HI Year_Month_Day].&[20201215].Parent /* Select Month of December */
MEMBER [MEASURES].[Price all] AS (
(
[DIM Products].[HI Products].Currentmember.Parent
, [DIM Products].[HI Subproduct].[Total]
)
, [MEASURES].[Price]
), FORMAT_STRING = '#,0' /* Get the parent product total next to every subproduct */
SELECT {
([DIM Datum].[HI Year_Month_Day].[CURRENT_MONTH], [MEASURES].[Price])
, ([DIM Datum].[HI Year_Month_Day].[CURRENT_MONTH], [MEASURES].[Price All])
} ON COLUMNS
, {
SUBSET(
ORDER(
NONEMPTY(
([DIM Products].[HI Produt Subproduct].[Subproduct])
, {([DIM Date].[HI Year_Month_Day].[CURRENT_MONTH], [MEASURES].[Price])}
)
, ([DIM Date].[HI Year_Month_Day].[CURRENT_MONTH], [MEASURES].[Price])
, BDESC
)
, 0
, 30
)
} ON ROWS
FROM (
SELECT
{[DIM StoreLocation].[HI Country].[Country].&[US]}
* {[DIM Productgroup].[HI Productgroup].[Productgroup].&[Bikes]}
ON COLUMNS
FROM [Cube]
)

Return 'n' rows from MDX output

How to filter MDX output for first 'n' rows and then loop over the next 'n' rows and so on using following example.
SELECT
{ [Measures1].members, [Measures2].members } ON COLUMNS,
{ [Date].members } ON ROWS
FROM [cube]
I'm trying this because I would like to loop over every 'n' rows of the MDX output and export the result to excel.
The original query returns very large number of records. That is the reason I'm planning to loop over the records.
You can do it like this: first, just take top N (lets say top 5 members), after that take top 10 members except top five. After that take top 15 members except top 10, and so on...
Here is the formula for the first 5, ordered by [SomeAmount], which is one of the measures from the cube
SELECT
{ [Measures].[SomeAmount] } ON COLUMNS,
EXCEPT(TopCount([Date].members, 5,[Measures].[SomeAmount] ),TopCount([Date].members, 0,[Measures].[SomeAmount] )) ON ROWS
FROM [cube]
and for the next five (first five are skipped):
SELECT
{ [Measures].[SomeAmount] } ON COLUMNS,
EXCEPT(TopCount([Date].members, 10,[Measures].[SomeAmount] ),TopCount([Date].members, 5,[Measures].[SomeAmount] )) ON ROWS
FROM [cube]
And so on...
If you have AdventureWorks cube you can try this query there:
SELECT
{ [Measures].[Internet Order Count] } ON COLUMNS,
EXCEPT(TopCount([Date].[Calendar].members, 10, [Measures].[Internet Order Count]),
TopCount([Date].[Calendar].members, 5,[Measures].[Internet Order Count] )) ON ROWS
FROM [Adventure Works]
And also, for the example from your comment where you have cross join:
SELECT
{Department.members} on COLUMNS,
EXCEPT(TopCount({[Product].[Status].members}*{Date.[Calendar].members}, 10),
TopCount({[Product].[Status].members}*{Date.[Calendar].members}, 5)) on ROWS
FROM [Adventure Works]
You can try this on Adventure Works also.
And also for your example from the comment:
SELECT EXCEPT(TopCount({dim1.members}*{dim2.members},10),
TopCount({dim1.members}*{dim2.members},5)) on ROWS,
{dim3.members} on COLUMNS
FROM [cube]
Hope it helps.

MDX - transpose rows to columns

I'm trying to display details from two rows into one using MDX. If I execute the MDX below, it returns 2 rows, one containing the 998 Key and one containing the 999 Key
SELECT NON EMPTY {
[Measures].[FactTableCount] } ON COLUMNS,
NON EMPTY { ([DimXXXX].[XXXXKey].[XXXXKey].ALLMEMBERS
* ([DimAAAA].[AAAAKey].[AAAAKey],{[DimBBBB].[Key].&[998],[DimBBBB].[Key].&[999]},[DimCCCC].[CCCCKey].[CCCCKey])
) } ON ROWS
FROM ( SELECT ( { [DimXXXX].[XXXXKey].&[MyValue] } ) ON COLUMNS
FROM [FactTable])
It returns something like this
(columns [DimXXXX].[XXXXKey], [DimAAAA].[AAAAKey], [DimBBBB].[Key], [DimCCCC].[CCCCKey], [Measures].[FactTableCount])
MyValue, MyAAAAKey1, 998, MyCCCCKey1, 1
MyValue, MyAAAAKey2, 999, MyCCCCKey2, 1
However I want to return one row like this
`(columns [DimXXXX].[Key], [DimAAAA].[AAAAKey], [DimAAAA].[AAAAKey], [DimBBBB].[Key], [DimBBBB].[Key], [DimCCCC].[CCCCKey], [DimCCCC].[CCCCKey], [Measures].[FactTableCount])
MyValue, MyAAAAKey1, MyAAAAKey2, 998, 999, MyCCCCKey1, MyCCCCKey2, 1
Among other things (such as using SETs, putting the 998/999 logic after the ROWS/COLUMNS, etc) I've tried
SELECT NON EMPTY {
[Measures].[FactTableCount] } ON COLUMNS,
NON EMPTY { ([DimXXXX].[XXXXKey].[XXXXKey].ALLMEMBERS
* ([DimAAAA].[AAAAKey].[Key],[DimBBBB].[Key].&[998],[DimCCCC].[CCCCKey].[CCCCKey])
* ([DimAAAA].[AAAAKey].[Key],[DimBBBB].[Key].&[999],[DimCCCC].[CCCCKey].[CCCCKey])
) } ON ROWS
FROM ( SELECT ( { [DimXXXX].[XXXXKey].&[MyValue] } ) ON COLUMNS
FROM [FactTable])
...however because the AAAAKey hierarchy is repeated I receive the error message "The AAAAKey hierarchy is used more than once in the Crossjoin function"
Is there a way to do do this ?
Based on your comment below I have a sample.Let me know if it works.
I think I can see what you're saying however the measures are one
thing, but the dimension values are another - say Record1:MyValue,
MyAAAAKey1, 998, MyCCCCKey1, 2 and Record2: MyValue, MyAAAAKey2, 999,
MyCCCCKey2, 5 - I would like to output MyValue, MyAAAAKey1,
MyAAAAKey2, 998, 999, MyCCCCKey1, MyCCCCKey2, 2, 5
So in the query below I am trying to simulate your problem.
select
{[Measures].[Internet Sales Amount]}
on columns,
non empty
([Customer].[City].[City],{[Product].[Category].&[1],[Product].[Category].&[3]},[Product].[Subcategory].[Subcategory])
on rows
from [Adventure Works]
Result
Now onw way is to take the changing values to columns, "{[Product].[Category].&1,[Product].[Category].&2}" in my case and "{[DimBBBB].[Key].&[998],[DimBBBB].[Key].&[999]}" in your case
select
{
({[Product].[Category].&[1],[Product].[Category].&[3]},[Measures].[Internet Sales Amount]),
([Product].[Category].defaultmember,[Measures].[Internet Order Quantity])
}
on columns,
non empty
([Customer].[City].[City],[Product].[Subcategory].[Subcategory])
on rows
from [Adventure Works]
Result:
Note how the values are only repeated for the relevent column. This does add an extra column but you rows are now half the orignal count.
Edit: to handle the requirement based on the comment
1st row of the grid would be Ballard, Bikes, Mountain Bikes, Road
Bikes. The 2nd: Ballard, Clothing, Caps, Gloves. The 3rd: Barstow,
Bikes, Road Bikes, null. I want to merge/list the actual dimension
values
So to achieve above we have two options. But in either case some manipulation on UI would be required.
1)First option
with member
measures.t
as (nonempty(existing([Customer].[City].currentmember,[Product].[Category].currentmember,[Product].[Subcategory].[Subcategory].members),[Measures].[Internet Sales Amount])).item(0).item(2).name
member measures.t1
as (nonempty(existing([Customer].[City].currentmember,[Product].[Category].currentmember,[Product].[Subcategory].[Subcategory].members),[Measures].[Internet Sales Amount])).item(1).item(2).name
select
{measures.t,measures.t1}
on columns,
nonempty(([Customer].[City].[City],{[Product].[Category].&[1],[Product].[Category].&[3]}),[Measures].[Internet Sales Amount])
on rows
from [Adventure Works]
2)The second option,
with member
measures.t1
as
[Customer].[City].currentmember.name
member measures.t2
as
[Product].[Category].currentmember.name
member measures.t3
as (nonempty(existing([Customer].[City].currentmember,[Product].[Category].currentmember,[Product].[Subcategory].[Subcategory].members),[Measures].[Internet Sales Amount])).item(0).item(2).name
member measures.t4
as (nonempty(existing([Customer].[City].currentmember,[Product].[Category].currentmember,[Product].[Subcategory].[Subcategory].members),[Measures].[Internet Sales Amount])).item(1).item(2).name
select
{measures.t1,measures.t2,measures.t3,measures.t4}
on columns,
nonempty(([Customer].[City].[City],{[Product].[Category].&[1],[Product].[Category].&[3]}),[Measures].[Internet Sales Amount])
on rows
from [Adventure Works]

MDX Query - Select Columns From Same Dimensions

I have a requirement displaying data from same dimension in more than 1 column. For eg. I want to show data Year and Month wise. In my dimension structure, Year and Month belongs to same hierarchy. When I run below query I get error. PFB the query.
Select NON EMPTY {[Measures].[Target Actual Value]} ON 0,
NON EMPTY {[Realization Date].[Hierarchy].[Year Name].Members *
[Realization Date].[Hierarchy].[Month Year]} ON 1
From [Cube_BCG_OLAP]
The error I get is Query (2, 12) The Hierarchy hierarchy is used more than once in the Crossjoin function. I am new to MDX queries. Please help in this regard. Thanks in advance.
Select NON EMPTY {[Measures].[Target Actual Value]} ON 0,
NON EMPTY {[Realization Date].[Hierarchy].[Year Name].Members ,
[Realization Date].[Hierarchy].[Month Year]} ON 1
From [Cube_BCG_OLAP]
Instead of CROSSJOIN have a set as above. In a set, you can put members from same hierarchy
I like Sourav's answer - but it will put the results in one column which is slightly different than the question.
In AdvWorks this is in one column:
SELECT
[State-Province].MEMBERS ON COLUMNS
,{
[Date].[Calendar].[Calendar Year].MEMBERS
,[Date].[Calendar].[Month].MEMBERS
} ON ROWS
FROM [Adventure Works];
It is possible to switch to two columns and use a cross join but you need to find out the details of your Date dimensions Attribute hierarchies (as opposed to User hierarchies):
SELECT
[State-Province].MEMBERS ON COLUMNS
,
[Calendar Year].[All Periods].Children
* [Month].MEMBERS ON ROWS
FROM [Adventure Works];
In your cube maybe something like this:
SELECT
NON EMPTY
{[Measures].[Target Actual Value]} ON 0
,NON EMPTY
[Year Name].MEMBERS
*
[Month Year].MEMBERS ON 1
FROM [Cube_BCG_OLAP];

Getting a count of users each day in Mondrian MDX

I'm trying to write a query to give me the total number of users for each customer per day.
Here is what I have so far, which for each customer/day combination is giving the total number of user dimension entries without splitting them up by customer/day.
WITH MEMBER [Measures].[MyUserCount]
AS COUNT(Descendants([User].CurrentMember, [User].[User Name]), INCLUDEEMPTY)
SELECT
NON EMPTY CrossJoin([Date].[Date].Members, [Customer].[Customer Name].Members) ON ROWS,
{[Measures].[MyUserCount]} on COLUMNS
FROM
[Users]
The problem with your calculated member is that [User].CurrentMember is set to the All member for every row tuple, and thus the count is the total. What you need is a way for the [Customer].CurrentMember and [Date].CurrentMember to effectively filter the [User] dimension.
You need to use a measure that makes sense, i.e. that will have a non-empty value for meaningful joins of the dimension members that you're interested in.
To find this out, you could start by running a query like this:
SELECT
NON EMPTY CrossJoin(
[User].[User Name].Members,
[Measures].[Some measuse]
) ON COLUMNS,
NON EMPTY CrossJoin(
[Date].[Date].Members,
[Customer].[Customer Name].Members
) ON ROWS
FROM [Project]
You would have selected Some measure adequately. The results of that query will be a lot of empty cells, but in a given row, the columns that do have a value correspond to the Users that are related to a given Customer x Date tuple (on the row). You want to count those columns for every row. COUNT and FILTER are what you need, then the query with the calculated member will be
WITH MEMBER [Measures].[User count] AS
COUNT(
FILTER(
[User].[User Name].Members,
NOT ISEMPTY([Measures].[Some measure])
)
)
SELECT
NON EMPTY {[Measures].[User count]} ON COLUMNS,
NON EMPTY CrossJoin(
[Date].[Date].Members,
[Customer].[Customer Name].Members
) ON ROWS
FROM [Users]
I am assuming a fair bit here, but with some experimentation you should be able to work it out.