My requirement is like. I have 3 column & 1 row.
Column A -> Value a
Column B -> Value b
Column C -> Value 123
I have to split value in column C and get 3 rows from that, and also copy values from another columns. I have to get 3 rows and it should be like:
Column A -> Value a , a , a
Column B -> Value b , b , b
Column C -> Value 1, 2, 3
Any Idea?
try this:
create table test(cola varchar(10),colb varchar(10),colc varchar(10))
insert into test select 'a','b','123'
;WITH CTE AS(
select cola,colb,LEFT(colc,1) colc,RIGHT(colc,len(colc)-1) as rem from test
union all
select cola,colb,LEFT(rem,1) colc,RIGHT(rem,len(rem)-1) as rem from CTE
where LEN(rem) >= 1
)
select cola,colb,colc from CTE
Related
I am selecting the records from 2 tables in which the 1st table column named DESC (first 3 characters) should match with the project column of the 2nd table.
I want to get the last 2 characters from Table 1 column DESC to be added in my output, but the last 2 characters are not present in Table 2 column project.
select SUBSTRING(a.[DESC], 1, 3)
from Table1 a
join Table2 b on SUBSTRING(a.[DESC], 1, 3) = b.project
Input: 1st Table DESC Column: Value: '2AB F YY'
2nd Table Project Column: Value: '2AB'
Expected Output: Return all the records of value 2AB
Column result:
'2AB YY'
Wrong output: all the records of value starting other then 2AB
One option is as follows
with data
as (
select SUBSTRING(a.[DESC],1,3) as first_3_characters,
,REVERSE(SUBSTRING(REVERSE(a.[DESC]),1,2)) as last_2_char_tab1
,REVERSE(SUBSTRING(REVERSE(b.project),1,2)) as last_2_char_tab2 characters_tab2
from Table1 a
join Table2 b
on SUBSTRING(a.[DESC],1,3) = b.project
)
select *,CONCAT(first_3_characters,last_2_characters)
from data
where last_2_char_tab1 <> last_2_char_tab2
Since you don't seem to need data from Table2, an EXISTS could be used for this.
And RIGHT can be used to get the last N characters of a string.
SELECT
CONCAT(LEFT([DESC], 3),' ', RIGHT([DESC], 2))
FROM Table1 t1
WHERE EXISTS
(
SELECT 1
FROM Table2 t2
WHERE t2.project = LEFT(t1.[DESC], 3)
)
ORDER BY 1;
Hi for my ssrs report i am using a matrix to display data row as a two column list and
I am using the following expression in order to group the row;
=ceiling(rownumber(nothing) / 2)
and
the following expression to group column;
=ceiling(rownumber(nothing) mod 2)
similar to https://www.experts-exchange.com/articles/12331/Simple-way-to-show-multi-column-data-in-SSRS-Horizontally-or-Vertically.html
it is working correctly however i would like results to be display alphabetical order going vertical instead of horizontal.
Like.
Record a Record d
Record b Record e
Record c Record f
Instead of
Record a Record b
Record c Record d
Record e Record f
i have order by in my sql query
any suggestions on how to achieve this?
You can modify your sql for this. The hack below could be used if you do not want to use multiple columns.
DECLARE #T TABLE
(
TableID INT,
Value1 NVARCHAR(20),
ShouldBe INT
)
INSERT INTO #T (TableID,Value1,ShouldBe)
VALUES
(1,'A',1),
(2,'B',3),
(3,'C',5),
(4,'D',2),
(5,'E',4),
(6,'F',6),
(7,'A',1),
(8,'B',3),
(9,'C',5),
(10,'D',2),
(11,'E',4),
(12,'F',6),
(13,'A',1)
DECLARE #NumberOfRowsPerPage INT = 3
DECLARE #NumberOfColumns INT = 2
SELECT PageNumber,Value1
FROM
(
SELECT ColumnOrder=ROW_NUMBER() OVER(PARTITION BY PageNumber,ColumnTile ORDER BY TableID),*
FROM
(
SELECT ColumnTile=NTILE(#NumberOfColumns) OVER(PARTITION BY PageNumber ORDER BY TableID),*
FROM
(
SELECT PageNumber=( (DataRowNumber -1) / (#NumberOfRowsPerPage * #NumberOfColumns )) + 1, *
FROM
(
SELECT DataRowNumber=ROW_NUMBER() OVER( ORDER BY TableID) ,*
FROM #T
)AS A
)AS B
)AS C
)AS D
ORDER BY
PageNumber,ColumnOrder,DataRowNumber
The query will produce the following output based on the RowsPerPage and NumberOfColumns.
Page Value
1 A
1 D
1 B
1 E
1 C
1 F
2 A
2 D
2 B
2 E
2 C
2 F
3 A
Lets say I have a table with 2 columns (a, b) with following values:
a b
--- ---
1 5
1 NULL
2 NULL
2 NULL
3 NULL
My desired output:
a
---
2
3
I want to select only those distinct values from column a for which every single occurrence of this value has NULL in column b. Therefore from my desired output, "1" won't come in because there is a "5" in column b even though there is a NULL for the 2nd occurrence of "1".
How can I do this using a TSQL query?
If I understand correctly, you can do this with group by and having:
select a
from t
group by a
having count(b) = 0;
When you use count() with a column name, it counts the number of non-NULL values. Hence, if all values are NULL, then the value will be zero.
It's fairly simple to do:
SELECT A
FROM table1
GROUP BY A
HAVING COUNT(B) = 0
Grouping by A results in all the rows where the value of A is identical to be transferred into a single row in the output. Adding the HAVING clause enables to filter those grouped rows with an aggregate function. COUNT doesn't count NULL values, so when it's 0, there are no other values in B.
Two more ways to do this:
SELECT a
FROM t
EXCEPT
SELECT a
FROM t
WHERE b IS NOT NULL ;
This would use an index on (a, b):
SELECT a
FROM t
GROUP BY a
WHERE MIN(b) IS NOT NULL ;
Try it like this:
DECLARE #tbl TABLE(a INT, b INT);
INSERT INTO #tbl VALUES(1,5),(1,NULL),(2,NULL),(2,NULL),(3,NULL);
--Your test data
SELECT * FROM #tbl;
--And this is what you want - hopefully...
SELECT DISTINCT tbl.a
FROM #tbl AS tbl
WHERE NOT EXISTS(SELECT * FROM #tbl AS x WHERE x.a=tbl.a AND b IS NOT NULL)
To turn your question on it's head, you want the values from column a where there are no non-null values for that value in column b.
select distinct a
from table1 as t1
where 0 = (select count(*)
from table1 as t2
where t1.a = t2.a
and b is not null)
Sample fiddle is here: http://sqlfiddle.com/#!6/5d1b8/1
This should do it:
SELECT DISTINCT a
FROM t
WHERE b IS NULL
AND a NOT IN (SELECT a FROM t WHERE b IS NOT NULL);
I have following data set
a b c
`1` 2 3
3 6 9
9 2 11
As you can see column a's first value is fixed (i.e. 1), but from second row it picks up the value of column c of previous record.
Column b's values are random and column c's value is calculated as c = a + b
I need to write a sql query which will select this data in above format. I tried writing using lag function but couldn't achieve.
Please help.
Edit :
Column b exists in table only, a and c needs to calculated based on the values of b.
Hanumant
SQL> select a
2 , b
3 , c
4 from dual
5 model
6 dimension by (0 i)
7 measures (0 a, 0 b, 0 c)
8 rules iterate (5)
9 ( a[iteration_number] = nvl(c[iteration_number-1],1)
10 , b[iteration_number] = ceil(dbms_random.value(0,10))
11 , c[iteration_number] = a[iteration_number] + b[iteration_number]
12 )
13 order by i
14 /
A B C
---------- ---------- ----------
1 4 5
5 8 13
13 8 21
21 2 23
23 10 33
5 rows selected.
Regards,
Rob.
Without knowing the relation between the rows ,how can we calculate the sum of the previous row a and b column to current row a column .I have created two more column id and parent in the table to find the relation between the two rows.
parent is the column which tell us about the previous row ,and id is the primary key of the row .
create table test1 (a number ,b number ,c number ,id number ,parent number);
Insert into TEST1 (A, B, C, ID) Values (1, 2, 3, 1);
Insert into TEST1 (B, PARENT, ID) Values (6, 1, 2);
Insert into TEST1 (B, PARENT, ID) Values (4, 2, 3);
WITH recursive (a, b, c,rn) AS
(SELECT a,b,c,id rn
FROM test1
WHERE parent IS NULL
UNION ALL
SELECT (rec.a+ rec.b) a
,t1.b b
,(rec.a+ rec.b+t1.b) c
,t1.id rn
FROM recursive rec,test1 t1
WHERE t1.parent = rec.rn
)
SELECT a,b,c
FROM recursive;
The WITH keyword defines the name recursive for the subquery that is to follow
WITH recursive (a, b, c,rn) AS
Next comes the first part of the named subquery
SELECT a,b,c,id rn
FROM test1
WHERE parent IS NULL
The named subquery is a UNION ALL of two queries. This, the first query, defines the starting point for the recursion. As in my CONNECT BY query, I want to know what is the start with record.
Next up is the part that was most confusing :
SELECT (rec.a+ rec.b) a
,t1.b b
,(rec.a+ rec.b+t1.b) c
,t1.id rn
FROM recursive rec,test1 t1
WHERE t1.parent = rec.rn
This is how it works :
WITH query: 1. The parent query executes:
SELECT a,b,c
FROM recursive;
This triggers execution of the named subquery. 2 The first query in the subquery's union executes, giving us a seed row with which to begin the recursion:
SELECT a,b,c,id rn
FROM test1
WHERE parent IS NULL
The seed row in this case will be for id =1 having parent is null. Let's refer to the seed row from here on out as the "new results", new in the sense that we haven't finished processing them yet.
The second query in the subquery's union executes:
SELECT (rec.a+ rec.b) a
,t1.b b
,(rec.a+ rec.b+t1.b) c
,t1.id rn
FROM recursive rec,test1 t1
WHERE t1.parent = rec.rn
Note: I would like to do this in a single SQL statement. not pl/sql, cursor loop, etc.
I have data that looks like this:
ID String
-- ------
01 2~3~1~4
02 0~3~4~6
03 1~4~5~1
I want to provide a report that somehow pivots the values of the String column into distinct rows such as:
Value "Total number in table"
----- -----------------------
1 3
2 1
3 2
4 3
5 1
6 1
How do I go about doing this? It's like a pivot table but I am trying to pivot the data in a column, rather than pivoting the columns in the table.
Note that in real application, I do not actually know what the values of the String column are; I only know that the separation between values is '~'
Given this test data:
CREATE TABLE tt (ID INTEGER, VALUE VARCHAR2(100));
INSERT INTO tt VALUES (1,'2~3~1~4');
INSERT INTO tt VALUES (2,'0~3~4~6');
INSERT INTO tt VALUES (3,'1~4~5~1');
This query:
SELECT VALUE, COUNT(*) "Total number in table"
FROM (SELECT tt.ID, SUBSTR(qq.value, sp, ep-sp) VALUE
FROM (SELECT id, value
, INSTR('~'||value, '~', 1, L) sp -- 1st posn of substr at this level
, INSTR(value||'~', '~', 1, L) ep -- posn of delimiter at this level
FROM tt JOIN (SELECT LEVEL L FROM dual CONNECT BY LEVEL < 20) q -- 20 is max #substrings
ON LENGTH(value)-LENGTH(REPLACE(value,'~'))+1 >= L
) qq JOIN tt on qq.id = tt.id)
GROUP BY VALUE
ORDER BY VALUE;
Results in:
VALUE Total number in table
---------- ---------------------
0 1
1 3
2 1
3 2
4 3
5 1
6 1
7 rows selected
SQL>
You can adjust the maximum number of items in your search string by adjusting the "LEVEL < 20" to "LEVEL < your_max_items".