I would like to build one sql query in that one of my filed of form should not contain common names (maintained list of words in separate table) and i am passing value of that filed as parameter and want to check that it shouldn't contain any common name from that table.
How can i achieve that using sql query?
Note : if common name is 'abc' and i am passing parameter as '!abc123' since it contains that word query should return false.
Thanks in advance.
Try something like (Untested Query):
SELECT CommonName
FROM CommonNamesTable
WHERE CommonName like '%NameToTest%'
OR CONTAINS(NameToTest, CommonName);
Basically you need the string match options:
Take a look at options of CONTAINS and read about Queries with full text search
Is this what you're looking for?
SELECT (COUNT(*) == 0) FROM tablewithcommonwords
WHERE wordfromform LIKE CONCAT('%', wordcolumnnfromcommonwordstable, '%');
Try this:
IF NOT EXISTS(SELECT word FROM CommonWord WHERE #yourparam
LIKE '%' + word + '%')
BEGIN
RETURN 1
END
ELSE
BEGIN
Return 0
END
This works if the #yourParam is contained in any word or name, what you do not want to use. It only returns 1 if it is not contained by any row in the table.
I worte this sentence only on this way (you can use a simple Exists instead of NOT Exists), because may you want to extend the functionality in the true part.
if exists (select * from reservedwords where #parameter like '%'+word + '%')
select 0
else
select 1
I would like to suggest that You have to use keypress Event in Your TextBox and then Handle your Code after Each character enter in your TextBox.
Related
I have one column that called 'message' and includes several data such as fund_no, detail, keywords. This column is in table called 'trackemails'.
I have another table, called 'sendemails' that has a column called 'Fund_no'.
I want to retrieve all data from 'trackemail' table that the column 'message' contains characters same as 'Fund_no' in 'trackemails' Table.
I think If I want to check the equality, I would write this code:
select
case when t.message=ts.fund_no then 1 else 0 end
from trackemails t, sendemails s
But, I do want something like below code:
select
case when t.message LIKE ts.fund_no then 1 else 0 end
from trackemails t, sendemails s
I would be appreciate any advice to how to do this:
SELECT *
FROM trackemails tr
INNER JOIN sendemail se on tr.Message like '%' + se.Fund_No + '%'
Dear Check SQL CHARINDEX() Function. This function finds a string in another string and returns int for the position they match. Like
SELECT CHARINDEX('ha','Elham')
-- Returns: 3
And as you need:
SELECT *
,(SELECT *
FROM sendemail
WHERE CHARINDEX(trackemails.Message,sendemail.Fund_No)>0 )
FROM trackemails
For more information, If you want something much better for greater purposes, you can use Fuzzy Lookup Component in SSDT SSIS. This Component gives you a new column in the output which shows the Percentages of similarity of two values in two columns.
I have a SQL procedure with this SQL:
select CenterExpensesID,sum(NISAmount) NISAmount
from ktrn10_fnCostCentersTransactions(#month_start_date,#todate,'BEI')
where AccountNumber like #like_account
group by CenterExpensesID
#like_account is a parameter which can get a pattern e.g. '18%'
Is it possible to make a pattern which shows all the records "not like '18%'"
the pattern '[^1][^8]%' is not the solution because it excludes also 19,58 etc..
No. If SQL Server supported regular expressions, this would be easy.
One thing you could do is to parse the expression. So, this does what you want:
where (accountNumber like #param and #param not like '^%') or
(accountNumber not like stuff(#param, 1, 1, '') and param like '^%')
You could then pass in the parameter as '18%' for like and '^18%' for not like.
Or, you could just use two parameters:
where accountNumber like #like_param and
accountNumber not like #notlike_param
The default values would be something like '%' for #like_param and '' for #notlike_param.
I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.
Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach
The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'
You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.
99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other
I have some data that will look like this:
05124110 LMY RET 2015
I need in SQL to return a row if there is LMY and RET it can be as one piece
LMY RET but maybe better to check for both separately in case the users add one extra blank.
select * from [table] where [column] like '%LMY%' and [column] like '%RET%'
Note that this will be case-insensitive, so 'lmy ret' will be returned as well. This will also return things that have "RET LMY"; I'm not sure if that's desired or not.
SELECT *
FROM yourTable
WHERE yourColumn LIKE '%LMY%RET%'
I'm writing some very simple search functionality for a list of FAQ's. I'm splitting the search string on a variety of characters, including spaces. Then performing a select along the lines of
SELECT *
FROM "faq"
WHERE
((LOWER("Question") LIKE '%what%'
OR LOWER("Question") LIKE '%is%'
OR LOWER("Question") LIKE '%a%'
OR LOWER("Question") LIKE '%duck%'))
I've had to edit this slightly as its generated by our data access layer but it should give you an idea of whats going on.
The problem is demonstrated well with the above query in that most questions are likely to have the words a or is in them, however I can not filter these out as acronyms may well be important for the searcher. What has been suggested is we order by the number of matching keywords. However I have been unable to find a way of doing this in SQL (we do not have time to create a simple search engine with an index of keywords etc). Does anyone know if there's a way of counting the number of LIKE matches in an SQL statement and ordering by that so that the questions with the most keywords appear at the top of the results?
I assume the list of matching keywords is being entered by the user and inserted into the query dynamically by the application, immediately prior to executing the query. If so, I suggest amending the query like so:
SELECT *
FROM "faq"
WHERE
((LOWER("Question") LIKE '%what%'
OR LOWER("Question") LIKE '%is%'
OR LOWER("Question") LIKE '%a%'
OR LOWER("Question") LIKE '%duck%'))
order by
case when LOWER("Question") LIKE '%what%' then 1 else 0 end +
case when LOWER("Question") LIKE '%is%' then 1 else 0 end +
case when LOWER("Question") LIKE '%a%' then 1 else 0 end +
case when LOWER("Question") LIKE '%duck%' then 1 else 0 end
descending;
This would even enable you to "weight" the importance of each selection term, assuming the user (or an algorithm) could assign a weighting to each term.
One caveat: if your query is being constructed dynamically, are you aware of the risk of SQL Insertion attacks?
You can write a function which counts the occurrences of one string in another like this:
CREATE OR REPLACE FUNCTION CountInString(text,text)
RETURNS integer AS $$
SELECT(Length($1) - Length(REPLACE($1, $2, ''))) / Length($2) ;
$$ LANGUAGE SQL IMMUTABLE;
And use it in the select: select CountInString("Question",' what ') from "faq".