I have a view I am creating and I want to group by an extracted date from a column that has a date and time. This is where I am....
SELECT
ClockCode AS MOnum, SUM(Actual_Hrs) AS Runtothours, TStamp
FROM
dbo.Raw_Booking
WHERE
(Actual_Hrs > 0) AND (ClockCode LIKE 'MO%')
AND (TStamp > CONVERT(DATETIME, '2013-01-01 00:00:00', 102))
GROUP BY
ClockCode, TStamp
so while I have it grouped by the TStamp column there is a record for each one based on the time... I am looking to get a total amount of run time for each order by date.
The TStamp column is formatted as:
2013-01-02 08:18:47.000
If you can change your schema, store it as a date to begin with. Otherwise, change your group by clause to something similar to...
GROUP BY CAST(TStamp AS DATE)
EDIT: Forgot you were in SQL 2005. You can still do something like the following, but keep in mind this should be considered an ugly, short-term, workaround. All the comments in this thread about redesigning are completely valid and should be pursued...
GROUP BY SUBSTRING(TStamp, 0, 11)
SELECT ClockCode AS MOnum
, SUM(Actual_Hrs) AS Runtothours
, TStampDate
FROM dbo.Raw_Booking
CROSS APPLY (
SELECT CONVERT(datetime, TStamp, 102) AS TStampDateTime
) AS CA1
CROSS APPLY (
SELECT DATEADD(day, DATEDIFF(day, 0, TStampDateTime), 0) AS TStampDate
) AS CA2
WHERE Actual_Hrs > 0
AND ClockCode LIKE 'MO%'
AND TStampDateTime > CONVERT(DATETIME, '2013-01-01 00:00:00', 102))
GROUP BY ClockCode
,TStampDate
Related
I'm trying to perform a query in SQL Server. I'm having trouble filtering the date. The output is always the same, the data doesn't get filter by date.
The date comes in the following format:
29-12-2020 16:38
31-12-2020 17:43
I tried to filter doing all the following but none worked out:
select
start_date
from table_1
where start_date between '01-01-2021 00:00:00' and '31-01-2021 00:00:00'
select
start_date
from table_1
where start_date between '01-01-2021 00:00' and '31-01-2021 00:00'
select
start_date
from table_1
where start_date between '01-01-2021' and '31-01-2021'
I also tried to cast it but I didn't have luck:
select
cast(start_date as date) as start_date
from table_1
where start_date between '2021-01-01' and '2021-01-31'
Can anyone help me?
Regards
You have a string. I strongly suggest making it a date/time of some sort. The following conversion works:
select convert(datetime, left(str, 10), 105) + convert(datetime, right(str, 5))
from (values ('29-12-2020 16:38')) v(str);
One operation is a computed column:
alter table table_1 start_date_dt as
( convert(datetime, left(start_date, 10), 105) + convert(datetime, right(start_date, 5)) )
Then you can use this value for your where clause. Or better yet. Fix the data! Don't store values in strings when there is an appropriate data type.
I have a small question about SQL Server: how to get the last 30 days information from this column from table1:
created_at
updated_at
2020-02-05T01:25:42Z
2020-02-05T01:25:42Z
2020-05-05T02:31:56Z
2020-05-05T02:31:56Z
With the above data, I would need something like day count within 30 days.
I have tried
SELECT * FROM table1
DATEDIFF(CAST(SUBSTR(updated_at,1,10)) AS VARCHAR,CURRENT_TIMESTAMP) BETWEEN 0 AND 30 ;
and
SELECT * FROM table1
WHERE updated_at BETWEEN DATETIME('now', '-30 days') AND DATETIME('now', 'localtime')
Would need your expertise to help me with this query
Thank you!
SELECT *
FROM (
SELECT otherColumns
, DATEADD(mi, DATEDIFF(mi, GETUTCDATE(), GETDATE()), updated_at) AS updated_at
FROM table1
) b
WHERE CAST(b.updated_at AS DATE) >= DATEADD(DAY,-30,GETDATE())
I think this will help you
If you want a count of updates by day for 30 (or so) days, then:
SELECT CONVERT(DATE, updated_at) as dte, COUNT(*)
FROM table1
WHERE updated_at >= DATEADD(DAY, -30, CONVERT(DATE, GETDATE()))
GROUP BY CONVERT(DATE, updated_at)
ORDER BY CONVERT(DATE, updated_at);
Note that SQLite date/time functions (which your code uses) are very peculiar to to SQLite. So are SQL Server's -- although I personally find them easier to remember.
I am banging my head against the desk here trying to work something out in SQL, I understand the logic and I can easily complete the task in Excel however where is the fun in that :)
The database in question as a WorkOrder table and I am selecting the following columns:
SELECT WorkOrderNumber,
WorkOrderDescription,
WorkOrderHistoryDescription,
RaisedDateTime,
FinishedDateTime
What I need I am trying to do is return all work orders raised within a given month which is easy enough:
WHERE RaisedDateTime >= CONVERT(DATETIME, '2014-12-01' ) and <= CONVERT(DATETIME, '2014-12-31' )
The kicker is I also want those return those records that were raised prior to but were closed in the given month, I tried the following which appeared to work:
WHERE ( RaisedDateTime >= CONVERT(DATETIME, '2014-12-01' ) AND RaisedDateTime <= CONVERT(DATETIME, '2014-12-31' ) )
OR ( FinishedDateTime >= CONVERT(DATETIME, '2014-12-01' ) AND FinishedDateTime <= CONVERT(DATETIME, '2014-12-31' ) AND RaisedDateTime < CONVERT(DATETIME, '2014-12-01' ) )
However when I inserted PreventativeMaintenanceID IS NULL after the statement above I found work orders that had a value in that column, if I just have the first line of the WHERE statement everything works fine.
Any ideas/pointers of where I might be going wrong? I was looking to see if I could use a CASE statement however I just couldn't get it to work.
It's hard to tell without knowing how exactly your full query looks but try grouping your criteria other than that line, and then add that line after the grouped criteria, like this:
SELECT WorkOrderNumber,
WorkOrderDescription,
WorkOrderHistoryDescription,
RaisedDateTime,
FinishedDateTime
from tbl
WHERE (
(RaisedDateTime between CONVERT(DATETIME, '2014-12-01') AND
CONVERT(DATETIME, '2014-12-31')) OR
(FinishedDateTime between CONVERT(DATETIME, '2014-12-01') AND
CONVERT(DATETIME, '2014-12-31') AND
RaisedDateTime < CONVERT(DATETIME, '2014-12-01'))
)
and PreventativeMaintenanceID IS NULL
Based on your description it sounds like an order of operations issue due to the OR
Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()
I have a question. I have a SQL Server 2008 table with a field column. I have for example the Following dates:
1/1/2001
5/5/2004
8/5/2009
10/7/2011
5/5/2012
1/13/2014
Id like to be able to show all dates >= the current date (7/29/2011) as well as largest table date that is < current date. In this example, the result would be all dates >= 8/5/2009.
Can someone help guide me please??
select max(date) [date] from table where date < getdate()
union
select date from table where date >= getdate()
If I understand correctly, you want to include the date prior to the current date. GETDATE() will get the current date (with time). If you're alright with that, then this should work. Otherwise, you may have to parse out just the date from GETDATE()
SELECT TheDate
FROM DateTable
WHERE TheDate >= (SELECT MAX(TheDate) FROM DateTable WHERE TheDate < GETDATE())
This gets all dates greater than or equal to the most recent date before the current date.
I am not entirely sure I understand, but this looks like a BETWEEN the relevant dates. Or is there something more I am missing?
Assuming your table is called DateTable and your field is called TheDate, do it like this:
SELECT TheDate
FROM DateTable
WHERE TheDate >= DATEADD(d, -2, GETDATE())
Good luck!
It depends on the SQL server you're using. In postgres, for example, you need something like
SELECT fields FROM table WHERE date_field >= CURRENT_DATE - 1
But other SQL servers have different ways to specify "yesterday"
SELECT d1.*
FROM dates d1
LEFT JOIN dates d2 ON d1.Date < d2.Date AND d2.Date < GETDATE()
WHERE d2.Date IS NULL
Explanation:
Select every date for which there does not exist a date that is both earlier than today and later than the one being inspected.
Lots of guessing here based on loose narrative and unknown data types.
DECLARE #t TABLE(d DATE);
INSERT #t SELECT '20010101'
UNION ALL SELECT '20040505'
UNION ALL SELECT '20090805'
UNION ALL SELECT '20111007'
UNION ALL SELECT '20120505'
UNION ALL SELECT '20140113';
DECLARE #now DATE = SYSDATETIME();
WITH t AS
(
SELECT d, rn = ROW_NUMBER() OVER (ORDER BY d)
FROM #t
)
SELECT t.d
FROM t LEFT OUTER JOIN t AS x
ON t.rn = x.rn - 1
WHERE COALESCE(x.d, #now) >= #now
ORDER BY t.d;