Am a newbie to Lucene an working on a city search API using Lucene.
If user types in san francisco as search input, then it should give cities with exact match only and not San Jose /San Diego,etc.
How should i index city names in Lucene?and which Lucene analyzer and query class do i need to use?
Index your content with StandardAnalyzer. And then use PhraseQuery to search. For this, simply use the query string as "san francisco" with double quotes.
<?php
if(isset($_POST['submit']) && $_POST['submit']=='submit' ){
$city = $_POST['city'];
$query = "SELECT * FROM libreary WHERE city LIKE'".$city."'";
$row = mysqli_query($con,$query);
$result = mysqli_num_rows($row);
if($result>0){
while($row1 = mysqli_fetch_array($row)){
print_r($row1);
}
}
$respon['Response'] = $response;
print_r(json_encode($respon));
}
?>
Related
I'm not really sure how involved this might be, but could someone help me with below problem.
I'm trying to implement search functionality in my project based on employee firt and last name. I have used Spring Data REST and Hibernate Search for this purpose.
#Transactional
public search(String searchText) {
FullTextEntityManager fullTextEntityManager = org.hibernate.search.jpa.Search
.getFullTextEntityManager(entityManager);
QueryBuilder qb = fullTextEntityManager.getSearchFactory().buildQueryBuilder().forEntity(Employee.class).get();
org.apache.lucene.search.Query luceneQuery = qb.keyword().wildcard()
.onFields("firstName", "middleName", "lastName").matching(searchText + "*").createQuery();
javax.persistence.Query jpaQuery = fullTextEntityManager.createFullTextQuery(luceneQuery, Employee.class);
List result = jpaQuery.getResultList();
List<EmployeeSearchDTO> listOfDTO = new ArrayList<>();
EmployeeSearchDTO employeeDTO;
Iterator<Employee> itr = result.iterator();
while (itr.hasNext()) {
Employee employee = itr.next();
employeeDTO = new EmployeeSearchDTO(employee);
listOfDTO.add(employeeDTO);
}
}
When I search "john doe" i expect the results should match the below two
FirstName : John LastName : Doe
FirstName : johnathan LastName : Doe
But that is not the case and I'm able to search only based on FirstName["john"] or LastName["doe"] but not with both.
How do I solve this, any pointers would be greatly appreciated. Thanksin advance.
You really want to create two queries, one against the first name and one against the last name and then combine them via the SHOULD operator. Something like
Query combinedQuery = querybuilder
.bool()
.should( firstNameQuery )
.should( lastNameQuery )
.createQuery();
This means you are looking for results where either of the queries match.
So the over all on this is I have two different systems and in both systems I have customers, unfortunately both systems allow you to type in the business name freehand so you end up with the example below.
Column A has a value of "St John Baptist Church"
Column B has a value of "John Baptist St Church"
What I need to come up with is a query that can compare the two columns to find the most closely matched values.
From there I plan to write a web app where I can have someone go through and validate all of the entries. I would enter in some example of what I have done, but unfortunately I honestly dont even know if what I am asking for is even possible. I would think it is though in this day and age I am sure I am not the first one to try to attempt this.
You could try and create a script something like this php script to help you:
$words = array();
$duplicates = array();
function _compare($value, $key, $array) {
global $duplicates;
$diff = array_diff($array, $value);
if (!empty($diff)) {
$duplicates[$key] = array_keys($diff);
}
return $diff;
}
$mysqli = new mysqli('localhost', 'username', 'password', 'database');
$query = "SELECT id, business_name FROM table";
if ($result = $mysqli->query($query)) {
while ($row = $result->fetch_object()) {
$pattern = '#[^\w\s]+#i';
$row->business_name = preg_replace($pattern, '', $row->business_name);
$_words = explode(' ', $row->business_name);
$diff = array_walk($words, '_compare', $_words);
$words[$row->id][] = $_words;
$result->close();
}
}
$mysqli->close();
This is not tested but you need something like this, because I don't think this is possible with SQL alone.
---------- EDIT ----------
Or you could do a research on what the guys in the comment recommend Levenshtein distance in T-SQL
Hope it helps, good luck!
I'm trying to query the country table with the below query to print all countries with the corresponding cities. Now i'm getting a duplicated country object for each city instead of have one country object for all cities.
$all = ORM::factory('country')->select('cities.*')->join('cities','LEFT')->on('country.id', '=', 'country_id' )->find-all();
foreach ($all as $country) {
echo $caountry->name;
foreach($country->cities as $city ){
echo $city->name;
}
}
Appreciate your help,
AA
If you are using MySQL and only need the name of the city, you can use GROUP_CONCAT function and then convert it to array using PHP's explode.
$all = ORM::factory('country')
->select('country.name',DB::epxr('GROUP_CONCAT(cities.name) AS cities'))
->join('cities','LEFT')
->on('country.id', '=', 'country_id' )
->group_by("country.id")
->find-all();
foreach ($all as $country) {
echo $country->name;
foreach(explode(",",$country->cities) as $city ){
echo $city;
}
}
i have 3 tables city, information and state. In my code i've shown the different cites under different state. what i want to do is to get the seperate ids of the cities so that i can run some queries in my 'information' table.
My model is given below:
function get_status(){
$states = $this->db->get('state');
$like = array();
$status = array();
foreach ($states->result() as $state){
$cities = $this->db->get_where('city', array('state_id'=> $state->id));
$like=$cities->result();
$status=$like[0]->city_id;
}
echo $status;
}
but when i run the code i only get the last id of the last city stored under the last state in the the table. for example the state 3 has city that has id 3. i'm only getting this id. but i want all the ids of the cities like- 1,2,3.
i'm using Codeigniter framework.
Thanks in advance
$like - it`s an array.
[0] - the first element of an array.
echo $like[0]->city_id;
I haven`t tested it. (In one iteration -> it takes all the cities from that ID)
function get_status(){
$states = $this->db->get('state');
$like = array();
$status = array();
foreach ($states->result() as $state){
$cities = $this->db->get_where('city', array('state_id'=> $state->id));
foreach ($cities->result() as &$v){
echo $v->city_id."<br/>";
}
echo "......<br/>";
}
}
How to write SQL LIKE Query in drupal ,
SELECT title FROM { node } WHERE type='%s'
i want to add the LIKE CONDITION IN THAT
SELECT title FROM { node } WHERE type='%s' AND LIKE '%S%'
i think i writtern wrong like query formnat, can rewrite and tell me,
Just use % to escape.
$result = db_query('SELECT title FROM {node} WHERE type = "%s" AND title LIKE "%%%s%%"', 'type', 'title');
while ($row = db_fetch_object($result)) {
// do stuff with the data
}
Node type does not need escaping.
And here is an example with how to use LIKE in a dynamic query (Drupal 7 Only):
$query = db_select('node', 'n')
->fields('n', array('title'))
->condition('type', 'my_type')
->condition('title', '%' . db_like(search_string) . '%', 'LIKE');
$result = $query->execute()->fetchCol();
db_like() is used to escapes characters that work as wildcard characters in a LIKE pattern.
drupal_query replace %% to % and %s to value string
so your code will be
$sql = "SELECT title FROM node WHERE type='%%%s' AND title LIKE '%%%S%%'";
$type = "type to use in query";
$title = "title to use in query";
$result = db_result(db_query($sql, $type, $title));
OK, so you want the LIKE operator to refer to the title column. Use this query:
$sql = "SELECT title FROM node WHERE type='%s' AND title LIKE '%S%'";
$type = "type to use in query";
$title = "title to use in query";
$result = db_result(db_query($sql, $type, $title));
This is because the LIKE operator requires a column name to be specified. Otherwise, your database doesn't have any idea what value you want to perform the comparison on. See here.