Given the following database table:
StartDate DATETIME -- day that the reminder period starts
LastReminderDate DATETIME -- the last time the reminder triggered
DayOfMonth INT -- the day of the month to remind the user
Interval INT -- how often in months to remind the user
How can I figure out the next reminder date based on these values? For example:
StartDate = '6/1/2011'
LastReminderDate = '6/5/2011'
DayOfMonth = 5 -- remind on the 5th of the month
Interval = 2 -- remind every other month
For this particular example, the next reminder date should be 8/5/2011 because it reminds on the 5th of the month every two months. How would I write a function to figure this out?
If LastReminderDate is NULL, then LastReminderDate should be equal to StartDate
UPDATE:
StartDate = '6/1/2011'
LastReminderDate = NULL
DayOfMonth = 5
Interval = 2
In this case, there was no last reminder date. The first time the reminder would occur would be 6/5/2011. The solutions below seem to be returning 8/5 in this case.
Here are some specific rules:
The Reminder should always occur on whatever DayOfMonth is. If DayOfMonth would be illegal for the given month then it should be the last day of that month. For example....if DayOfMonth is 31 and the next reminder date would fall on June 31, then it should be June 30th instead.
The next reminder date should always be based off of the Last Reminder Date plus the Interval. If Last Reminder Date does not match the Day of Month, then it could potentially be more than what the interval was. For example...if Last Reminder was 6/1/2011 and the interval is 2 months, but the reminder is for the 20th of the month, then the next reminder will be 8/20/2011.
If there is no last reminder date, then use the Start Date instead of last reminder date...but this will use the earliest date in the future. If start date was 6/1/2011 and day of month is 5, then this will be 7/5/2011 since today is 6/22/2011. If Day of Month was 25 then it would be 6/25/2011
DECLARE
#StartDate AS datetime, -- day that the reminder period starts
#LastReminderDate AS datetime, -- the last time the reminder triggered
#DayOfMonth AS integer, -- the day of the month to remind the user
#Interval AS integer -- how often in months to remind the user
SET #StartDate = '6/1/2011'
SET #LastReminderDate = '6/5/2011'
SET #DayOfMonth = 5 -- remind on the 5th of the month
SET #Interval = 2 -- remind every other month
SELECT
CASE
WHEN #LastReminderDate IS NULL
THEN
CASE WHEN Day(#StartDate) <= #DayOfMonth
THEN DateAdd( month, ((Year( #StartDate ) - 1900) * 12) + Month( #StartDate ) - 1, #DayOfMonth - 1 )
ELSE DateAdd( month, ((Year( #StartDate ) - 1900) * 12) + Month( #StartDate ) - 0, #DayOfMonth - 1 )
END
ELSE DateAdd( month, #Interval, #LastReminderDate )
END
The meat of this is the last four lines, the SELECT CASE ... END statement. I provided a whole script that lets you plug in different values, and see how the SELECT CASE ... END behaves for those test values.
But to just use this on your table, use only the last four lines (and remove the # from the front of the names so they match the table's column names).
You could also generalize this so that Interval doesn't have to be months. If your table had an IntervalType column, you could supply that as the first argument to DateAdd(). See the docs but some common intervals are days, months, years, and so on.
EDIT2: Respect DayOfMonth.
Since you want to use the StartDate if there is no LastReminderDate, then you'll want to use COALESCE for that bit of logic: COALESCE(LastReminderDate, StartDate)
Now, get to the last of the previous month: DATEADD(DAY, -DAY(COALESCE(LastReminderDate, StartDate)), COALESCE(LastReminderDate, StartDate))
Finally, add the months and then get to the date that we need:
DATEADD(MONTH, Interval, DATEADD(DAY, -DAY(COALESCE(LastReminderDate, StartDate)) + DayOfMonth, COALESCE(LastReminderDate, StartDate)))
This will potentially go forward less than two months if the date of the last reminder was on a day of the month after the "DayOfMonth" that's configured for the reminder. You should be able to tweak that depending on what your business logic is in that situation.
Related
I am working on a report that will send daily with the full months data minus the current day as it sends early and won't have relevant data from today.
Currently the parameter for the start as =dateadd(“m”,1,dateserial(year(Today),month(Today),0))
and the end as =DateAdd("d",-1,Today())
The problem is that this will skip the last day of each month. I want to change the start date to the first of the month from today - 1 day, but I am not sure how to do this?
I could change it to send with the current days data as well but with it sending at 8 AM the data would still be missing.
Probably least amount of code is to (1) subtract a day from today, (2) take the eomonth of the previous month, and (3) add a day.
SELECT DATEADD(DAY, 1, EOMONTH(DATEADD(DAY, -1, GETDATE()),-1));
I'm not sure what language you're doing dateserial stuff in but I'd personally do this inside SQL Server.
Also the best way to drive a report for any period is to say:
col >= start of the period
AND
col < start of *next* period
For example, for a report to cover all of last month (I realize that's not quite what you're doing, it's just a simpler example), I would say:
DECLARE #start date = DATEADD(DAY, 1, EOMONTH(GETDATE(), -2));
...
WHERE date_column >= #start
AND date_column < DATEADD(MONTH, 1, #start);
This way you don't get bitten by all of the problems that can happen with various date/time types as you try to figure out what is the end of a day or month.
For month-to-date covering yesterday and not today, I would say:
DECLARE #today date = GETDATE();
DECLARE #start date = DATEADD(DAY, 1, EOMONTH(DATEADD(DAY, -1, #today),-1));
... WHERE date_column >= #start
AND date_column < #today;
Consider the date "2022-07-02"
For the month July first week only have 3 days in it.
I need to find the number of days in the week for the given date.
In above date the week has 3 days where "2022-07-02" day reside.
Example 2 :
For month June in 2022 first week has 5 days in the week
Therefore if i declare a date as "2022-06-03" it should pass the number of days in the week as 5
I need a query to find the number of days for the specific week.
set datefirst 1 -- assumes Monday is set as start of week
declare #myDate date = getdate();
-- calculate the next last day of week
declare #nextSunday date = dateadd(day, 7 - datepart(weekday, #myDate), #myDate);
select case
-- advancing into the next month implies a partial week
-- datediff(month, #myDate, nextSunday) = 1 would be equivalent
when day(#nextSunday) < day(#myDate) then 7 - day(#nextSunday)
-- else see if still within first week
when day(#nextSunday) < 7 then day(#nextSunday)
else 7 end;
Within a query you might use it this way:
select case
when day(nextSunday) < day(dateColumn) then 7 - day(nextSunday)
when day(nextSunday) < 7 then day(nextSunday)
else 7 end
from
myData cross apply (
values (dateadd(day, 7 - datepart(weekday, dateColumn), dateColumn))
) v(nextSunday);
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=ee5bfb52dabe31dd619cfd136689db59
If you don't want the shorthand form then just replace every instance of nextSunday in the final step with its full expression.
There's nothing in the logic that prevents this from working with another first day of week. I just chose a variable name that helped ellucidate this particular problem.
I am trying to write a SQL query that shows the count of the days and date depending upon the financial period it falls in. The financial period starts 5 days before the month end eg march 27th to 26th April
For the above mentioned period if the day is 29th march, the count of the day should be 3 and the date should be 2020-04. The date should adjust depending upon the period it falls in.
I tried to adress the second part of this query by writing the below script but it does not bring any result
declare #date datetime
set #date = getdate()
SELECT format (date,'yyyy-MM-dd') as date
where #date
between dateadd(day,-5,EOMONTH(getdate(),-1)) and dateadd(day,-5,EOMONTH(getdate()))
updated to include 5 days from previous month.
Is this what you are looking for the second part?
Edit: Modifying the query. I guess this should give you what you need for both the parts.
you can try changing the dates in set #date.
Please note that the -4 instead of -5 is done intentionally as you said the financial month starts 5 days earlier. For March, 31 - 5 would give 26, but it should start on 27 right? so that on 29th the no. of days should be 3 including 27 and 29. Anyways, the query should be self explanatory, might just need to change the number depending on your requirement.
declare #date datetime
--set #date = getdate()
set #date = '2020-02-14'
SELECT format(#date,'yyyy-MM-dd') as date,
case WHEN #date < dateadd(day,-4,EOMONTH(#date)) THEN format(EOMONTH(#date),'yyyy-MM')
ELSE format(EOMONTH(#date, 1),'yyyy-MM') END
AS FinancialMonth,
CASE WHEN #date < dateadd(day,-4,EOMONTH(#date)) THEN DATEDIFF(day,dateadd(day,-5,EOMONTH(#date,-1)), #date)
ELSE DATEDIFF(day, dateadd(day,-5,EOMONTH(#date)), #date) END
AS CountDays
The following code will calculate what you need. Please read the comments in the code itself.
-- First, lets declare all the variables we need.
-- I tried to name them so they are selfexplanatory.
declare #inputdate DateTime,
#financialPeriodStartDate DateTime,
#EndOfTheMonth DateTime,
#nextFinantialMonthYear DateTime,
#previousFinancialPeriodStartDate DateTime
-- Now we calculate some of the values
set #inputdate = GETDATE() -- Let's use Today's date, but you can change this to any date.
set #EndOfTheMonth = EOMONTH(#inputdate) -- This is the end of the month for the input date
set #financialPeriodStartDate = DATEADD(DAY,-5,EOMONTH(#inputdate)) -- This is you Financial Period Start Date for the giving input date.
set #previousFinancialPeriodStartDate = DATEADD(DAY,-5,EOMONTH(DATEADD(MONTH, -1, #inputdate))) -- Also calculates the Start Date of the precious financial period.
set #nextFinantialMonthYear = DATEADD(MONTH, 1,#financialPeriodStartDate) -- This is the start date of the next financial period.
-- In the following Select, it calculates the values you need, based in the previous variables.
select
#inputdate as Today,
#EndOfTheMonth as EndOfMonth,
#previousFinancialPeriodStartDate as PreviousFinancialPeriodStartDate,
#financialPeriodStartDate as FinacialPeriodStartDate,
CASE WHEN DATEDIFF(DAY , #financialPeriodStartDate, #inputdate + 1 ) < 0
THEN DATEDIFF(DAY , #previousFinancialPeriodStartDate, #inputdate + 1 )
WHEN DATEDIFF(DAY , #financialPeriodStartDate, #inputdate + 1 ) >=0
THEN DATEDIFF(DAY , #financialPeriodStartDate, #inputdate + 1 )
END as DaysFromFPStartDate,
STR(YEAR(#nextFinantialMonthYear)) +'-'+LTRIM(RTRIM(STR(MONTH(#nextFinantialMonthYear)))) as NextFinantialPeriodMonthAndYear
I hope it helps.
my user table is as follows:
birhtMonth: int
dayOfBirthday: int
HireDate: Date
REQUIREMENT: i want to get all upcoming birthdays and hire dates (day/month year is excluded here) in next 6 months, putting in consideration that for current month the day should be greater than today, so here's what i did:
#Query("from User u where ( (u.birthMonth in (8,9,10,11,12,1)) or (month(u.hireDate) in (8,9,10,11,12,1)) ) and u.company = :company")
this gets all upcoming birthdays & hire dates in next six months but it gets birthdays & hire dates in this month for days before & after current day, and it should only get results > current day and ignore results < current day in this month.
EXAMPLE:
today's date is 8/3/2013, if there's birthday with birthMonth=8 and dayOfBirth=3 or 2 or 1 it should be ignored only dayOfBirth > 3 in current month is considered, also if there's hirDate like:
2011-08-01
2012-08-02
2012-08-03
they should be ignored too, please advise how to solve this in sql or hql.
Your hireDate is of type Date, so use a date comparison and use between such as:
(hireDate between :toDayParam and :sixMonthLaterParam)
for birthDate, you can compare with lpad(birthMonth, 2, 0) + lpad(birthDate, 2, 0) but you shall care about whether six month later is in next year or current year.
I think your looking for the DATE functions. They can greatly help you out here. Specifically the DATEADD function. Take a look at the code I made here.
SELECT * FROM dbo.product
WHERE dbo.product.stockDate > GETDATE()
AND dbo.product.stockDate < GETDATE() + DATEADD(month, 6, dbo.product.stockDate)
AND dbo.product.expirationDate > GETDATE()
AND dbo.product.expirationDate < GETDATE() + DATEADD(month, 6, dbo.product.expirationDate)
This will guarantee that the stockDate and the expirationDate are greater than the current date and less than the current date + 6 mo. DATEADD works as follows DATEADD(-what you want to increment by-, -how much you want to increment-, -date to add to-).
I'm trying to create custom week numbers and ranges based on user entered Week Start Day.
I'm passing that User defined day with SET Datefirst = #Userdefinedvalue (using a function to map my weekday start values to T-SQL's). Also I have a function to gets me the last day of the current week.
What is the best approach for this?
My Goal is: if I select Tuesday as my start day of the week the Stored Procedure to generate my week numbers and start/end dates based on my selection for the entire year
The idea is to find the first day of the week. First, use SQL Server built in functions to move the start of the week to the Sunday (in the US) by subtracting datepart(wd). Actually datepart(wd) returns values form 1 to 7 and we want them 0 to 6.
Then, add back in an offset based on your date of the week. Here is example code:
declare #offset int (case when #DateFirst = 'Mon' then 1
when #DateFirst = 'Tue' then 2
...
when #DateFirst = 'Sun' then 0
end);
select dateadd(dd, #offset - (datepart(wd, thedate) - 1)
thedate) as WeekStartDate