I have a bunch of dns entries in a file
a1.us.company.com ------ DO NOT PRINT
a2.us.us.company.com ------PRINT------ ("us" is repeated)
a3.eu.a3.compamy.com ------PRINT------ ("a3" is repeated)
a4.tx.a4.tx.company.com -----PRINT------- ("a4" and "tx" is repeated)
awk 'BEGIN {FS="."; OFS="."} {if ($2==$3) print $1"."$2"."$NF}' device_list
awk 'BEGIN {FS="."; OFS="."} {if ($1==$3) print $1"."$2"."$NF}' device_list
I am using 2 commands above.
Can someone please give me a awk command that lists duplicate columns per row.
Some of the names are crazy with as many as 7 to 8 . separated fields.
$ cat file
a1.us.company.com
a2.us.us.company.com
a3.eu.a3.compamy.com
a4.tx.a4.tx.company.com
$ awk -F'.' '{delete seen; for (i=1;i<=NF;i++) if (seen[$i]++) {print; next} }' file
a2.us.us.company.com
a3.eu.a3.compamy.com
a4.tx.a4.tx.company.com
Note that using delete seen is GNU-awk specific, with other awks you can delete the whole array by doing split("",seen).
$ awk -F. '{for(i=1;i<=NF;i++)if(x[$i]++){print;delete x;next}}' file
a2.us.us.company.com
a3.eu.a3.compamy.com
a4.tx.a4.tx.company.com
If you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk , /usr/xpg6/bin/awk , or nawk
Related
I have a file test.txt with the next lines
1997 100 500 2010TJ
2010TJXML 16 20 59
I'm using the next awk line to get information only about string 2010TJ
awk -v var="2010TJ" '$0 ~ var {print $0}' test.txt
But the code print the two lines. I want to know how to get the line containing the exact string
1997 100 500 2010TJ
the string can be placed in any column of the file.
Several options:
Use a gawk word boundary (not POSIX awk...):
$ gawk '/\<2010TJ\>/' file
An actual space or tab or what is separating the columns:
$ awk '/^2010TJ /' file
Or compare the field directly to the string:
$ awk '$1=="2010TJ"' file
You can loop over the fields to test each field if you wish:
$ awk '{for (i=1;i<=NF;i++) if ($i=="2010TJ") {print; next}}' file
Or, given your example of setting a variable, those same using a variable:
$ gawk -v s=2010TJ '$0~"\\<" s "\\>"'
$ awk -v s=2010TJ '$0~"^" s " "'
$ awk -v s=2010TJ '$1==s'
Note the first is a little different than the second and third. The first is the standalone string 2010TJ anywhere in $0; the second and third is a string that starts with that string.
Try this (for testing only column 1) :
awk '$1 == "2010TJ" {print $0}' test.txt
or grep like (all columns) :
gawk '/\<2010TJ\>/ {print $0}' test.txt
Note
\< \> is word boundarys
another awk with word boundary
awk '/\y2010TJ\y/' file
note \y matches either beginning or end of a word.
I have a file (; seperated) with data like this
111111121;000-000.1;000-000.2
111111211;000-000.1;000-000.2
111112111;000-000.1;000-000.2
111121111;000-000.1;000-000.2
111211111;000-000.1;000-000.2
112111111;000-000.1;000-000.2
121111112;000-000.2;020-000.8
121111121;000-000.2;020-000.8
121111211;000-000.2;020-000.8
121113111;000-000.3;000-200.2
211111121;000-000.1;000-000.2
I would like to remove any $3 that has less than 3 occurences, so the outcome would be like
111111121;000-000.1;000-000.2
111111211;000-000.1;000-000.2
111112111;000-000.1;000-000.2
111121111;000-000.1;000-000.2
111211111;000-000.1;000-000.2
112111111;000-000.1;000-000.2
121111112;000-000.2;020-000.8
121111121;000-000.2;020-000.8
121111211;000-000.2;020-000.8
121113111;000-000.3
211111121;000-000.1;000-000.2
That is, only $3 got deleted, as it had only a single occurence
Sadly I am not really sure if (thus how) this could be done relatively easily (as doing the =COUNT.IF matching, and manuel delete in Excel feels quite embarrassing)
$ awk -F';' 'NR==FNR{cnt[$3]++;next} cnt[$3]<3{sub(/;[^;]+$/,"")} 1' file file
111111121;000-000.1;000-000.2
111111211;000-000.1;000-000.2
111112111;000-000.1;000-000.2
111121111;000-000.1;000-000.2
111211111;000-000.1;000-000.2
112111111;000-000.1;000-000.2
121111112;000-000.2;020-000.8
121111121;000-000.2;020-000.8
121111211;000-000.2;020-000.8
121113111;000-000.3
211111121;000-000.1;000-000.2
or if you prefer:
$ awk -F';' 'NR==FNR{cnt[$3]++;next} {print (cnt[$3]<3 ? $1 FS $2 : $0)}' file file
this awk one-liner can help, it processes the file twice:
awk -F';' 'NR==FNR{a[$3]++;next}a[$3]<3{NF--}7' file file
Though that awk solutions are the best in terms of performance, your goal could be also achieved with something like this:
while IFS=" " read a b;do
if [[ "$a" -lt "3" ]];then
sed -i "s/$b//" b.txt
fi
done <<<"$(cut -d";" -f3 b.txt |sort |uniq -c)"
Operation is based on the output of cut which counts occurrences.
$cut -d";" -f3 b.txt |sort |uniq -c
7 000-000.2
1 000-200.2
3 020-000.8
Above works for editing source file in place, so keep a back up for testing.
You can feed the file twice to awk. On the first run you gather a statistic that you use in the second run:
script.awk
FNR == NR { stats[ $3 ]++
next
}
{ if( stats[$3] < 3) print $1 $2
else print
}
Run it like this: awk -F\; -f script.awk yourfile yourfile .
The condition FNR == NR is true during processing of the first filename given to awk. The next statement skips the second block.
Thus the second block is only used for processing the second filename given to awk (which is here the same as the first filename).
I have a file set up like
Words on
many line
%
More Words
on many lines
%
Even More Words
on many lines
%
and I would like to output the second to last record of this file where the record is delimited by % after each block of text.
I have used:
awk -v RS=\% ' END{ print NR }' $f
to find the number of records (1136). Then I did
awk -v RS=\% ' { print $(NR-1) }' $f
and
awk -v RS=\% ' { print $(NR=1135) }' $f
.
Neither of these worked, and, instead, displayed a record towards the beginning of the file and a many blank lines.
OUTPUT:
"You know, of course, that the Tasmanians, who never committed adultery, are
now extinct."
-- M. Somerset Maugham
"The
is
what
that
This output had many, many more blank lines and contains a record near the middle of the file.
awk -v RS=\% 'END{ print $(NR-1) }' $f
returns a blank line. The same command with different $(NR-x) values also returns a blank line.
Can someone help me to print the second to last record in this case?
Thanks
You can do:
awk '{this=last;last=$0} END{print this}' file
Or, if you don't mind having the entire file in memory:
awk '{a[NR]=$0} END{print a[NR-1]}' file
Or, if it is just line count (or record count) based, you can keep a rolling deletion going so you are not too piggish on memory:
$ seq 999999 | tail -2
999998
999999
$ seq 999999 | awk '{a[NR]=$0; delete a[NR-3]} END{print a[NR-1]}'
999998
If they are blocks of text the same method works if you can separate the blocks into delimited records.
Given:
$ echo "$txt"
Words on
many line
%
More Words
on many lines
%
Even More Words
on many lines
%
You can do:
$ echo "$txt" | awk -v RS=\% '{a[NR]=$0} END{print a[NR-1]}'
Even More Words
on many lines
$ echo "$txt" | awk -v RS=\% '{a[NR]=$0} END{print a[NR-2]}'
More Words
on many lines
If you want to not print the leading and trailing \n you can do:
$ echo "$txt" | awk 'BEGIN{RS="%\n"} {a[NR]=$0} END{printf a[NR-2]}'
Words on
many line
Finally, if you know the specific record you want to print, do it this way in awk:
$ seq 999999 | awk -v mrk=1135 'NR==mrk{print; exit}'
1135
If you want a random record, you can do:
$ awk -v min=1 -v max=1135 'BEGIN{srand()
RS="%\n"
tgt=int(min+rand()*(max-min+1))
}
NR==tgt{print; exit}' file
Does the solution have to be with awk? Just using head and tail would be simpler.
tail -2 file.txt | head 1 > justthatline.txt
The best way for this would be to use the BEGIN construct.
awk 'BEGIN{RS="%\n"; ORS="%\n"}(NR>=2){print}' file
RS and ORS set the input file and output record separators respectively.
echo 'NODE_1_length_317516_cov_18.568_ID_4005' | awk 'FS="_length" {print $1}'
Obtained output:
NODE_1_length_317516_cov_18.568_ID_4005
Expected output:
NODE_1
How is that possible? I'm missing something.
When you are going through lines using Awk, the field separator is interpreted before processing the record. Awk reads the record according the current values of FS and RS and goes ahead performing the operations you ask it for.
This means that if you set the value of FS while reading a record, this won't have effect for that specific record. Instead, the FS will have effect when reading the next one and so on.
So if you have a file like this:
$ cat file
1,2 3,4
5,6 7,8
And you set the field separator while reading one record, it takes effect from the next line:
$ awk '{FS=","} {print $1}' file
1,2 # FS is still the space!
5
So what you want to do is to set the FS before starting to read the file. That is, set it in the BEGIN block or via parameter:
$ awk 'BEGIN{FS=","} {print $1}' file
1,2 # now, FS is the comma
5
$ awk -F, '{print $1}' file
1
5
There is also another way: make Awk recompute the full record with {$0=$0}. With this, Awk will take into account the current FS and act accordingly:
$ awk '{FS=","} {$0=$0;print $1}' file
1
5
awk Statement used incorrectly
Correct way is
awk 'BEGIN { FS = "#{delimiter}" } ; { print $1 }'
In your case you can use
awk 'BEGIN { FS = "_length" } ; { print $1 }'
Inbuilt variables like FS, ORS etc must be set within a context i.e in 1 of the following blocks: BEGIN, condition blocks or END.
$ echo 'NODE_1_length_317516_cov_18.568_ID_4005' | awk 'BEGIN{FS="_length"} {print $1}'
NODE_1
$
You can also pass the delimiter using -F switch like this:
$ echo 'NODE_1_length_317516_cov_18.568_ID_4005' | awk -F "_length" '{print $1}'
NODE_1
$
I'm attempting to write a small script in bash. The script's purpose is to pull out a search pattern from file1.txt and to print the line number of the matching search from file2.txt. I know the exact place of the pattern that I want in file1.txt, and I can pull that out quite easily with sed and awk e.g.
sed -n 3p file1.txt | awk '{print $4}'
The part that I'm having trouble with is passing that information again to awk to use as a search pattern in file2.txt. Something along the lines of:
awk '/search_pattern/{print NR}' file2.txt
I was able to get this code working in two lines of code by storing the output of the first line as a variable, and passing that variable to awk in the second line,
myVariable=`sed -n 3p file1.txt | awk '{print $4}'`
awk '/'"$myVariable"'/{print NR}' file2.txt
but this seems "inelegant". I was hoping there was a way to do this in one line of code using file redirects (or something similar?). Any help is greatly appreciated!
You can avoid sed | awk with
awk 'NR==3{print $4; exit 0}' file1.txt
You can do your search with:
search=$(awk 'NR==3{print $4; exit 0}' file1.txt)
awk -v search="$search" '$0 ~ search { print NR }' file2.txt
You could even write that all on one line, but I don't recommend that; clarity is more important than brevity.
In principle, you could use:
awk 'NR==3{search = $4; next} FNR!=NR && $0 ~ search {print NR}' file1.txt file2.txt
This scans file1.txt and finds the search pattern; then it scans file2.txt and finds the lines that match. One line — even moderately clear. There'll be lots of matches if there isn't a column 4 on line 3 of file1.txt.