I have a directory and inside of the directory are subdirectories and a python file trying to run other files called Main.py. In each of the subdirectories there will be one file called runner.py with its only function I need to execute is “func”. If I want to use importlib.importmodule how would I go about doing that. As of right now I’m iterating over the directory and using:
filepath = sys.argv\[1\] + "/runner.py"
student_module = importlib.import_module("func", filepath)
But I’m afraid I don’t know how to use it properly as I’m new to python.
In case my words weren’t clear the directory architecture is as follows
Directory
->Main.py
->Subdirectory(1)
->runner.py
->Subdirectory(2)
->runner.py
.
.
.
->Subdirectory(n)
->runner.py
I had tried using the snippet of code above and I was expecting to be able to run the func from the different runner.py files. Unfortunately I’m getting a:
ModuleNotFoundError: No module named ‘func’
Related
target_link_libraries(${PROJECT_NAME}
serializer
iothub_client
iothub_client_mqtt_transport
umqtt
aziotsharedutil
ssl
crypto
curl
ssl..... utils)
Hello there , I am working on a project where I have a large set of libraries, and have use it like it (shown above). but instead of hardcoding these libraries explicitly,i want write it in a one line.
now I want to write it in a one line for linking, so specifically, what I have tried in the root level I have created a file called "library.lst" and in this .lst file I am giving the path of that library
build/src/con/shared/virtual/serializer/serializer.a"
build/src/con/shared/virtual/iothub_client/iothub_client.a"
build/src/con/shared/virtual/umqtt/ umqtt.a"
build/src/con/shared/virtual/utils/utlis.a
## write for every library
I am placing this .lst file in the folder called "filelist", e.g filelist/Library.lst where it will take all the libraries and will link.
so what I wrote this In each camkelists.txt where this library used by writing
file(STRINGS ${filelist} library) ,
target_link_libraries(${PROJECT NAME} ${library}),
but when I am running this script I an getting the errors like
"error:- "file strings requires and filename and output variable",
and I also have creates build.sh file where I am giving the path of it
"-D"filelist=%FILELISTSPATH%\library.lst"
" so could you please help me here and also need some explanation on it to understand it in a better way.Thanks in advance.
I tried to import System.Directory in my Frege program (In Eclipse) in order to use functions as getDirectoryContent, etc., and it writes me this error :
Could not import module frege.system.Directory (java.lang.ClassNotFoundException: frege.system.Directory)
What do I have to do ?
It is because the module frege.system.Directory doesn't exist in Frege. A good way to find out about a module is to use Hoogle for Frege at this URL: http://hoogle.haskell.org:8081. If we search for that module there, we can see that it doesn't list any module as opposed to, say, if you search for frege.data.List, we would see the module in the result.
Now for the functions you need like getDirectoryContent, if you look at the search result for frege.system.Directory, the first result is about processes and the third and fourth results are about jars and zip files. If you click on the second result, it would open the module frege.java.IO and you can see some relevant functions that might be useful for you (list for example). However the Haskell module you are trying to find is not yet ported to Frege but it should, of course, be possible to port that module backed by native Java implementations.
Update for OP's comment
Here is a simple snippet to return the files under a given directory:
ls :: String -> IO [String]
ls dir = do
contents <- File.new dir >>= _.list
maybe (return []) (JArray.fold (flip (:)) []) contents
Regarding createTempFile, the following works for me:
frege> File.createTempFile "test.txt"
String -> STMutable RealWorld File
I am trying to make a program that will write data to a file for another program to be able to read the data from it. The problem is that I can't figure out a way to do this when the file i am reading and writing from is in another directory than both of my programs. I know there are other ways of doing this, but I just thought that it would be useful to know how to do it. Anyone that can help me?
You can use the full path, e.g
local f1 = io.open('D:/test/b.txt') -- Windows
local f2 = io.open('/test/b.txt') -- Unix
or use relative path, e.g
local f = io.open('../../test/b.txt')
In this example, the file is in the test directory of the parent directory (..) of parent directory.
I'm trying to load group of folders files in one time with when
i set
sourceURI = 'gs://ybbi/bi_landing_zone/files_to_load/app/reports/app_network_analytics_report/201409011*'
all the folders that i'm want to load start with 20140911
but i get the error:
ERROR: Invalid path: gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/
20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0 is one of these folders(don't know why it's print the all folder name of this specific folder)
in some other folder tree cases it's works, but in this specific folder tree it's return the same error .
i know that cloud storage don't have real folders and it's part of the name of the object, but you understand what i mean.
is it bug?
Without more information, what it looks like is that you have a object file called gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/ that is not a csv/json file. Some tools may create these dummy files in order to simulate directories. BigQuery requires all objects that match the input glob path to be importable files.
One solution would be to change the glob path to include a narrower set of files. You can pass multiple paths if that makes things easier. For example, you could pass
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/*
and
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_some_other_path/*
is it possible to load module from file with extension other than .lua?
require("grid.txt") results in:
module 'grid.txt' not found:
no field package.preload['grid.txt']
no file './grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt/init.lua'
no file '/usr/local/lib/lua/5.1/grid/txt.lua'
no file '/usr/local/lib/lua/5.1/grid/txt/init.lua'
no file './grid/txt.so'
no file '/usr/local/lib/lua/5.1/grid/txt.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
no file './grid.so'
no file '/usr/local/lib/lua/5.1/grid.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
I suspect that it's somehow possible to load the script into package.preaload['grid.txt'] (whatever that is) before calling require?
It depends on what you mean by load.
If you want to execute the code in a file named grid.txt in the current directory, then just do dofile"grid.txt". If grid.txt is in a different directory, give a path to it.
If you want to use the path search that require performs, then add a template for .txt in package.path, with the correct path and then do require"grid". Note the absence of suffix: require loads modules identified by names, not by paths.
If you want require("grid.txt") to work should someone try that then yes, you'll need to manually loadfile and run the script and put whatever it returns (or whatever require is documented to return when the module doesn't return anything) into package.loaded["grid.txt"].
Alternatively, you could write your own loader just for entries like this which you set into package.preload["grid.txt"] which finds and loads/runs the file or, more generically, you could write yourself a loader function, insert it into package.loaders, and then let it do its job whenever it sees a "*.txt" module come its way.