Lets consider the orders table in the Northwind database and I need to get the count of order records for the year 1997 and 1998 in a single query how do I do this?
I tried some thing like this...
select COUNT(o.orderid) as 'Count Of Orders 1997', COUNT(o1.orderid) as 'Count Of Orders 1998'
from orders O
inner join orders o1
on o.orderid = o1.orderid
where year(o.orderdate) = 1997
or year(o1.orderdate) = 1998
Please help me in this...
select COUNT(o.orderid) as 'Count Of years'
from orders O
where year(o.orderdate) = 1997
or year(o1.orderdate) = 1998
group by year(o.orderdate)
SELECT
(SELECT COUNT(*) FROM orders WHERE YEAR(orderdate) = 1997)
AS [Orders 1997],
(SELECT COUNT(*) FROM orders WHERE YEAR(orderdate) = 1998)
AS [Orders 1998]
if you want in one row then you can use pivot function as well
with pivot_table as
(
select orderid, orderdate from orders
)
select * from pivot_table
pivot ( count(orderid) as 'count' for to_char(orderdate,'YYYY') in ('1997' , '1998') )
then it will give output like
1997_count | 1998_count
<count of 1997> <count of 1998>
or else you can do folloing for take output in different different rows
SELECT to_char(o.OrderDate,'YYYY'), COUNT(o.OrderId)
FROM Orders o
WHERE to_char(o.OrderDate,'YYYY') = '1997'
or to_char(o.OrderDate,'YYYY') = '1998'
GROUP BY to_char(o.OrderDate,'YYYY')
Related
I am using the Nortwind database with SQL Server 2014, I try to make a query to divide the results of the orders in two different years, The format that I want in my query is
category |anio one | anio two
where the years may vary , What I try so far is
SELECT ca.CategoryName , YEAR(o.OrderDate), SUM(ot.UnitPrice*ot.Quantity) as total
FROM Orders o
INNER JOIN [Order Details] ot ON O.OrderID = ot.OrderID
INNER JOIN Products pro ON ot.ProductID = pro.ProductID
INNER JOIN Categories ca ON pro.CategoryID = ca.CategoryID
GROUP BY ca.CategoryName,YEAR(o.OrderDate)
ORDER BY ca.CategoryName;
This gives me the totals of each category for a different year, 1996-1997-1998 in column YEAR(o.OrderDate)
I want to get for example
CategoryName | 1996 | 1997
Beverages |53879,20 | 110424,00
Condiments |19458,30 | 59679,00
....
Use "conditional aggregates".
SELECT
ca.CategoryName
, SUM(case when year(o.OrderDate) = 1996 then ot.UnitPrice * ot.Quantity end) AS total_1996
, SUM(case when year(o.OrderDate) = 1997 then ot.UnitPrice * ot.Quantity end) AS total_1997
FROM Orders o
INNER JOIN [Order Details] ot ON o.OrderID = ot.OrderID
INNER JOIN Products pro ON ot.ProductID = pro.ProductID
INNER JOIN Categories ca ON pro.CategoryID = ca.CategoryID
where o.OrderDate >= '19960101' and o.OrderDate < '19980101'
GROUP BY
ca.CategoryName
ORDER BY
ca.CategoryName
Basically that means use a case expression inside the aggregate function.
I case you are wondering why I have not used "between in the where clause: see
Bad habits to kick : mis-handling date / range queries
You can use PIVOT to get your desired Output
BEGIN TRAN
CREATE TABLE #Temp(CategoryName NVARCHAR(50),[Year]INT,TOTAL DECIMAL(15,2))
INSERT INTO #Temp
SELECT ca.CategoryName , YEAR(o.OrderDate), SUM(ot.UnitPrice*ot.Quantity) as total
FROM Orders o
INNER JOIN [Order Details] ot ON O.OrderID = ot.OrderID
INNER JOIN Products pro ON ot.ProductID = pro.ProductID
INNER JOIN Categories ca ON pro.CategoryID = ca.CategoryID
GROUP BY ca.CategoryName,YEAR(o.OrderDate)
ORDER BY ca.CategoryName;
SELECT * FROM #Temp
GO
select *
from
(
select CategoryName, [Year], TOTAL
from #Temp
) src
pivot
(
sum(TOTAL)
for YEAR in ([1996], [1997]
)) piv;
ROLLBACK TRAN
you can use pivot to get the desired output
CREATE TABLE #TEMP
(
Category VARCHAR(200),
YEAR1 NUMERIC,
Total MONEY
)
INSERT INTO #TEMP
SELECT 'beverages', 1996, 500
union
SELECT 'beverages', 1997, 750
union
SELECT 'Condiments', 1997, 1000
union
SELECT 'Condiments', 1996, 800
SELECT *
FROM
(
SELECT Category,YEAR1, Total FROM #TEMP
) AS SourceTable
PIVOT
(
AVG(Total) FOR YEAR1 IN ( [1996], [1997])
) AS PivotTable;
I have to make a query where I show for each year wich shipper had the maximum total cost.
My query now show for each year the total cost of each shipper. So in the result i must have a list of the years, for each year the shipper and the total cost.
Thanks in advance.
select year(OrderDate), s.ShipperID, sum(freight)
from orders o
join shippers s on o.ShipVia = s.ShipperID
group by year(OrderDate),s.ShipperID
Select a.FreightYear, a,ShipperID, a.FreightValue
from
(
select year(OrderDate) FreightYear, s.ShipperID, sum(freight) FreightValue
from orders o
join shippers s on o.ShipVia = s.ShipperID
group by year(OrderDate),s.ShipperID
) a
inner join
(
select FreightYear, max(FrieghtTotal) MaxFreight
from
(
select year(OrderDate) FreightYear, s.ShipperID, sum(freight) FreightTotal
from orders o
join shippers s on o.ShipVia = s.ShipperID
group by year(OrderDate),s.ShipperID
) x
group by FreightYear
) max on max.FreightYear = a.FreightYear and max.MaxFreight = a.FreightValue
order by FreightYear
Inner query a is your original query, getting the value of freight by shipper.
Inner query max gets the max value for each year, and then query max is joined to query a, restricting the rows in a to be those with a value for a year = to the max value for the year.
Cheers -
It's marginally shorter if you use windowing functions.
select shippers_ranked.OrderYear as OrderYear,
shippers_ranked.ShipperId as ShipperId,
shippers_ranked.TotalFreight as TotalFreight
from
(
select shippers_freight.*, row_number() over (partition by shippers_freight.OrderYear order by shippers_freight.TotalFreight desc) as Ranking
from
(
select year(OrderDate) as OrderYear,
s.ShipperID as ShipperId,
sum(freight) as TotalFreight
from orders o
inner join shippers s on o.ShipVia = s.ShipperID
group by year(OrderDate), s.ShipperID
) shippers_freight
) shippers_ranked
where shippers_ranked.Ranking = 1
order by shippers_ranked.OrderYear
;
You need to decide what you would like to happen if two shippers have the same TotalFreight for a year - as the code above stands you will get one row (non-deterministically). If you would like one row, I would add ShipperId to the order by in the over() clause so that you always get the same row. If in the same TotalFreight case you would like multiple rows returned, use dense_rank() rather than row_number().
I have two tables
Order with columns:
OrderID,OrderDate,CID,EmployeeID
And OrderItem with columns:
OrderID,ItemID,Quantity,SalePrice
I need to return the CustomerID(CID), number of orders per customer, and each customers total amount for all orders.
So far I have two separate queries. One gives me the count of customer orders....
SELECT CID, Count(Order.OrderID) AS TotalOrders
FROM [Order]
Where CID = CID
GROUP BY CID
Order BY Count(Order.OrderID) DESC;
And the other gives me the total sales. I'm having trouble combining them...
SELECT CID, Sum(OrderItem.Quantity*OrderItem.SalePrice) AS TotalDollarAmount
FROM OrderItem, [Order]
WHERE OrderItem.OrderID = [Order].OrderID
GROUP BY CID
I'm doing this in Access 2010.
You would use COUNT(DISTINCT ...) in other SQL engines:
SELECT CID,
Count(DISTINCT O.OrderID) AS TotalOrders,
Sum(OI.Quantity*OI.SalePrice) AS TotalDollarAmount
FROM [Order] O
INNER JOIN [OrderItem] OI
ON O.OrderID = OI.OrderID
GROUP BY CID
Order BY Count(DISTINCT O.OrderID) DESC
Which Access unfortunately does not support. Instead you can first get the Order dollar amounts and then join them before figuring the order counts:
SELECT CID,
COUNT(Orders.OrderID) AS TotalOrders,
SUM(OrderAmounts.DollarAmount) AS TotalDollarAmount
FROM [Orders]
INNER JOIN (SELECT OrderID, Sum(Quantity*SalePrice) AS DollarAmount
FROM OrderItems GROUP BY OrderID) AS OrderAmounts
ON Orders.OrderID = OrderAmounts.OrderID
GROUP BY CID
ORDER BY Count(Orders.OrderID) DESC
If you need to include Customers that have orders with no items (unusual but possible), change INNER JOIN to LEFT OUTER JOIN.
Create a query which uses your 2 existing queries as subqueriers, and join the 2 subqueries on CID. Define your ORDER BY in the parent query instead of in a subquery.
SELECT
sub1.CID,
sub1.TotalOrders,
sub2.TotalDollarAmount
FROM
(
SELECT
CID,
Count(Order.OrderID) AS TotalOrders
FROM [Order]
GROUP BY CID
) AS sub1
INNER JOIN
(
SELECT
CID,
Sum(OrderItem.Quantity*OrderItem.SalePrice)
AS TotalDollarAmount
FROM OrderItem INNER JOIN [Order]
ON OrderItem.OrderID = [Order].OrderID
GROUP BY CID
) AS sub2
ON sub1.CID = sub2.CID
ORDER BY sub1.TotalOrders DESC;
I am trying to recap on my sql skill, now I am trying to run a simple query on northwinddb to show me the top customer for each year, but as soon as I use the TOP function only 1 record gets display no matter on what I partition by, This is my T-SQL code
SELECT DISTINCT TOP 1 C.CompanyName
, YEAR(O.OrderDate) AS Year
, SUM(Quantity) OVER(PARTITION BY C.CompanyName, YEAR(O.OrderDate)) AS Total
FROM Customers C JOIN Orders O
ON C.CustomerID = O.CustomerID JOIN [Order Details] OD
ON O.OrderID = OD.OrderID
You can do this bit more compactly in SQL Server 2008 as follows:
select top (1) with ties
C.CompanyName,
Year(O.OrderDate) as Yr,
sum(OD.Quantity) as Total
from Orders as O
join Customers as C on C.CustomerID = O.CustomerID
join "Order Details" as OD on OD.OrderID = O.OrderID
group by C.CompanyName, Year(O.OrderDate)
order by
row_number() over (
partition by Year(O.OrderDate)
order by sum(OD.Quantity) desc
);
Thank you for the help. I found a way that allows me to change the number of top customers i want to see for each year. By using Sub queries and Row_Number
SELECT CompanyName
,yr
,Total
FROM(SELECT CompanyName
, yr
, Total
, ROW_NUMBER() OVER(PARTITION BY yr ORDER BY yr, Total DESC) AS RowNumber
FROM(SELECT DISTINCT CompanyName
, YEAR(O.OrderDate) AS yr
, SUM(OD.Quantity) OVER(PARTITION BY CompanyName
, YEAR(O.OrderDate)) As Total
FROM Customers C JOIN Orders O
ON C.CustomerID = O.CustomerID JOIN [Order Details] OD
ON O.OrderID = OD.OrderID) Tr)Tr2
Where RowNumber <= 1
Three steps: first sum quantities grouped by company and year, then order the results by quantity, then filter first row by group only.
; WITH sums as (
SELECT C.Companyname, YEAR(O.OrderDate) AS Year, sum (Quantity) Total
FROM Customers C JOIN Orders O
ON C.CustomerID = O.CustomerID JOIN [Order Details] OD
ON O.OrderID = OD.OrderID
group by C.Companyname, YEAR(O.OrderDate)
)
with ordering as (
select Companyname, Year, Total,
row_number() over (partition by CompanyName, Year order by Total desc) rownum
from sums
)
select *
from ordering
where rownum = 1
I have the following database structure :
[Order]
OrderId
Total
[Payment]
OrderId
Amount
Every Order can have X payment rows. I want to get only the list of orders where the sum of all the payments are < than the order Total.
I have the following SQL but I will return all the orders paid and unpaid.
SELECT o.OrderId,
o.UserId,
o.Total,
o.DateCreated,
COALESCE(SUM(p.Amount),0) AS Paid
FROM [Order] o
LEFT JOIN Payment p ON p.OrderId = o.OrderId
GROUP BY o.OrderId, o.Total, o.UserId, o.DateCreated
I have tried to add Where (Paid < o.Total) but it does not work, any idea?
BTM I'm using SQL CE 3.5
What you are looking for is the HAVING clause.
Instead of "Where (COALESCE(SUM(p.Amount),0) < o.Total)", try "HAVING (COALESCE(SUM(p.Amount),0) < o.Total)"
Check out the MSDN Reference on HAVING.
Select Order.* From Order
Left Join
(Select OrderID, Sum(Amount) As t From Payment Group By OrderID) As s On s.OrderID = Oder.OrderID
Where IsNULL(s.t,0) < Order.Total