I am currently working an SQL script to calculate the difference between two dates which would give me the result in DD:HH:MI:SEC format.
Example:
Date 1: 7/30/12 4:00 PM
Date 2: 5/4/12 10:31 AM
And the result should be 87:05:29:00
Can you kindly help with the script for this?
Regards,
Arjun
If you are using sql-server then you can do this:
declare #x int,
#dt1 smalldatetime = '1996-03-25 03:24:16',
#dt2 smalldatetime = getdate()
set #x = datediff (s, #dt1, #dt2)
SELECT convert(varchar, #x / (60 * 60 * 24)) + ':'
+ convert(varchar, dateadd(s, #x, convert(datetime2, '0001-01-01')), 108)
Reference here
Well, you if want to perform some calculation, you could do this as well:
DECLARE #SecsInADay INT = 60 * 60 * 24
DECLARE #DATE1 DATETIME = CONVERT(DATETIME,'30/07/2012 16:00:00')
DECLARE #DATE2 DATETIME = CONVERT(DATETIME,'04/05/2012 10:31:00')
DECLARE #Days INT = DATEDIFF(DAY, #DATE2, #DATE1)
DECLARE #DiffInSeconds INT = DATEDIFF(SECOND, #DATE2, #DATE1)
DECLARE #TotalDaysInSeconds INT = #Days * #SecsInADay
DECLARE #RemainingHours INT = #DiffInSeconds - #TotalDaysInSeconds
DECLARE #Hours INT = #RemainingHours / 3600
DECLARE #Seconds INT = #RemainingHours % 3600
DECLARE #Minutes INT = #Seconds / 60
DECLARE #RemainingSeconds INT = #Seconds % 60
SELECT
CASE WHEN #Days < 10 THEN '0' + CAST(#Days AS VARCHAR) ELSE CAST(#Days AS VARCHAR) END + ':' +
CASE WHEN #Hours < 10 THEN '0' + CAST(#Hours AS VARCHAR) ELSE CAST(#Hours AS VARCHAR) END + ':' +
CASE WHEN #Minutes < 10 THEN '0' + CAST(#Minutes AS VARCHAR) ELSE CAST(#Minutes AS VARCHAR) END + ':' +
CASE WHEN #RemainingSeconds < 10 THEN '0' + CAST(#RemainingSeconds AS VARCHAR) ELSE CAST(#RemainingSeconds AS VARCHAR) END
Hi i had a similar problem, took some time to think and here's my solution, I've had the Table with user subscriptions, there sad starting time and closing time, my problem was a bit more complex bit basically it came down to this:
SELECT subscription_id, time_open, time_closed, TIMESTAMPDIFF(DAY,time_open,time_closed) AS Day,
HOUR(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Hour,
MINUTE(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Minute,
SECOND(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Second
FROM `user_subscription`
So basically what this query does is that it calculates days by deducing dates in the first line. Then it adds the number of the full days to the starting time and reduces the closing time my the sum, so what remains is the time in the current day. After that you just select Hours, minutes, and seconds from that. If you want it all together you can concatenate the strings but this way you can use it further, unlike the strings.
I am developing Time management system for employees.
I want the duration how much duration employee come late , or he went early.
i have following structure.
**Attendace**
AutoId --uniqueidentifier
EMployeeId --uniqueidentifier
Date --datetime
InTime -- varchar(50)
OutTime -- varchar(50)
ActualInTime--datetime
ActualOutTime--datetime
I want Late Coming Report ( i.e. who came late in morning after ActualInTime and how much duration in hh:mm:ss ) and also want early going(i.e who went early in the evening before ActualOutTime in duration in format hh:mm:ss )
So can you please help me..???
I came across an easier way of solving this issue.
First, a quick example of turning a "number of seconds" into the "hh:mm:ss" format.
DECLARE #NumberOfSeconds int
SET #NumberOfSeconds = 3843 -- 1 hour, 4 minutes, 3 seconds
SELECT #NumberOfSeconds AS 'seconds',
CONVERT(varchar, DATEADD(second, #NumberOfSeconds, 0), 108) AS 'hh:mm:ss'
This will give us this output:
And we can easily take this a step further, calculate the number of seconds between two datetimes, and display it in hh:mm:ss format:
DECLARE
#NumberOfSeconds int,
#StartTime datetime = '2017-09-14 14:16:11',
#EndTime datetime = '2017-09-14 14:23:13'
SET #NumberOfSeconds = DATEDIFF(second, #StartTime, #EndTime)
SELECT #NumberOfSeconds AS 'seconds',
CONVERT(varchar, DATEADD(second, #NumberOfSeconds, 0), 108) AS 'hh:mm:ss'
Which gives us this output:
Simple, hey ?
(And yes, you can simplify it further by putting the DATEDIFF directly into the DATEADD function.)
You can do it in a very simple way:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
It will works until the difference of 86399 seconds (23:59:59):
select convert(char(8),dateadd(s,datediff(s
, DATEADD(s,-86399,GETDATE())
, GETDATE()
),'1900-1-1'),8)
... after that it will return to zero:
select convert(char(8),dateadd(s,datediff(s
, DATEADD(s,-86400,GETDATE())
, GETDATE()
),'1900-1-1'),8)
Because they are the same day (you don't have to worry about number of hours >24), you can just use a combination of DATEDIFF(second,time1,time2) and DATEADD(second,0,) to get a datetime value.
To format to hh:nn:ss, use convert(char(8),answer,8) but this is something better done by the reporting front end against the datetime result.
-- Late report
select *, dateadd(s,0,datediff(s,intime,actualintime)) late_by
from attendance
where intime < actualintime
this code might help you...
DECLARE #First datetime
DECLARE #Second datetime
SET #First = '04/02/2008 05:23:22'
SET #Second = getdate()
SELECT DATEDIFF(day,#First,#Second)*24 as TotalHours,
DATEDIFF(day,#First,#Second)*24*60 as TotalMinutes,
DATEDIFF(day,#First,#Second)*24*60*60 as TotalSeconds
well, yes, you need to use DATEDIFF, and yes, all that posted above works, but, if you want to show 07:07:07 instead of 7:7:7, you have to do something like this:
Declare #starttime datetime, #endtime datetime, #seconds int, #minutes int, #hours int
Set #starttime ='2013-10-01 05:05:17'
Set #endtime = '2013-10-01 23:10:18'
set #hours = DateDiff(hour, #starttime, #endtime)
set #minutes = DateDiff(minute, #starttime, #endtime);
set #seconds = DateDiff(second, #starttime, #endtime);
select case when DateDiff(minute, #starttime, #endtime) > 60
then CASE WHEN #hours >= 10 THEN cast(#hours as varchar(3))
ELSE '0' + cast(#hours as varchar(3)) END +':' +
CASE WHEN #minutes - (#hours * 60) >= 10 THEN
cast((#minutes - (#hours * 60)) as varchar(3))
ELSE '0' +cast((#minutes - (#hours * 60)) as varchar(3)) END
+ CASE WHEN (#seconds - (#minutes *60)) >= 10 THEN
+':' + cast(#seconds - (#minutes *60) as varchar(10))
ELSE ':0' + cast(#seconds - (#minutes *60) as varchar(10)) END
ELSE '0' + cast(#minutes as varchar(3)) +':' + cast(#seconds as varchar(10))
end
It may not look very nice, but it gave me what i wanted.
How about using CAST.
,CAST (Table1.DateTimeLatest-Table1.DateTimeFirst as time) as [Elapsed Time]
The raw result from SSMS from an apparatus table:
SQL Return shows out to nanoseconds in this Data.
For the report, as pasted in formatted Excel sheet:
Formatted result column as hh:mm:ss.
SELECT id, pickupdateandtime, GETDATE() AS CurrentTime,
((DATEDIFF(day,GETDATE(),pickupdateandtime)) - 1) AS Days ,
convert(char(8),dateadd(s,datediff(s,GETDATE(),pickupdateandtime),'1900-1-
1'),8) AS 'Hours & Mins' FROM orders
Here's what worked for me. Thank you #lynx_74.
https://i.stack.imgur.com/hOmyJ.png
Create a stored procedure to do the work and then just call the procedure passing your start and end dates.
CREATE PROCEDURE [dbo].[GetOperationDuration]
#DurationStart DATETIME, #DurationEnd DATETIME,
#Duration VARCHAR(100) OUTPUT
AS
BEGIN
DECLARE #years INT, #months INT, #days INT,
#hours INT, #minutes INT, #seconds INT, #milliseconds INT;
-- DOES NOT ACCOUNT FOR LEAP YEARS
SELECT #years = DATEDIFF(yy, #DurationStart, #DurationEnd)
IF DATEADD(yy, -#years, #DurationEnd) < #DurationStart
SELECT #years = #years-1
SET #DurationEnd = DATEADD(yy, -#years, #DurationEnd)
SELECT #months = DATEDIFF(mm, #DurationStart, #DurationEnd)
IF DATEADD(mm, -#months, #DurationEnd) < #DurationStart
SELECT #months=#months-1
SET #DurationEnd= DATEADD(mm, -#months, #DurationEnd)
SELECT #days=DATEDIFF(dd, #DurationStart, #DurationEnd)
IF DATEADD(dd, -#days, #DurationEnd) < #DurationStart
SELECT #days=#days-1
SET #DurationEnd= DATEADD(dd, -#days, #DurationEnd)
SELECT #hours=DATEDIFF(hh, #DurationStart, #DurationEnd)
IF DATEADD(hh, -#hours, #DurationEnd) < #DurationStart
SELECT #hours=#hours-1
SET #DurationEnd= DATEADD(hh, -#hours, #DurationEnd)
SELECT #minutes=DATEDIFF(mi, #DurationStart, #DurationEnd)
IF DATEADD(mi, -#minutes, #DurationEnd) < #DurationStart
SELECT #minutes=#minutes-1
SET #DurationEnd= DATEADD(mi, -#minutes, #DurationEnd)
SELECT #seconds=DATEDIFF(s, #DurationStart, #DurationEnd)
IF DATEADD(s, -#seconds, #DurationEnd) < #DurationStart
SELECT #seconds=#seconds-1
SET #DurationEnd= DATEADD(s, -#seconds, #DurationEnd)
SELECT #milliseconds=DATEDIFF(ms, #DurationStart, #DurationEnd)
SELECT #Duration= ISNULL(CAST(NULLIF(#years,0) AS VARCHAR(10)) + ' years,','')
+ ISNULL(' ' + CAST(NULLIF(#months,0) AS VARCHAR(10)) + ' months,','')
+ ISNULL(' ' + CAST(NULLIF(#days,0) AS VARCHAR(10)) + ' days,','')
+ ISNULL(' ' + CAST(NULLIF(#hours,0) AS VARCHAR(10)) + ' hours,','')
+ ISNULL(' ' + CAST(#minutes AS VARCHAR(10)) + ' minutes and','')
+ ISNULL(' ' + CAST(#seconds AS VARCHAR(10))
-- UNCOMMENT THEFOLLOWING IF YOU WANT MILLISECONDS INCLUDED
--+ CASE
--WHEN #milliseconds > 0
--THEN '.' + CAST(#milliseconds AS VARCHAR(10))
--ELSE ''
--END
+ ' seconds','')
SELECT #Duration
END
GO
Then just call using:
DECLARE #return_value int, #Duration varchar(100)
EXEC #return_value = [dbo].[GetOperationDuration] #DurationStart, #DurationEnd, #Duration = #Duration OUTPUT
SELECT #Duration as N'#Duration'
Thought I'd share my 2 cents. This fixes the overflow problems but only works with datetime not datetime2. It probably does not work with leap years or when clocks go backwards/forwards. I haven't tested with either.
declare #startTime datetime = getdate()
declare #endTime datetime
select [StartDate] = #startTime,
[EndDate] = #endTime,
[DD:HH:MM:SS.MS] = right( '00' + convert( varchar(20), datediff(hh, 0, #endTime - #startTime ) / 24 ), 2) + ':' +
right( '00' + convert( varchar(20), datediff(hh, 0, #endTime - #startTime ) % 24 ), 2) + ':' +
substring( convert( varchar(20), #endtime - #startTime, 114 ),
charindex( ':', convert( varchar(20), #endTime - #startTime, 114 ) ) + 1,
len( convert( varchar(20), #endTime - #startTime, 114 ) ) )
Is there any way to take the difference between two datetime in sql server?
For example, my dates are
2010-01-22 15:29:55.090
2010-01-22 15:30:09.153
So, the result should be 14.063 seconds.
Just a caveat to add about DateDiff, it counts the number of times you pass the boundary you specify as your units, so is subject to problems if you are looking for a precise timespan.
e.g.
select datediff (m, '20100131', '20100201')
gives an answer of 1, because it crossed the boundary from January to February, so even though the span is 2 days, datediff would return a value of 1 - it crossed 1 date boundary.
select datediff(mi, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Gives a value of 1, again, it passed the minute boundary once, so even though it is approx 14 seconds, it would be returned as a single minute when using Minutes as the units.
SELECT DATEDIFF (MyUnits, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Substitute "MyUnits" based on DATEDIFF on MSDN
SELECT DATEDIFF(day, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Replace day with other units you want to get the difference in, like second, minute etc.
I can mention four important functions of MS SQL Server that can be very useful:
1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):
select datediff(day,'1997-10-07','2011-09-11')
2) You can use the function GETDATE() to get the actual time and calculate differences of some date and actual date:
select datediff(day,'1997-10-07', getdate() )
3) Another important function is DATEADD(), used to convert some value in datetime using the same datepart of the datediff, that you can add (with positive values) or substract (with negative values) to one base date:
select DATEADD(day, 45, getdate()) -- actual datetime adding 45 days
select DATEADD( s,-638, getdate()) -- actual datetime subtracting 10 minutes and 38 seconds
4) The function CONVERT() was made to format the date like you need, it is not parametric function, but you can use part of the result to format the result like you need:
select convert( char(8), getdate() , 8) -- part hh:mm:ss of actual datetime
select convert( varchar, getdate() , 112) -- yyyymmdd
select convert( char(10), getdate() , 20) -- yyyy-mm-dd limited by 10 characters
DATETIME cold be calculated in seconds and one interesting result mixing these four function is to show a formated difference um hours, minutes and seconds (hh:mm:ss) between two dates:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
I tried this way and it worked. I used SQL Server version 2016
SELECT DATEDIFF(MILLISECOND,'2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')/1000.00;
Different DATEDIFF Functions are:
SELECT DATEDIFF(year, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(quarter, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(month, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(dayofyear, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(week, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(hour, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(minute, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(millisecond, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
Ref: https://learn.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql?view=sql-server-2017
Ok we all know the answer involves DATEDIFF(). But that gives you only half the result you may be after. What if you want to get the results in human-readable format, in terms of Minutes and Seconds between two DATETIME values?
The CONVERT(), DATEADD() and of course DATEDIFF() functions are perfect for a more easily readable result that your clients can use, instead of a number.
i.e.
CONVERT(varchar(5), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
This will give you something like:
HH:MM
If you want more precision, just increase the VARCHAR().
CONVERT(varchar(12), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
HH:MM.SS.MS
There are a number of ways to look at a date difference, and more when comparing date/times. Here's what I use to get the difference between two dates formatted as "HH:MM:SS":
ElapsedTime AS
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
I used this for a calculated column, but you could trivially rewrite it as a UDF or query calculation. Note that this logic rounds down fractional seconds; 00:00.00 to 00:00.999 is considered zero seconds, and displayed as "00:00:00".
If you anticipate that periods may be more than a few days long, this code switches to D:HH:MM:SS format when needed:
ElapsedTime AS
CASE WHEN DATEDIFF(S, StartDate, EndDate) >= 359999
THEN
CAST(DATEDIFF(S, StartDate, EndDate) / 86400 AS VARCHAR(7)) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 86400 / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
ELSE
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
END
The following query should give the exact stuff you are looking out for.
select datediff(second, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Here is the link from MSDN for what all you can do with datediff function .
https://msdn.microsoft.com/en-us/library/ms189794.aspx
Internally in SQL Server dates are stored as 2 integers. The first integer is the number of days before or after the base date (1900/01/01). The second integer stores the number of clock ticks after midnight, each tick is 1/300 of a second.
More info here
Because of this, I often find the simplest way to compare dates is to simply substract them. This handles 90% of my use cases. E.g.,
select date1, date2, date2 - date1 as DifferenceInDays
from MyTable
...
When I need an answer in units other than days, I will use DateDiff.
SELECT DATEDIFF(yyyy, '2011/08/25', '2017/08/25') AS DateDiff
It's gives you difference between two dates in Year
Here (2017-2011)=6 as a result
Syntax:
DATEDIFF(interval, date1, date2)
Use This for DD:MM:SS:
SELECT CONVERT(VARCHAR(max), Datediff(dd, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'))
+ ':'
+ CONVERT(CHAR(8), Dateadd(s, Datediff(s, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'), '1900-1-1'), 8)
So this isn't my answer but I just found this while searching around online for a question like this as well. This guy set up a procedure to calculate hours, minutes and seconds. The link and the code:
--Creating Function
If OBJECT_ID('UFN_HourMinuteSecond') Is Not Null
Drop Function dbo.UFN_HourMinuteSecond
Go
Exec(
'Create Function dbo.UFN_HourMinuteSecond
(
#StartDateTime DateTime,
#EndDateTime DateTime
) Returns Varchar(10)
As
Begin
Declare #Seconds Int,
#Minute Int,
#Hour Int,
#Elapsed Varchar(10)
Select #Seconds = ABS(DateDiff(SECOND ,#StartDateTime,#EndDateTime))
If #Seconds >= 60
Begin
select #Minute = #Seconds/60
select #Seconds = #Seconds%60
If #Minute >= 60
begin
select #hour = #Minute/60
select #Minute = #Minute%60
end
Else
Goto Final
End
Final:
Select #Hour = Isnull(#Hour,0), #Minute = IsNull(#Minute,0), #Seconds = IsNull(#Seconds,0)
select #Elapsed = Cast(#Hour as Varchar) + '':'' + Cast(#Minute as Varchar) + '':'' + Cast(#Seconds as Varchar)
Return (#Elapsed)
End'
)
declare #dt1 datetime='2012/06/13 08:11:12', #dt2 datetime='2012/06/12 02:11:12'
select CAST((#dt2-#dt1) as time(0))
PRINT DATEDIFF(second,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153')
select
datediff(millisecond,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153') / 1000.0 as Secs
result:
Secs
14.063
Just thought I'd mention it.
Sol-1:
select
StartTime
, EndTime
, CONVERT(NVARCHAR,(EndTime-StartTime), 108) as TimeDiff
from
[YourTable]
Sol-2:
select
StartTime
, EndTime
, DATEDIFF(hh, StartTime, EndTime)
, DATEDIFF(mi, StartTime, EndTime) % 60
from
[YourTable]
Sol-3:
select
DATEPART(hour,[EndTime]-[StartTime])
, DATEPART(minute,[EndTime]-[StartTime])
from
[YourTable]
Datepart works the best
Please check below trick to find the date difference between two dates
DATEDIFF(DAY,ordr.DocDate,RDR1.U_ProgDate) datedifff
where you can change according your requirement as you want difference of days or month or year or time.
CREATE FUNCTION getDateDiffHours(#fdate AS datetime,#tdate as datetime)
RETURNS varchar (50)
AS
BEGIN
DECLARE #cnt int
DECLARE #cntDate datetime
DECLARE #dayDiff int
DECLARE #dayDiffWk int
DECLARE #hrsDiff decimal(18)
DECLARE #markerFDate datetime
DECLARE #markerTDate datetime
DECLARE #fTime int
DECLARE #tTime int
DECLARE #nfTime varchar(8)
DECLARE #ntTime varchar(8)
DECLARE #nfdate datetime
DECLARE #ntdate datetime
-------------------------------------
--DECLARE #fdate datetime
--DECLARE #tdate datetime
--SET #fdate = '2005-04-18 00:00:00.000'
--SET #tdate = '2005-08-26 15:06:07.030'
-------------------------------------
DECLARE #tempdate datetime
--setting weekends
SET #fdate = dbo.getVDate(#fdate)
SET #tdate = dbo.getVDate(#tdate)
--RETURN #fdate
SET #fTime = datepart(hh,#fdate)
SET #tTime = datepart(hh,#tdate)
--RETURN #fTime
if datediff(hour,#fdate, #tdate) <= 9
RETURN(convert(varchar(50),0) + ' Days ' + convert(varchar(50),datediff(hour,#fdate, #tdate))) + ' Hours'
else
--setting working hours
SET #nfTime = dbo.getV00(convert(varchar(2),datepart(hh,#fdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#fdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#fdate)))
SET #ntTime = dbo.getV00(convert(varchar(2),datepart(hh,#tdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#tdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#tdate)))
IF #fTime > 17
begin
set #nfTime = '17:00:00'
end
else
begin
IF #fTime < 8
set #nfTime = '08:00:00'
end
IF #tTime > 17
begin
set #ntTime = '17:00:00'
end
else
begin
IF #tTime < 8
set #ntTime = '08:00:00'
end
-- used for working out whole days
SET #nfdate = dateadd(day,1,#fdate)
SET #ntdate = #tdate
SET #nfdate = convert(varchar,datepart(yyyy,#nfdate)) + '-' + convert(varchar,datepart(mm,#nfdate)) + '-' + convert(varchar,datepart(dd,#nfdate))
SET #ntdate = convert(varchar,datepart(yyyy,#ntdate)) + '-' + convert(varchar,datepart(mm,#ntdate)) + '-' + convert(varchar,datepart(dd,#ntdate))
SET #cnt = 0
SET #dayDiff = 0
SET #cntDate = #nfdate
SET #dayDiffWk = convert(decimal(18,2),#ntdate-#nfdate)
--select #nfdate,#ntdate
WHILE #cnt < #dayDiffWk
BEGIN
IF (NOT DATENAME(dw, #cntDate) = 'Saturday') AND (NOT DATENAME(dw, #cntDate) = 'Sunday')
BEGIN
SET #dayDiff = #dayDiff + 1
END
SET #cntDate = dateadd(day,1,#cntDate)
SET #cnt = #cnt + 1
END
--SET #dayDiff = convert(decimal(18,2),#ntdate-#nfdate) --datediff(day,#nfdate,#ntdate)
--SELECT #dayDiff
set #fdate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + #nfTime
set #tdate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + #ntTime
set #markerFDate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + '17:00:00'
set #markerTDate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + '08:00:00'
--select #fdate,#tdate
--select #markerFDate,#markerTDate
set #hrsDiff = convert(decimal(18,2),datediff(hh,#fdate,#markerFDate))
--select #hrsDiff
set #hrsDiff = #hrsDiff + convert(int,datediff(hh,#markerTDate,#tdate))
--select #fdate,#tdate
IF convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate))
BEGIN
--SET #hrsDiff = #hrsDiff - 9
Set #hrsdiff = datediff(hour,#fdate,#tdate)
END
--select FLOOR((#hrsDiff / 9))
IF (#hrsDiff / 9) > 0
BEGIN
SET #dayDiff = #dayDiff + FLOOR(#hrsDiff / 9)
SET #hrsDiff = #hrsDiff - FLOOR(#hrsDiff / 9)*9
END
--select convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff) + ' Hours'
RETURN(convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff)) + ' Hours'
END
For Me This worked Perfectly
Convert(varchar(8),DATEADD(SECOND,DATEDIFF(SECOND,LogInTime,LogOutTime),0),114)
and the Output is
HH:MM:SS which is shown accurately in my case.
Please try
DECLARE #articleDT DATETIME;
DECLARE #nowDate DATETIME;
-- Time of the ARTICLE created
SET #articleDT = '2012-04-01 08:10:16';
-- Simulation of NOW datetime
-- (in real world you would probably use GETDATE())
SET #nowDate = '2012-04-10 11:35:36';
-- Created 9 days ago.
SELECT 'Created ' + CAST(DATEDIFF(day, #articleDT, #nowDate) AS NVARCHAR(50)) + ' days ago.';
-- Created 1 weeks, 2 days, 3 hours, 25 minutes and 20 seconds ago.
SELECT 'Created '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 % 24 AS NVARCHAR(50)) + ' hours, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) % 60 AS NVARCHAR(50)) + ' seconds ago.';
For MS SQL, you can convert the datetime value to a double value.
The integer part contains the number of days since 1900-01-01, the fractional part contains the time in hours.
So you can calculate date difference as:
cast(date1-date2 as FLOAT)