I am trying to select data containing four percentage signs in a row. How can I escape the percentage signs so my LIKE condition works?
Thanks
Use #% with the escape character clause:
select *
from tbl
where fld like '%#%%' escape '#'
This will search for all records that contain the "%" character in the fld column.
DB2/z has a slightly different format:
select *
from tbl
where fld like {escape '#'} '%#%%'
Obviously, you'll need to choose your escape character carefully so it won't interfere with the rest of your string but this is relatively easy for static strings. Dynamically built strings will require dynamically built queries so that it doesn't use a character from the string.
Related
I need to find rows where col have special characters or numbers (except hyphen,apostrophe and space) in Oracle SQL.
I am doing like below:
SELECT *
FROM test
WHERE Name_test LIKE '%[^A-Za-z _]%'
But It is not working and I also need to exclude any apostrophe.
Kindly help.
If you need to find all rows where column have ONLY numbers and special characters (and you can specify all of required special characters):
SELECT *
FROM test
WHERE regexp_like(Name_test, q['^[0-9'%##]+$]')
as you can see you just need to add your special characters after 0-9.
^ - start
$ - end
About format q'[SOMETHING]' please see TEXT LITERALS here: https://docs.oracle.com/en/database/oracle/oracle-database/19/sqlrf/Literals.html#GUID-1824CBAA-6E16-4921-B2A6-112FB02248DA
If you need to find all rows where column have no alpha-characters:
SELECT *
FROM test
WHERE regexp_like(Name_test, '^[^a-zA-Z]*$');
or
SELECT *
FROM test
WHERE regexp_like(Name_test, '^\W*$');
about \W - please see "Table 8-5 PERL-Influenced Operators in Oracle SQL Regular Expressions" here:
https://docs.oracle.com/database/121/ADFNS/adfns_regexp.htm#ADFNS235
I need to find rows where col have special characters or numbers (except hyphen, apostrophe and space [and presumably single quotes]) in Oracle SQL.
You can use double single quotes to put a single quote in:
WHERE Name_test LIKE '%[^-A-Za-z _'']%'
However, this is not Oracle syntax. If the above works, then I would guess you are using SQL Server. In Oracle:
WHERE REGEXP_LIKE(Name_test, '[^A-Za-z _'']')
Database I'm using: https://uploadfiles.io/72wph
select acnum, field.fieldnum, title, descrip
from field, interest
where field.fieldnum=interest.fieldnum and trim(ID) like 'B.1._';
What will the output be from the above query?
Does trim(ID) like 'B.1._' mean that it will only select items from B.1._ column?
trim removes spaces at the beginning and end.
"_" would allow representing any character. Hence query select any row that starts with "B.1."
For eg.
'B.1.0'
'B.1.9'
'B.1.A'
'B.1.Z'
etc
Optional Wildcard characters allowed in like are % (percent) and _ (underscore).
A % matches any string with zero or more characters.
An _ matches any single character.
I don't know about the DB you are using but trim usually remove spaces around the argument you give to it.
The ID is trimmed to be sure to compare the ID without any white-space around it.
About your second question, Only the ROWS with an ID like 'B.1.' will be selected.
SQL like
SQL WHERE
Text = “World“ world ” <world <Word> ‘ word’ ‘ word“ word’ =1254.25 = 2545.58. 20%
Hey guys,
I need to search a word from a string which was saved in my db. The searching word contains special characters such as ""'!##$%^<>. Below is the sql select query used for the search.
select * from TABLE where TABLE.text like ('%'+ '“ World' +'%')
as a result some of the special character are not searched. Characters such as double quotation, single quotation are not searched from this. need assistance with solving this problem asap. thank you :)
These Special characters are Unicode characters, When ever dealing with these characters in sql server you have to tell sql server explicitly that there can be some unicode characters in the strings you are about to manipulate by prefixing your strings with N'String'
In your case you would write a query something like ....
select * from TABLE
where TABLE.text like N'%'+ N'“ World' + N'%'
you can use the ESCAPE clause and escape your parameter value. http://technet.microsoft.com/en-us/library/ms179859.aspx
so for example to search for a string containing the character %
select * from TABLE where TABLE.text like ('%'+ N'\%' +'%') ESCAPE '\'
i have a string value like 'Apple's'. i want to use this string in SQL "IN" clause like below query
select * from tbl_fruit where nm_fruit IN(''Apple's'','Orange');
how i can get the above query work correctly ?
Many Thanks,
Awais Afzal.
double the single quotes,
select * from tbl_fruit where nm_fruit IN ('Apple''s', 'Orange')
but if you do it on the application level, make sure you parameterized the query :)
I have found SQL correctly interprets the ASCII single-closed-quote (ALT 0146) as an apostrophe in searches while the "IN" treats it like any other character. Now I can search for 'Matt's Macintosh' using Matt(ASCII character 0146)s Macintosh" without messing up my list or the search.
It's pretty straightforward to strip out non-alphanumeric characters out from the search term, but how do you compare it to only the non-alphanumeric characters of values in the database?
For example, if I search for stack's, how can I get it to match both stacks and stack's?
What do I need to do to the what-do-i-do variable below to make the above happen?
SELECT * FROM table WHERE <what-do-i-do> ilike 'stacks'
One way to do this is with translate:
select *
from table
where translate(lower(WhatIDo), translate(lower(WhatIDo), 'abcdefghijklmnopqrstuvwxyz', ''), '') = 'stacks'
The inner translate finds all non-alpha characters. The outer then removes these from the string.
You can try to replace all instances of non-alphanumeric characters with the wildcard character ('%'). In your example:
SELECT * FROM table WHERE data like 'stack%s'