I am new to openLDAP.
When I create a new user (generic user), there is a field GID number.
Can somebody explain what this field means?
Does this number needs to be unique? I can select between my posixGroups.
I have the same posixgroups in each country (OU): users, admin, linux.
When I have the list of posixGroups in the GIDnumber, there I cannot see which group from which ou I need to select? How can I solve this?
When you select a posixsgroup for a new user. When I go to that selected group, how can I see that the new user is a member of that group?
Kr,
Joeri
With the gidNumber-attribute you can set the primary group of a user. That group will be used for instance when the user creates a file in a unix-like filesystem in that the file will belong to that group. And it doesn't need to be unique.
As you created the same group names under different subtrees there is no easy way to differentiate between those equally named groups. Easiest solution would be to rename those groups to include a hint to the subtree. But to be honest Personally I'd see whether it is necessary to have the same group in different subtrees and try to consilidate that to only three groups.
Related
I'm looking for a way to migrate data from LDAP-hosted groups to Google Groups.
With GCDS only the users are migrated, but I would like to migrate the data, do you know any way?
Thanks team
I've migrate groups between different directories using custom-written scripts. This requires some type of mapping between IDs. That is I know the fully qualified DN of each member within the LDAP-hosted group, I can match that up to a record in the new directory -- e.g. cn=lisa,ou=users,o=example has uid lisaj, and there's a corresponding account with the logon id lisaj in the new directory. I've had to do migrations where there was no direct correlation available within the two directories, and successfully linked the two systems using a text file with cross-reference info. A line in the file might say "lisaj 019485-B9184A-9284C-1949" to map my user id in the old system to a record identifier in the new one.
Basic process:
Connect to source LDAP
Find all in-scope groups For each in-scope group, get member list
Find the corresponding group in the new directory (if none exists,
create it)
For each member, find corresponding account in new
directory
Add member to group in new directory
(https://developers.google.com/admin-sdk/directory/v1/reference/members/insert
for Google Groups,
https://github.com/alfasin/Google-Admin-Directory-API has some Python
examples)
As a one-off process, it's pretty simple. If you need the two directories to remain in sync for some time, the script becomes a little more complicated. Assuming the old directory is "authoritative" (the one with the 'right' data -- and you can only make changes in one of the directories, otherwise it's impossible to tell which members actually should be in the group), you need to check the new directory group for any members that aren't a member of the old directory group and remove them as well as add any old directory group members that aren't in the new directory group yet. I generally add a "last modified" constraint to the filter used to locate groups in the old directory -- e.g. find all group objects where the lastModified timestamp is in the past 24 hrs -- to avoid continually reprocessing data for groups that haven't changed.
New to LDAP. The way our LDAP is arranged is People and groups. The people have user information such as name, uid, and mail. The groups have group name and multiple member field which has value like cn=First Last,cn=people,dc=comic,dc=com, listing the People that are members of the group.
Currently starting with userid and password, doing two searches:
1) Get user by searching on People base domain on uid=value. Then from the user get the first and last name.
2) Search on Groups base domain based on member=cn=First Last,cn=People,dc=comic,dc=com and iterate over the list of group objects returned to the group name field.
Am just wondering is there way to do all this in one search or are two searches necessary?
Unfortunately you cannot do what would like in one operation.
Also, what you are doing will not always work. Instead of retrieving the users first and last name you should retrieve their distinguished name (dn attribute) and do your group search based on that. First and last names can be modified within LDAP and can happen due to marriage / divorce / etc.
It is possible, provided that you implement a Reverse Group Membership Maintenance Overlay.
To determine which groups an entry is a member of without performing extra searches, the memberOf overlay is exactly what you need.
The memberof overlay updates an attribute (by default memberOf)
whenever changes occur to the membership attribute (by default member)
of entries of the objectclass (by default groupOfNames) configured to
trigger updates. Thus, it provides maintenance of the list of groups
an entry is a member of, when usual maintenance of groups is done by
modifying the members on the group entry.
You may find this Server Fault post useful for a how to.
Once you have memberOf attribute ready to be used, you may have to run ldapmodify manually on each group entries, but just once, so that all members entries can be provisioned with the corresponding group dn in their respective memberOf attribute.
Finally, to perform a group membership search for a given user, you would just search for the user entry and iterate the memberOf attribute to get group dn's.
What is the search filter to list users belong to specific group like "engineering" in a ldap server which don't have backlink enabled.
For example, if backlink enabled i can use following filter,
(&(objectClass=person)(memberOf=cn=engineering,ou=Groups,o=company,o=com))
Wanted to know corresponding search query without using memberOf attribute.
Thanks
DarRay
Try your filter as:
(&(objectClass=group)(cn=engineering))
using a base of
ou=Groups,o=company,o=com
and a scope of subtree
Returning attribute "member"
Or even more efficient:
(objectClass=group)
With a base of
cn=engineering,ou=Groups,o=company,o=com
and a scope of base
Returning attribute "member"
-jim
The main question is: How are the users linked to groups?
One way is by specifying the users as attributes in the group. That can be done either via the uniqueMember- or the memberUid-Attribute. To find the users of a certain group you will have to use two queries. One query will retrieve the DNs or UIDs of the users of a group by fetching the uniqueMember or memberUid attribute of the group in question depending on your setup. Then you can retrieve the users by either using (&(objectclass=person)(uid=<uid>)) or (&(objectclass=person)(dn=<dn>)).
The other way is by storing the grous as attributes in the user, which you described above.
Hope that helps.
Is there any LDAP command to delete all users attached to a specific group. Assume there are user1,user2,user3 assigned to group G1 . I want to delete all the users attached to group G1
Users are not attached to a group, entries are members of a group. To delete all entries that are members
of a group, execute a search that will return all of distinguished names that are members of the group:
make the base object of the search the distinguished name of the group
use (&) or (objectClass=*) for the filter. Some directory servers, for example Sun DSEE in certain
versions fail to properly parse the filter (&)
use base for the search scope
request the attribute type whose values are the distinguished names of the members of the groups. This varies,
but could be something like uniqueMember
Then, transmit a delete request for each distinguished name returned from the above search.
Some servers support referential integrity, if so, the members of the group will be deleted
at the same time as the entries are deleted.
See also
LDAP: Programming Practices
LDAP: Search best practices
I'm trying to make an LDAP query, to get a list from all my groups/members. I can't figure out how can i do this. All my tries were unsuccesfull.
My "AD tree": mydomain.local/Mybusiness/Distribution Groups/ here are my groups
I tried with somethin' like this:
(objectCategory=user)
(memberOf=CN=Distribution Groups,OU=Mybusiness,DC=mydomain.local,DC=com)
I appreciate if somebody could help me to write an ldap query, which gives a list with my groups and the members of this groups.
The query should be:
(&(objectCategory=user)(memberOf=CN=Distribution Groups,OU=Mybusiness,DC=mydomain.local,DC=com))
You missed & and ()
Active Directory does not store the group membership on user objects. It only stores the Member list on the group. The tools show the group membership on user objects by doing queries for it.
How about:
(&(objectClass=group)(member=cn=my,ou=full,dc=domain))
(You forgot the (& ) bit in your example in the question as well).
The good way to get all the members from a group is to, make the DN of the group as the searchDN and pass the "member" as attribute to get in the search function. All of the members of the group can now be found by going through the attribute values returned by the search.
The filter can be made generic like (objectclass=*).