I want to convert a value of 8:00 to either a 8 OR a 8.00 so then I can multiply this number to another INT value such as 2.
Right now I get a error message saying:
Conversion failed when converting the nvarchar value '8:00' to data type int.
I have tried CAST(MYCOLUMN AS INT) but it did not work.
Can you kindly help?
Best Regards,
I'm still not sure what you're doing, however it is it actually a time and you want they hour you can do this.
SELECT DATEPART(HOUR, CAST('8:00' AS TIME));
EDIT:
SQL 2005 doesn't have the TIME data type so you'd have to do this.
SELECT DATEPART(HOUR, CAST('1900-01-01 ' + '8:00' AS DATETIME));
How about:
CAST(replace(MYCOLUMN, ':', '.') AS float)
(This assumes that your internationalization settings interpret . as a decimal place.)
or
CAST(left(mycolumn, charindex(':', mycolumn) - 1) as int)
Related
I'm working on a legacy database and need to parse info from one database to another, parsing it into the new database is easy enough but first I need to create the query to convert and cast the following in the legacy SQL Server database:
WorkedHours(NVARCHAR(10)) is in text format 07:30
I need to convert and cast this as a decimal ie 7.5
I have searched around for the answer to this but can not find anything that has worked, so thought I would put it out there to see if any of you has any ideas.
Edit - What I should of asked is. What is causing an error converting to an int from a character with a value of 0 when trying to trying to convert and cast a time to a decimal?
DATEDIFF(
MINUTE,
0,
CAST('07:30' AS TIME)
)
/
60.0
Works up to '23:59' only
EDIT:
Based on a comment elsewhere, you have some 'bad' values.
This may find them...
SELECT
*
FROM
yourTable
WHERE
TRY_CONVERT(TIME, worked_hours) IS NULL
And as such, this is a safer version of my expression....
DATEDIFF(
MINUTE,
0,
TRY_CONVERT(TIME, worked_hours)
)
/
60.0
(Returns NULL for values that failed to parse.)
There's no reason to pull out the date/time types. Just do some simple string parsing:
cast(left(right('0' + WorkedHours, 5), 2) as int)
+ cast(right(WorkedHours, 2) as int) / 60.00
This won't have any limitations on 24 hours or anything like that. It just assumes that you've got one or two digits before a colon and two digits after.
This should work in SQL Server and an example-string "1101:56" (1101h & 56 minutes) | in general from 0h to >24h:
-- Take all hours before ":" and all Minutes (2 digits) after ":" and convert it to decimal.
select convert(decimal,left('1101:56',CHARINDEX(':','1101:56')-1)) + ( convert(decimal,right('1101:56',2))/60 );
-- with column-placeholder "time_str_from_table"
select convert(decimal,left(time_str_from_table,CHARINDEX(':',time_str_from_table)-1)) + ( convert(decimal,right(time_str_from_table,2))/60 );
If the source table have NULL-Values, than use "ISNULL" with substitution-value "0.0":
-- with column-placeholder "time_str_from_table"
select isnull( ( convert(decimal,left(time_str_from_table,CHARINDEX(':',time_str_from_table)-1)) + ( convert(decimal,right(time_str_from_table,2))/60) ), 0.0);
I have gone through a bunch of posts here with this error and tried changing data types and used Convert but nothing seems to fix this. So I would like to ask for some help here. I will try to give as much info, but feel free to ask if its not enough.
This is where I am getting the error:
Insert into prompt(ID, Date)
select
ROW_NUMBER() over (order by b.IDLoc),
[dbo].[fn_GetGPtime](cast (replace(DateCollected, '/', '-') + ' ' + a.UTCTime as datetime))
from
Img a
inner join
Tloc b on a.Filename = b.filename
order by
b.IDLoc
The Date column in prompt table has a datatype of float. UTCTime and DateCollected are both varchar(20)
The error is:
Msg 242, Level 16, State 3, Line 274
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Here is the function:
[dbo].[fn_GetGPtime] (#UTCtime datetime)
returns varchar(50)
AS
BEGIN
return (DATEPART (WEEKDAY, #UTCtime) - 1) * 86400 ---day
+ DATEPART (HOUR, #UTCtime) * 3600 ---hour
+ DATEPART (MINUTE, #UTCtime) * 60 ----minutes
+ DATEPART (SECOND, #UTCtime) ---second
+ (DATEPART (MILLISECOND, #UTCtime)) * 0.001 ---ms
+ (DATEPART (MICROSECOND, #UTCtime)) * 0.000001 ---us
+ 16 ----leap seconds
end;
To get an idea of the data itself:
How do I fix this issue?
Your error message could mean two different things: that you have non-convertible data in some cells, or that field's data are not convertible to datetime at all.
You can use try_convert instead of convert to figure out which it is. It will solve your problem if you have a few completely unusable values (i.e. bad data); you'll get nulls for bad data and good conversion for good data. If the overall conversion is never going to work you'll get all nulls and you'll know it isn't just a few bad values.
Another thing you could try is converting from float to numeric before converting to datetime. I find that float formatted data are awful for conversions and converting to numeric can remove many issues. You'd have something like convert(datetime, convert(numeric(18,2), UTCTime))
Use convert instead of cast. When using convert, you can specify the format of the string representing the date.
Once you've converted DateCollected to datetime, you can cast a.UTCTime to datetime and add them together:
Insert into prompt(ID,Date)
select ROW_NUMBER() over (order by b.IDLoc),
[dbo].[fn_GetGPtime](convert(datetime, DateCollected, 101) + cast(a.UTCTime as datetime))
from Img a inner join Tloc b on a.Filename=b.filename
order by b.IDLoc
(assuming a.UTCTime is either varchar or time)
What worked for me, solving this error on an input line such as
SELECT CAST(N'2003-12-01 14:20:47.000' AS DateTime) AS result
Msg 242 Level 16 ...
is the magic instruction:
SET DATEFORMAT ymd;
I am using SQL Server 2008R2.
I am trying to get part of a date in an output, and my column is in datetime datatype.
Eg,
If Current date and time is 2016-06-28 17:34:12.060, then I need output as 17:00 only the Hour with :00 mins.
I have tried this until now,
Select DateName(HH,SUBSTRING('2016-06-28 17:34:12.060',12,5)) +':00'
which gives me right output.But when I pass Column Name which is of datetime datatype, then it gives error,
Select DateName(HH,SUBSTRING(TimeInHour,12,5)) +':00'
gives error,
Argument data type time is invalid for argument 1 of substring function.
I know I am using SUBSTRING() at wrong place, But I really don't know how to achieve that output.
A help will be much appreciable.I need output as HH:00, Hour will be anything but 00 mins.
Why would you use substring() at all? The second argument to datename() should be a date/time data type. So, just do:
Select DateName(hour, '2016-06-28 17:34:12.060') + ':00'
Try this:
Select CAST(DATEPART(hour,'2016-06-28 17:34:12.060') AS VARCHAR(2)) +':00'
Below is the code that might be helpful
SELECT CONVERT(VARCHAR(50),DATEPART(YY,'2016-06-28 17:34:12.060')) -- Year
SELECT CONVERT(VARCHAR(50),DATEPART(mm,'2016-06-28 17:34:12.060')) -- Month
SELECT CONVERT(VARCHAR(50),DATEPART(d,'2016-06-28 17:34:12.060')) -- Day
SELECT CONVERT(VARCHAR(50),DATEPART(HH,'2016-06-28 17:34:12.060'))+':00' -- Hour
SELECT CONVERT(VARCHAR(50),DATEPART(mi,'2016-06-28 17:34:12.060'))+':00' -- Minutes
SELECT CONVERT(VARCHAR(50),DATEPART(ss,'2016-06-28 17:34:12.060')) -- Seconds
SELECT CONVERT(VARCHAR(50),DATEPART(ms,'2016-06-28 17:34:12.060')) -- Millisecond
You need to cast your DATETIME type column first, Use CAST function
Select DateName(HH,SUBSTRING(CAST(ColumnName AS VARCHAR(30)),12,5)) +':00'
Or alternative to do is Use LEFT and CONVERT
SELECT LEFT(CONVERT(VARCHAR, ColumnName ,108),2)+':00'
select convert(varchar, datepart(hour, getdate())) + ':' + convert(varchar, datepart(second, getdate()))
There is a column in my Table. In which we are storing string value in format 'HH:MM'.During fetching records with this table every things works ok with
DATEDIFF(MINUTE, '00:00', ColumnName)
Problem is when we have Value greater than 23:59.
Its showing error like
Conversion failed when converting date and/or time from character string.
Can anybody suggest me the right approach for achieving this scenario.
If you are storing the value as something other than a time, why not just store the number of minutes and convert to whatever format you want on output?
Otherwise, I would suggest that you simply convert the value to minutes:
select (cast(left(ColumnName, 2) as int) * 60 +
cast(right(ColumnName, 2) as int)
) as Minutes
If you are not using date/time values, there is no requirement for using the functions specifically designed for them.
EDIT:
To handle hours longer than 99, use charindex():
select (cast(left(ColumnName, charindex(':', ColumnName) - 1) as int) * 60 +
cast(right(ColumnName, 2) as int)
) as Minutes
So it sounds like your saving the length of a time period. Try storing it in minutes. My query can handle numbers of different lengths since it's based on the colon.
DECLARE #yourTable TABLE (ColumnName VARCHAR(10));
INSERT INTO #yourTable
VALUES ('100:00'),
('24:20');
SELECT ColumnName,
(hr * 60) + minut AS time_period_in_minutes
FROM #yourTable
CROSS APPLY (SELECT CAST(SUBSTRING(ColumnName,0,CHARINDEX(':',ColumnName)) AS INT),
CAST(SUBSTRING(ColumnName,CHARINDEX(':',ColumnName) + 1,LEN(ColumnName)) AS INT)) CA(hr,minut)
Results:
ColumnName time_period_in_minutes
---------- ----------------------
100:00 6000
24:20 1460
Try to this
select DATEDIFF(MINUTE, '00:00', case when ISDATE(ColumnName)=0 then '00:00' else ColumnName end )
I got a column called DateOfBirth in my csv file with Excel Date Serial Number Date
Example:
36464
37104
35412
When i formatted cells in excel these are converted as
36464 => 1/11/1999
37104 => 1/08/2001
35412 => 13/12/1996
I need to do this transformation in SSIS or in SQL. How can this be achieved?
In SQL:
select dateadd(d,36464,'1899-12-30')
-- or thanks to rcdmk
select CAST(36464 - 2 as SmallDateTime)
In SSIS, see here
http://msdn.microsoft.com/en-us/library/ms141719.aspx
The marked answer is not working fine, please change the date to "1899-12-30" instead of "1899-12-31".
select dateadd(d,36464,'1899-12-30')
You can cast it to a SQL SMALLDATETIME:
CAST(36464 - 2 as SMALLDATETIME)
MS SQL Server counts its dates from 01/01/1900 and Excel from 12/30/1899 = 2 days less.
tldr:
select cast(#Input - 2e as datetime)
Explanation:
Excel stores datetimes as a floating point number that represents elapsed time since the beginning of the 20th century, and SQL Server can readily cast between floats and datetimes in the same manner. The difference between Excel and SQL server's conversion of this number to datetimes is 2 days (as of 1900-03-01, that is). Using a literal of 2e for this difference informs SQL Server to implicitly convert other datatypes to floats for very input-friendly and simple queries:
select
cast('43861.875433912' - 2e as datetime) as ExcelToSql, -- even varchar works!
cast(cast('2020-01-31 21:00:37.490' as datetime) + 2e as float) as SqlToExcel
-- Results:
-- ExcelToSql SqlToExcel
-- 2020-01-31 21:00:37.490 43861.875433912
this actually worked for me
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-30')
(minus 1 more day in the date)
referring to the negative commented post
SSIS Solution
The DT_DATE data type is implemented using an 8-byte floating-point number. Days are represented by whole number increments, starting with 30 December 1899, and midnight as time zero. Hour values are expressed as the absolute value of the fractional part of the number. However, a floating point value cannot represent all real values; therefore, there are limits on the range of dates that can be presented in DT_DATE. Read more
From the description above you can see that you can convert these values implicitly when mapping them to a DT_DATE Column after converting it to a 8-byte floating-point number DT_R8.
Use a derived column transformation to convert this column to 8-byte floating-point number:
(DT_R8)[dateColumn]
Then map it to a DT_DATE column
Or cast it twice:
(DT_DATE)(DT_R8)[dateColumn]
You can check my full answer here:
Is there a better way to parse [Integer].[Integer] style dates in SSIS?
Found this topic helpful so much so created a quick SQL UDF for it.
CREATE FUNCTION dbo.ConvertExcelSerialDateToSQL
(
#serial INT
)
RETURNS DATETIME
AS
BEGIN
DECLARE #dt AS DATETIME
SELECT #dt =
CASE
WHEN #serial is not null THEN CAST(#serial - 2 AS DATETIME)
ELSE NULL
END
RETURN #dt
END
GO
I had to take this to the next level because my Excel dates also had times, so I had values like this:
42039.46406 --> 02/04/2015 11:08 AM
42002.37709 --> 12/29/2014 09:03 AM
42032.61869 --> 01/28/2015 02:50 PM
(also, to complicate it a little more, my numeric value with decimal was saved as an NVARCHAR)
The SQL I used to make this conversion is:
SELECT DATEADD(SECOND, (
CONVERT(FLOAT, t.ColumnName) -
FLOOR(CONVERT(FLOAT, t.ColumnName))
) * 86400,
DATEADD(DAY, CONVERT(FLOAT, t.ColumnName), '1899-12-30')
)
In postgresql, you can use the following syntax:
SELECT ((DATE('1899-12-30') + INTERVAL '1 day' * FLOOR(38242.7711805556)) + (INTERVAL '1 sec' * (38242.7711805556 - FLOOR(38242.7711805556)) * 3600 * 24)) as date
In this case, 38242.7711805556 represents 2004-09-12 18:30:30 in excel format
In addition of #Nick.McDermaid answer I would like to post this solution, which convert not only the day but also the hours, minutes and seconds:
SELECT DATEADD(s, (42948.123 - FLOOR(42948.123))*3600*24, dateadd(d, FLOOR(42948.123),'1899-12-30'))
For example
42948.123 to 2017-08-01 02:57:07.000
42818.7166666667 to 2017-03-24 17:12:00.000
You can do this if you just need to display the date in a view:
CAST will be faster than CONVERT if you have a large amount of data, also remember to subtract (2) from the excel date:
CAST(CAST(CAST([Column_With_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you need to update the column to show a date you can either update through a join (self join if necessary) or simply try the following:
You may not need to cast the excel date as INT but since the table I was working with was a varchar I had to do that manipulation first. I also did not want the "time" element so I needed to remove that element with the final cast as "date."
UPDATE [Table_with_Date]
SET [Column_With_Excel_Date] = CAST(CAST(CAST([Column_With_Excel_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you are unsure of what you would like to do with this test and re-test! Make a copy of your table if you need. You can always create a view!
Google BigQuery solution
Standard SQL
Select Date, DATETIME_ADD(DATETIME(xy, xm, xd, 0, 0, 0), INTERVAL xonlyseconds SECOND) xaxsa
from (
Select Date, EXTRACT(YEAR FROM xonlydate) xy, EXTRACT(MONTH FROM xonlydate) xm, EXTRACT(DAY FROM xonlydate) xd, xonlyseconds
From (
Select Date
, DATE_ADD(DATE '1899-12-30', INTERVAL cast(FLOOR(cast(Date as FLOAT64)) as INT64) DAY ) xonlydate
, cast(FLOOR( ( cast(Date as FLOAT64) - cast(FLOOR( cast(Date as FLOAT64)) as INT64) ) * 86400 ) as INT64) xonlyseconds
FROM (Select '43168.682974537034' Date) -- 09.03.2018 16:23:28
) xx1
)
For those looking how to do this in excel (outside of formatting to a date field) you can do this by using the Text function https://exceljet.net/excel-functions/excel-text-function
i.e.
A1 = 132134
=Text(A1,"MM-DD-YYYY") will result in a date
This worked for me because sometimes the field was a numeric to get the time portion.
Command:
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-31')