Have two tables say ABC and XYZ and contain one column which data will be unique across these table. Now I have id with me but don't know in which table this id belongs. Is it possible to fetch record in single query with that id from ABC or XYZ?
Thanks in advance.
Is it possible to fetch record in single query with that id from ABC
or XYZ?
Yes, you can use UNION(implicit distinct) or UNION ALL(with duplicate values) to get all id's from the two tables:
SELECT id FROM ABC
UNION ALL
SELECT id FROM XYZ
Related
I'm creating a new table using PostgreSQL, but I need to get a parameter from another table as an input.
This is the table I have (I called table_1):
id column_1
1 100
2 100
3 100
4 100
5 100
I want to create a new table, but only using ids that are higher than the highest id from the table above (table_1). Something like this:
insert into table_new
select id, column_1 from table_old
where id > (max(id) from table_1)
How can I do this? I tried searching, but I got to several posts like https://community.powerbi.com/t5/Desktop/M-Query-Create-a-table-using-input-from-another-table/td-p/209923, Take one table as input and output using another table BigQuery and sql query needs input from another table, which are not exactly what I need.
Just use where id > (select max(id) from table_1).
I have a DB with three tables.
"Campaign" table has a column "Campaign number" (e.g. value = 1)
"Payment" table has a column "user_id" (e.g. value = 134356)
"User_Source" table has a column "dump" which contains both the user id and campaign number: info_u134356_cpn_1 OR info_cpn_1_u134356
I need to divide the data from the combined values in user_source, so that I would be able to see user_id and their linked campaign number in one table, and then count how many users are attributed to each campaign.
I can't get my head around the way to split ths column, and whether there is a way to do s without spitting (e.g. somehow filtering).
I'm currently using DataGrip for this.
You can use regexp_match() in Postgres:
with sample (dump) as (
values
('info_cpn_1_u134356'),
('info_u456789_cpn_5')
)
select (regexp_match(dump, 'u([0-9]+)'))[1] as user_id,
(regexp_match(dump, 'cpn_([0-9]+)'))[1] as campaign
from sample;
returns:
user_id | campaign
--------+---------
134356 | 1
456789 | 5
Postgresql:
I have two tables 'abc' and 'xyz' in postgresql. Both tables have same 'id' columns which type is 'serial primary key;'.
abc table id column values are 1,2,3 and also xyz id column containing same values 1,2,3,4
I want to union both tables with 'union all' constraint. But I want to change 'xyz' id column values to next value of 'abc' id column last value as 1,2,3,4,5,6,7
select id from abc
union all
select id from xyz
|id|
1
2
3
1
2
3
4
my wanted resuls as
|id|
1
2
3
4
5
6
7
BETTER - Thanks to #CaiusJard
This should do it for you
select id FROM abc
UNION ALL select x.id + a.maxid FROM xyz x,
(SELECT MAX(id) as maxid from abc) a
ORDER BY id
For anyone who's doing something like this:
I had a similar problem to this, I had table A and table B which had two different serials. My solution was to create a new table C which was identical to table B except it had an "oldid" column, and the id column was set to use the same sequence as table A. I then inserted all the data from table B into table C (putting the id in the oldid field). Once I fixed the refernces to point to from the oldid to the (new)id I was able to drop the oldid column.
In my case I needed to fix the old relations, and needed it to remain unique in the future (but I don't care that the ids from table A HAVE to all be before those from table C). Depending on what your trying to accomplish, this approach may be useful.
If anyone is going to use this approach, strictly speaking, there should be a trigger to prevent someone from manually setting an id in one table to match another. You should also alter the sequence to be owned by NONE so it's not dropped with table A, if table A is ever dropped.
I have an SQL Server 2012 table with ID, First Name and Last name. The ID is unique per person but due to an error in the historical feed, different people were assigned the same id.
------------------------------
ID FirstName LastName
------------------------------
1 ABC M
1 ABC M
1 ABC M
1 ABC N
2 BCD S
3 CDE T
4 DEF T
4 DEG T
In this case, the people with ID’s 1 are different (their last name is clearly different) but they have the same ID. How do I query and get the result? The table in this case has millions of rows. If it was a smaller table, I would probably have queried all ID’s with a count > 1 and filtered them in an excel.
What I am trying to do is, get a list of all such ID's which have been assigned to two different users.
Any ideas or help would be very appreciated.
Edit: I dont think I framed the question very well.
There are two ID's which are present multiple time. 1 and 4. The rows with id 4 are identical. I dont want this in my result. The rows with ID 1, although the first name is same, the last name is different for 1 row. I want only those ID's whose ID is same but one of the first or last names is different.
I tried loading ID's which have multiple occurrences into a temp table and tried to compare it against the parent table albeit unsuccessfully. Any other ideas that I can try and implement?
SELECT
ID
FROM
<<Table>>
GROUP BY
ID
HAVING
COUNT(*) > 1;
SELECT *
FROM myTable
WHERE ID IN (
SELECT ID
FROM myTable
GROUP BY ID
HAVING MAX(LastName) <> MIN(LastName) OR MAX(FirstName) <> MIN(FirstName)
)
ORDER BY ID, LASTNAME
This is staight forward I believe:
I have a table with 30,000 rows. When I SELECT DISTINCT 'location' FROM myTable it returns 21,000 rows, about what I'd expect, but it only returns that one column.
What I want is to move those to a new table, but the whole row for each match.
My best guess is something like SELECT * from (SELECT DISTINCT 'location' FROM myTable) or something like that, but it says I have a vague syntax error.
Is there a good way to grab the rest of each DISTINCT row and move it to a new table all in one go?
SELECT * FROM myTable GROUP BY `location`
or if you want to move to another table
CREATE TABLE foo AS SELECT * FROM myTable GROUP BY `location`
Distinct means for the entire row returned. So you can simply use
SELECT DISTINCT * FROM myTable GROUP BY 'location'
Using Distinct on a single column doesn't make a lot of sense. Let's say I have the following simple set
-id- -location-
1 store
2 store
3 home
if there were some sort of query that returned all columns, but just distinct on location, which row would be returned? 1 or 2? Should it just pick one at random? Because of this, DISTINCT works for all columns in the result set returned.
Well, first you need to decide what you really want returned.
The problem is that, presumably, for some of the location values in your table there are different values in the other columns even when the location value is the same:
Location OtherCol StillOtherCol
Place1 1 Fred
Place1 89 Fred
Place1 1 Joe
In that case, which of the three rows do you want to select? When you talk about a DISTINCT Location, you're condensing those three rows of different data into a single row, there's no meaning to moving the original rows from the original table into a new table since those original rows no longer exist in your DISTINCT result set. (If all the other columns are always the same for a given Location, your problem is easier: Just SELECT DISTINCT * FROM YourTable).
If you don't care which values come from the other columns you can use a (bad, IMHO) MySQL extension to SQL and do:
SELECT * FROM YourTable GROUP BY Location
which will give a result set with one row per location and values for the other columns derived from the original data in an undefined fashion.
Multiple rows with identical values in all columns don't have any sense. OK - the question might be a way to correct exactly that situation.
Considering this table, with id being the PK:
kram=# select * from foba;
id | no | name
----+----+---------------
2 | 1 | a
3 | 1 | b
4 | 2 | c
5 | 2 | a,b,c,d,e,f,g
you may extract a sample for every single no (:=location) by grouping over that column, and selecting the row with minimum PK (for example):
SELECT * FROM foba WHERE id IN (SELECT min (id) FROM foba GROUP BY no);
id | no | name
----+----+------
2 | 1 | a
4 | 2 | c