I have one table and one column in it. There is 15 rows (integers). I want to count
the positive numbers and negative numbers, and also sum of total numbers in one query.
Can any one help me?
Or...
SELECT
COUNT(CASE WHEN Col > 0 THEN 1 END) AS NumPositives,
COUNT(CASE WHEN Col < 0 THEN 1 END) AS NumNegatives,
SUM(Col) AS Tot
FROM TableName;
Or you could consider using SIGN(Col), which gives 1 for positive numbers and -1 for negative numbers.
I'll give you psudeo code to help you with your homework.
3 aggregates:
SUM
SUM (CASE < 0)
SUM (CASE > 0)
select (select sum(mycolumn) from mytable where mycolumn > 0) as positive_sum,
(select sum(mycolumn) from mytable where mycolumn < 0) as negative_sum,
sum(mycolumn) as total_sum
from mytable
Try this
SELECT SUM(CASE WHEN Col > 0 THEN 1 ELSE 0 END) AS Pos,
SUM(CASE WHEN Col < 0 THEN 1 ELSE 0 END) AS Neg,
SUM(Col) AS Tot
FROM Table
Related
A table (ex: A) has three columns id, name, amount. Amount has some +ve,-ve and zero values. How to write a query to get the amount in such a way that it gives as a result first +ve then -ve then zeros? PFA for the sample table.
Thanks in advance
If you want 3 groups one after the other:
SELECT *
FROM tablename
ORDER BY
(CASE
WHEN amount > 0 then 1
WHEN amount < 0 then 2
ELSE 3
END),
Id;
Are you just looking for order by with a case expression?
select a.*
from a
order by (case when a.amount > 0 then 1
when a.amount < 0 then 2
else 3
end),
a.amount desc;
I have two queries and I want to get the maximum value of the two of them.
MAX((SELECT COUNT(p.[ItemID]) FROM [dbo].[Table] p WHERE HasHuman=0),
(SELECT COUNT(p.[ItemID]) FROM [dbo].[Table] p WHERE HasHuman=1))
You can calculate both result in a single query and then apply TOP:
select top 1
HasHuman,
COUNT(p.[ItemID]) as cnt
from [dbo].[Table]
group by HasHuman
order by cnt desc
You could even do this in a single query:
SELECT
CASE WHEN SUM(CASE WHEN HasHuman=0 THEN 1 ELSE 0 END) >
SUM(CASE WHEN HasHuman=1 THEN 1 ELSE 0 END)
THEN SUM(CASE WHEN HasHuman=0 THEN 1 ELSE 0 END)
ELSE SUM(CASE WHEN HasHuman=1 THEN 1 ELSE 0 END) END
FROM [dbo].[Table]
WHERE ItemID IS NOT NULL -- you were not counting NULLs
SELECT MAX(RC)
FROM (SELECT COUNT(p.ItemID) AS RC FROM dbo.[Table]
WHERE HasHuman=0
UNION
SELECT COUNT(p.ItemID) AS RC FROM dbo.[Table]
WHERE HasHuman=1
) A
how i can result like this ?
in my mind i can query = >
select id, count(no1, no2, no3) where no1='B',no2='B',no3='B'
thank's very much.
Use Case Statement
select id,
case when no1='B' then 1 else 0 END +
case when no2='B' then 1 else 0 END +
case when no3='B' then 1 else 0 END As Count_All
From yourtable
Use Case When statements with Count aggregate. Lastly, Group them with id:
Select id,
count(case when no1='B' then 1 END) +
count(case when no2='B' then 1 END) +
count(case when no3='B' then 1 END) AS count_all
From yourtable
Group by id
I'd like to have the average of a column when its bigger than zero.
Select Avg(Case when Column > 0 then Column else 0 end) as Avg
but I'm afraid the else clause is not correct. I want to ignore the zero values in the average.
Remove else part from case statement so the values less than 1 will be NULL.
Null values will be eliminated by the Avg aggregate. So you will get the average of values which are greater then 0. Try this.
Select Avg(Case when [Column]>0 then [Column] end) as [Avg]
DEMO
Without else part in case statement (Expected Average)
SELECT Avg(CASE WHEN a > 0 THEN a END) [Avg]
FROM (SELECT 2 a UNION ALL SELECT 2 UNION ALL SELECT -1) bb
Result : 2
With else part in case statement.
SELECT Avg(CASE WHEN a > 0 THEN a ELSE 0 END) [Avg]
FROM (SELECT 2 a UNION ALL SELECT 2 UNION ALL SELECT -1) bb
Result : 1
My table structure is this
id last_mod_dt nr is_u is_rog is_ror is_unv
1 x uuid1 1 1 1 0
2 y uuid1 1 0 1 1
3 z uuid2 1 1 1 1
I want the count of rows with:
is_ror=1 or is_rog =1
is_u=1
is_unv=1
All in a single query. Is it possible?
The problem I am facing is that there can be same values for nr as is the case in the table above.
Case statments provide mondo flexibility...
SELECT
sum(case
when is_ror = 1 or is_rog = 1 then 1
else 0
end) FirstCount
,sum(case
when is_u = 1 then 1
else 0
end) SecondCount
,sum(case
when is_unv = 1 then 1
else 0
end) ThirdCount
from MyTable
you can use union to get multiple results e.g.
select count(*) from table with is_ror=1 or is_rog =1
union
select count(*) from table with is_u=1
union
select count(*) from table with is_unv=1
Then the result set will contain three rows each with one of the counts.
Sounds pretty simple if "all in a single query" does not disqualify subselects;
SELECT
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_ror=1 OR is_rog=1) cnt_ror_reg,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_u=1) cnt_u,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_unv=1) cnt_unv;
how about something like
SELECT
SUM(IF(is_u > 0 AND is_rog > 0, 1, 0)) AS count_something,
...
from table
group by nr
I think it will do the trick
I am of course not sure what you want exactly, but I believe you can use the logic to produce your desired result.