I believe my problem appeared somewhere on this site (of course they are resolved) but those solutions did not work for my case.
I have:
Table 1
isbn | in_count
123 | 3
124 | 1
Table 2
isbn | out_count
125 | 1
126 | 1
My expected result:
isbn | in_count | out_count
123 | 3 | 0
124 | 1 | 0
125 | 0 | 1
126 | 0 | 1
I've tried with the sql:
SELECT * FROM
(SELECT o.isbn, COUNT(*) AS out_count FROM out_tbl o GROUP BY o.isbn) t1
FULL OUTER JOIN
(SELECT i.isbn, COUNT(*) AS in_count FROM in_tbl i GROUP BY i.isbn) t2
ON t1.isbn = t2.isbn;
But what I got in return was:
isbn | in_count | isbn | out_count
123 | 3 | null | null
124 | 1 | null | null
null | null | 125 | 1
null | null | 126 | 1
Please help with this. Really appreciate!
SELECT T.isbn,T.in_count,0 AS out_count
FROM TABLE_1 AS T
UNION ALL
SELECT X.isbn,0,X.out_count
FROM TABLE_2 AS X
Related
I have a table which follows the state of the item delivery:
ID | ContractID | State
----------------------------------
1 | 125 | Created
2 | 125 | Activated
3 | 125 | PickupStarted
4 | 125 | PickedUp
5 | 125 | DeliveryStarted
6 | 125 | Delivered
7 | 126 | Created
8 | 126 | Activated
9 | 126 | PickupStarted
10 | 126 | PickedUp
11 | 126 | DeliveryStarted
12 | 126 | Delivered
13 | 127 | Created
14 | 127 | Activated
15 | 127 | PickupStarted
16 | 127 | PickedUp
I would like to create SQL query which counts only those 'ContractIds' which are not delivered yet (only those whose current status has reached 'PickedUp' status). In this case that would be 'ContractId' 127.
Is there a way to do that type of COUNT()?
You can use not exists:
select count(distinct contractId)
from t
where not exists (select 1
from t t2
where t2.contractId = t.contractid and
t2.status not like 'Deliver%'
);
Or, if you specifically want to get PickedUp as the last status:
select count(*)
from t
where t.id = (select max(t2.id) from t t2 2here t2.contractid = t.contractid) and
t.status = 'PickedUp';
The two are different. The second is specifically that the last status is PickedUp. The first is anyone that has not reached a "deliver" status.
I have the following three tables:
Permission
| PermissionId | PermissionName |
+--------------+----------------+
| 1 | A |
| 2 | B |
| 3 | C |
| 100 | D |
Group
| GroupId | GroupLevel | GroupName |
+---------+------------+----------------------+
| 1 | 0 | System Administrator |
| 7 | 0 | Test Group 100 |
| 8 | 20 | Test Group 200 |
| 9 | 20 | test |
| 10 | 50 | TestGroup01 |
| 11 | 51 | TestUser02 |
| 12 | 52 | TestUser03 |
GroupPermission
| GroupPermissionId | FkGroupId | FkPermissionId |
+-------------------+-----------+----------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 1 | 4 |
I need to insert records into GroupPermission table, if table Group, GroupLevel column have 0
then I need to take its GroupId and need to insert values to GroupPermission table as that particular id and 100.
In order to above sample table records, I need to insert the following two records to GroupPermission table,
| FkGroupId | FkPermissionId |
+-----------+----------------+
| 1 | 100 |
| 7 | 100 |
How can I do it
This question is not very clear and I can only assume the value 100 is a static value and that you don't actually have foreign keys as the names of the columns imply. Also, you really should avoid reserved words like "Group" for object names. It makes things more difficult and confusing.
The simple version of your insert might look like this.
insert GroupPermission
(
FkGroupId
, FkPermissionId
)
select g.GroupId
, 100
from [Group] g
where g.GroupLevel = 0
--EDIT--
Since you want to only insert those rows that don't already exist you can use NOT EXISTS like this.
select g.GroupId
, 100
from [Group] g
where g.GroupLevel = 0
AND NOT EXISTS
(
select *
from GroupPermission gp
where gp.FkGroupId = g.GroupId
and g.FkPermissionId = 100
)
Or you could use a left join like this.
select g.GroupId
, 100
from [Group] g
left join GroupPermission gp on gp.FkGroupId = g.GroupId
and gp.FkPermissionId = 100
where g.GroupLevel = 0
and gp.FkGroupId is null
I have following 3 tables and last entered reasoncode from Reasons table against each claimno in claims table.
Reasons:
Rid |chargeid| enterydate user reasoncode
-----|--------|-------------|--------|----------
1 | 210 | 04/03/2018 | john | 99
2 | 212 | 05/03/2018 | juliet | 24
5 | 212 | 26/12/2018 | umar | 55
3 | 212 | 07/03/2018 | borat | 30
4 | 211 | 03/03/2018 | Juliet | 20
6 | 213 | 03/03/2018 | borat | 50
7 | 213 | 24/12/2018 | umer | 60
8 | 214 | 01/01/2019 | john | 70
Charges:
chargeid |claim# | amount
---------|-------|---------
210 | 1 | 10
211 | 1 | 24.2
212 | 2 | 5.45
213 | 2 | 76.30
214 | 1 | 2.10
Claims:
claimno | Code | Code
--------|-------|------
1 | AH22 | AH22
2 | BB32 | BB32
Expected result would be like this:
claimno | enterydate | user | reasoncode
--------|-------------|--------|-----------
1 | 01/01/2019 | john | 70
2 | 26/12/2018 | umer | 55
I have applied many solutions but no luck. Following is the latest solution I was trying using SQL Server 2008 but still got incorrect result.
With x As
(
select r.chargeid,r.enterydate,ch.claimno from charges ch
join (select chargeid,max(enterydate) enterydate,user from Reasons group by chargeid) r on r.chargeid = ch.chargeid
)
select x.*,r1.user, r1.reasoncode from x
left outer join Reasons r1 on r1.chargeid = x.chargeid and r1.enterydate = x.enterydate
--group by x.claimno
Is this what you want?
select claimno, enterydate, user, reasoncode
from (select c.claimno, r.*,
row_number() over (partition by c.claimno order by r.entrydate desc) as seqnum
from charges c join
reasons r
on c.chargeid = r.chargeid
) cr
where seqnum = 1;
You can try using row_number()
select * from
(
select r.chargeid,r.enterydate,ch.claimno,user,reasoncode,
row_number() over(partition by ch.claimno order by r1.enterydate desc) as rn
from charges ch left outer join Reasons r1 on r1.chargeid = ch.chargeid
)A where rn=1
I have four tables:
mls_category
points_matrix
mls_entry
bonus_points
My first table (mls_category) is like below:
*--------------------------------*
| cat_no | store_id | cat_value |
*--------------------------------*
| 10 | 101 | 1 |
| 11 | 101 | 4 |
*--------------------------------*
My second table (points_matrix) is like below:
*----------------------------------------------------*
| pm_no | store_id | value_per_point | maxpoint |
*----------------------------------------------------*
| 1 | 101 | 1 | 10 |
| 2 | 101 | 2 | 50 |
| 3 | 101 | 3 | 80 |
*----------------------------------------------------*
My third table (mls_entry) is like below:
*-------------------------------------------*
| user_id | category | distance | status |
*-------------------------------------------*
| 1 | 10 | 20 | approved |
| 1 | 10 | 30 | approved |
| 1 | 11 | 40 | approved |
*-------------------------------------------*
My fourth table (bonus_points) is like below:
*--------------------------------------------*
| user_id | store_id | bonus_points | type |
*--------------------------------------------*
| 1 | 101 | 200 | fixed |
| 2 | 102 | 300 | fixed |
| 1 | 103 | 4 | per |
*--------------------------------------------*
Now, I want to add bonus points value into the sum of total distance according to the store_id, user_id and type.
I am using the following code to get total distance:
SELECT MIN(b.value_per_point) * d.total_distance FROM points_matrix b
JOIN
(
SELECT store_id, sum(t1.totald/c.cat_value) as total_distance FROM mls_category c
JOIN
(
SELECT SUM(distance) totald, user_id, category FROM mls_entry
WHERE user_id= 1 AND status = 'approved' GROUP BY user_id, category
) t1 ON c.cat_no = t1.category
) d ON b.store_id = d.store_id AND b.maxpoint >= d.total_distance
The above code is correct to calculate value, now I want to JOIN my fourth table.
This gives me sum (60*3 = 180) as total value. Now, I want (60+200)*3 = 780 for user 1 and store id 101 and value is fixed.
i think your query will be like below
SELECT Max(b.value_per_point)*( max(d.total_distance)+max(bonus_points)) FROM mls_point_matrix b
JOIN
(
SELECT store_id, sum(t1.totald/c.cat_value) as total_distance FROM mls_category c
JOIN
(
SELECT SUM(distance) totald, user_id, category FROM mls_entry
WHERE user_id= 1 AND status = 'approved' GROUP BY user_id, category
) t1 ON c.cat_no = t1.category group by store_id
) d ON b.store_id = d.store_id inner join bonus_points bp on bp.store_id=d.store_id
DEMO fiddle
I apologize if this is a duplicate question but I could not find my answer.
I am trying to take data that is horizontal, and get a count of how many times a specific number appears.
Example table
+-------+-------+-------+-------+
| Empid | KPI_A | KPI_B | KPI_C |
+-------+-------+-------+-------+
| 232 | 1 | 3 | 3 |
| 112 | 2 | 3 | 2 |
| 143 | 3 | 1 | 1 |
+-------+-------+-------+-------+
I need to see the following:
+-------+--------------+--------------+--------------+
| EmpID | (1's Scored) | (2's Scored) | (3's Scored) |
+-------+--------------+--------------+--------------+
| 232 | 1 | 0 | 2 |
| 112 | 0 | 2 | 1 |
| 143 | 2 | 0 | 1 |
+-------+--------------+--------------+--------------+
I hope that makes sense. Any help would be appreciated.
Since you are counting data across multiple columns, it might be easier to unpivot your KPI columns first, then count the scores.
You could use either the UNPIVOT function or CROSS APPLY to convert your KPI columns into multiple rows. The syntax would be similar to:
select EmpId, KPI, Val
from yourtable
cross apply
(
select 'A', KPI_A union all
select 'B', KPI_B union all
select 'C', KPI_C
) c (KPI, Val)
See SQL Fiddle with Demo. This gets your multiple columns into multiple rows, which is then easier to work with:
| EMPID | KPI | VAL |
|-------|-----|-----|
| 232 | A | 1 |
| 232 | B | 3 |
| 232 | C | 3 |
| 112 | A | 2 |
Now you can easily count the number of 1's, 2's, and 3's that you have using an aggregate function with a CASE expression:
select EmpId,
sum(case when val = 1 then 1 else 0 end) Score_1,
sum(case when val = 2 then 1 else 0 end) Score_2,
sum(case when val = 3 then 1 else 0 end) Score_3
from
(
select EmpId, KPI, Val
from yourtable
cross apply
(
select 'A', KPI_A union all
select 'B', KPI_B union all
select 'C', KPI_C
) c (KPI, Val)
) d
group by EmpId;
See SQL Fiddle with Demo. This gives a final result of:
| EMPID | SCORE_1 | SCORE_2 | SCORE_3 |
|-------|---------|---------|---------|
| 112 | 0 | 2 | 1 |
| 143 | 2 | 0 | 1 |
| 232 | 1 | 0 | 2 |