Select
pnf_notas_processadas.pnf_notas_dest_cnpj_cpf,
Count(Distinct pnf_notas_processadas.pnf_notas_nnf) As destinadas,
Sum(0) As emitidas
From
pnf_notas_processadas
Group By
pnf_notas_processadas.pnf_notas_dest_cnpj_cpf
Having
pnf_notas_processadas.pnf_notas_dest_cnpj_cpf In ('03846642000102',
'03846642000285', '03846642000447', '03846642000528')
Union
Select
pnf_notas_processadas.pnf_notas_emit_cnpj_cpf,
Sum(0) As destinadas,
Count(Distinct pnf_notas_processadas.pnf_notas_nnf)
From
pnf_notas_processadas
Group By
pnf_notas_processadas.pnf_notas_emit_cnpj_cpf
Having
pnf_notas_processadas.pnf_notas_emit_cnpj_cpf In ('03846642000102',
'03846642000285', '03846642000447', '03846642000528')
result:
My expectation for the query
One method is to do the aggregation in one step. However, you need somehow to aggregate along two fields.
Here is a method. Essentially, the rows are "doubled" and then the aggregation pulls out the right values:
select (case when which = 1 then np.pnf_notas_dest_cnpj_cpf else pnf_notas_emit_cnpj_cpf end) as cnpj_cpf,
count(distinct case when which = 1 then np.pnf_notas_nnf end) as destinadas,
count(distinct case when which = 2 then np.pnf_notas_nnf end) as emitidas
from pnf_notas_processadas np cross join
(values (1), (2)) as v(which)
where np.pnf_notas_dest_cnpj_cpf In ('03846642000102', '03846642000285', '03846642000447', '03846642000528')
Group By cnpj_cpf;
I adjusted the query
select (case when which = 1 then pnf_notas_processadas.pnf_notas_dest_cnpj_cpf else pnf_notas_processadas.pnf_notas_emit_cnpj_cpf end) as cnpj_cpf,
count(distinct case when which = 1 then pnf_notas_processadas.pnf_notas_nnf end) as destinadas,
count(distinct case when which = 2 then pnf_notas_processadas.pnf_notas_nnf end) as emitidas
from pnf_notas_processadas cross join
(values (1), (2)) as v(wich)
where pnf_notas_processadas.pnf_notas_dest_cnpj_cpf In ('03846642000102', '03846642000285', '03846642000447', '03846642000528')
Group By cnpj_cpf;
but returned this error
select sentence invalidates unexpected element "2" on line 5 , position 16
Related
How can I use CASE statement or IF statement in WHERE clause ?
I am trying to apply a check on the basis of COUNT
SELECT * FROM sometable
WHERE CASE WHEN (SELECT COUNT(*) FROM sometable s WHERE SP = 2 AND sometable.id = s.id) > 2 THEN sometable.SP IS NOT NULL END
So basically if the count of rows is more than 1 it should apply IS NOT NULL condition else it should not.
Your logic suggests something like:
SELECT s.*
FROM (SELECT s.*,
SUM(CASE WHEN sp = 2 THEN 1 ELSE 0 END) OVER (PARTITION BY id) as cnt_2
FROM sometable s
) s
WHERE cnt_2 <= 2 OR s.sp is not null;
That seems equivalent. The logic doesn't seem particularly useful though.
I have a simple select query with some joins like:
SELECT
[c].[column1]
, [c].[column2]
FROM [Customer] AS [c]
INNER JOIN ...
So I do a left join with my principal table as:
LEFT JOIN [Communication] AS [com] ON [c].[CustomerGuid] = [com].[ComGuid]
this relatioship its 1 to *, one customer can have multiple communications
So in my select I want to get value 1 or 2 depending of condition:
Condition:
if ComTypeKey (from communication) table have a row with value 3 and have another row with vale 4 return 1 then 0
So I try something like:
SELECT
[c].[column1]
, [c].[column2]
, IIF([com].[ComTypeKey] = 3 AND [com].[ComTypeKey] = 4,1,0)
FROM [Customer] AS [c]
INNER JOIN ...
LEFT JOIN [Communication] AS [com] ON [c].[CustomerGuid] = [com].[ComGuid]
But it throws me two rows, beacause there are 2 rows on communication. My desire value is to get only one row with value 1 if my condition is true
If you have multiple rows you need GROUP BY, then count the relevant keys and subtract 1 to get (1, 0)
SELECT
[c].[column1]
, [c].[column2]
, COUNT(CASE WHEN [ComTypeKey] IN (3,4) THEN 1 END) - 1 as FLAG_CONDITION
FROM [Customer] AS [c]
INNER JOIN ...
LEFT JOIN [Communication] AS [com]
ON [c].[CustomerGuid] = [com].[ComGuid]
GROUP BY
[c].[column1]
, [c].[column2]
I'm not really sure I understand.
This will literally find if both values 3 and 4 exist for that CustomerGuid, and only select one of them in that case - not filtering out any record otherwise.
If this is not what you want, providing sample data with the expected result would remove the ambiguity.
SELECT Field1,
Field2,
...
FieldN
FROM (SELECT TMP.*,
CASE WHEN hasBothValues = 1 THEN
ROW_NUMBER() OVER ( PARTITION BY CustomerGuid ORDER BY 1 )
ELSE 1
END AS iterim_rn
FROM (SELECT TD.*,
MAX(CASE WHEN Value1 = '3' THEN 1 ELSE 0 END) OVER
( PARTITION BY CustomerGuid ) *
MAX(CASE WHEN Value1 = '4' THEN 1 ELSE 0 END) OVER
( PARTITION BY CustomerGuid ) AS hasBothValues
FROM TEST_DATA TD
) TMP
) TMP2
WHERE interim_rn = 1
I have following table named as 'Table',
Where I want result like following table where if you take first row and last three columns I want value to be 56.
I want sql server code for above table 'Table' and result to be second table. Here MaxV-1 and MaxV-2 are dependent on 'Number' column. MaxV-1 is max value out of FirstV, SecondV and ThirdV when Number is equal to 1 and same logic for MaxV-2.
One method is an unpivot and conditional aggreation:
select t.model,
max(case when t.number = 1 then t.pro_code end) as pro_code_1,
max(case when t.number = 2 then t.pro_code end) as pro_code_2,
max(case when t.number = 1 then v.v end) as max_val_1,
max(case when t.number = 2 then v.v end) as max_val_2
from t cross apply
(select max(v.v) as v
from (values (t.firstv), (t.secondv), (t.thirdv)) v(v)
) v
group by t.model;
I have a table called tbl_A with the following schema:
After insert, I have the following data in tbl_A:
Now the question is how to write a query for the following scenario:
Put (1) in front of any employee who was present three days consecutively
Put (0) in front of employee who was not present three days consecutively
The output screen shoot:
I think we should use case statement, but I am not able to check three consecutive days from date. I hope I am helped in this
Thank you
select name, case when max(cons_days) >= 3 then 1 else 0 end as presence
from (
select name, count(*) as cons_days
from tbl_A, (values (0),(1),(2)) as a(dd)
group by name, adate + dd
)x
group by name
With a self-join on name and available = 'Y', we create an inner table with different combinations of dates for a given name and take a count of those entries in which the dates of the two instances of the table are less than 2 units apart i.e. for each value of a date adate, it will check for entries with its own value adate as well as adate + 1 and adate + 2. If all 3 entries are present, the count will be 3 and you will have a flag with value 1 for such names(this is done in the outer query). Try the below query:
SELECT Z.NAME,
CASE WHEN Z.CONSEQ_AVAIL >= 3 THEN 1 ELSE 0 END AS YOUR_FLAG
FROM
(
SELECT A.NAME,
SUM(CASE WHEN B.ADATE >= A.ADATE AND B.ADATE <= A.ADATE + 2 THEN 1 ELSE 0 END) AS CONSEQ_AVAIL
FROM
TABL_A A INNER JOIN TABL_A B
ON A.NAME = B.NAME AND A.AVAILABLE = 'Y' AND B.AVAILABLE = 'Y'
GROUP BY A.NAME
) Z;
Due to the complexity of the problem, I have not been able to test it out. If something is really wrong, please let me know and I will be happy to take down my answer.
--Below is My Approch
select Name,
Case WHen Max_Count>=3 Then 1 else 0 end as Presence
from
(
Select Name,MAx(Coun) as Max_Count
from
(
select Name, (count(*) over (partition by Name,Ref_Date)) as Coun from
(
select Name,adate + row_number() over (partition by Name order by Adate desc) as Ref_Date
from temp
where available='Y'
)
) group by Name
);
select name as employee , case when sum(diff) > =3 then 1 else 0 end as presence
from
(select id, name, Available,Adate, lead(Adate,1) over(order by name) as lead,
case when datediff(day, Adate,lead(Adate,1) over(order by name)) = 1 then 1 else 0 end as diff
from table_A
where Available = 'Y') A
group by name;
I'm after a CTE which I want to return two columns, one with the total number of 1's and one with the total number of 0's. Currently I can get it to return one column with the total number of 1's using:
WITH getOnesAndZerosCTE
AS (
SELECT COUNT([message]) AS TotalNo1s
FROM dbo.post
WHERE dbo.checkletters([message]) = 1
--SELECT COUNT([message]) AS TotalNo0s
--FROM dbo.post
--WHERE dbo.checkletters([message]) = 0
)
SELECT * FROM getOnesAndZerosCTE;
How do I have a second column called TotalNo0s in the same CTE which I have commented in there to show what I mean.
Using conditional aggregation:
WITH getOnesAndZerosCTE AS(
SELECT
TotalNo1s = SUM(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 ELSE 0 END),
TotalNo0s = SUM(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 ELSE 0 END)
FROM post
)
SELECT * FROM getOnesAndZerosCTE;
For using COUNT() directly just be aware that it counts any NON-NULL values. You can omit the ELSE condition which implicitly returns NULL if not stated
SELECT
COUNT(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 END) TotalNo1s
, COUNT(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 END) TotalNo0s
FROM post
or, explicitly state NULL
SELECT
COUNT(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 ELSE NULL END) TotalNo1s
, COUNT(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 ELSE NULL END) TotalNo0s
FROM post
You can do it without CTE
select count(message) total,
dbo.checkletters(message) strLength
from post
group by dbo.checkletters(message)
having dbo.checkletters(message) in (1, 2) //All the messages with length 1 or 2