Check date between two dates in T-SQL - sql

I have a stored procedure where want check that a date is between a fixed date and the current date/time (with GETDATE()):
SELECT
a, b
FROM myTbl
WHERE
DATE BETWEEN 'Day start datetime' AND GETDATE()
...for example :
WHERE
DATE BETWEEN '2013-09-10 00:00:00.00' AND 'GETDATE()'
How to do it?

A pair of DATEADD/DATEDIFF calls will round a date down to the previous midnight:
SELECT a , b
FROM myTbl
WHERE DATE BETWEEN DATEADD(day,DATEDIFF(day,0,GETDATE()),0) and GETDATE()
Alternatively, if you're on SQL Server 2008 or later:
SELECT a , b
FROM myTbl
WHERE DATE BETWEEN CONVERT(date,GETDATE()) and GETDATE()

'GETDATE()' is a string literal, GETDATE() is a T-SQL function.
Your query should look like:
SELECT a , b
FROM myTbl
WHERE DATE BETWEEN '2013-09-10 00:00:00.0' and GETDATE()

I think WHERE DATE BETWEEN '2013-09-10 00:00:00.00' and GETDATE() (without the single quotes around the GETDATE() call) should work just fine.

You can get Day start date time by converting Getdate() return value to a Date type and again to Datetime as below.
select a,b
from myTbl
where [date] between convert(datetime,convert([date], getdate()))
and getdate()

Related

SQL, GETDATE in where clause

I am trying to use my query as the current day for my SQL query.
What I am trying below returns 0 records:
select *
from [TEST].[dbo].LIMIT
where endOfDay = GETDATE()
select *
from [TEST].[dbo].LIMIT
where endOfDay = dateadd(dd, datediff(dd, 0, getdate()), 0)
where endOfDay >= getdate() and endOfDay < getdate() + 1
An example date would be 2019-07-09 00:00:00.0
Also if there is no given date for today's date can I get a range of dates?
Any help would be appreciated, thanks.
First, you need to omit the quotes or else 'GETDATE()' is just a string.
Second, to match by "day", you need to strip the time part from the result of GETDATE(), which you can do by using CAST(GETDATE() as DATE) instead:
select *
from [TEST].[dbo].LIMIT
where endOfDay = CAST(GETDATE() as DATE)
For this to work best, the endOfDay column also needs to be of type DATE. If it is something else, you need to also CAST or CONVERT endOfDay to a DATE.
Using quotes makes it looking for a meaningless literal 'GETDATE()' to find nothing
You can use
with LIMIT(today, EndOfDay) as
(
select CONVERT(DATETIME, CONVERT(date, GETDATE())), GETDATE()
)
select EndOfDay
from LIMIT
where EndOfDay >= today and EndOfDay < today + 1;
Demo
Try this:
select *
from [TEST].[dbo].LIMIT
where cast(endOfDay as date) = cast(GETDATE() as date)
SQL Fiddle to see what the date will be compared with.
GETDATE() returns the server's current date and time. Unless you have any records that match that exactly, it doesn't make sense to use GETDATE. It doesn't look like you do based on the endOfDay column name.
The other criteria you show,
dateadd(dd,datediff(dd,0,getdate()),0) is essentially stripping the time off and returning midnight of the current date.
select getdate() 2019-07-11 15:10:09.287
select dateadd(dd,datediff(dd,0,getdate()),0) 2019-07-11 00:00:00.000
Assuming you don't care about time, convert both EndofDay and Getdate to a simple date for comparison.
select * from [TEST].[dbo].LIMIT where convert(date,EndOfDay) = convert(date,getdate())

retrieve day after tomorrow date query

I want to select day after tomorrow date in sql. Like I want to make a query which select date after two days. If I select today's date from calender(29-04-2015) then it should show date on other textbox as (01-05-2015). I want a query which retrieve day after tomorrow date. So far I have done in query is below:
SELECT VALUE_DATE FROM DLG_DEAL WHERE VALUE_DATE = GETDATE()+2
thanks in advance
Note that if you have a date field containing the time information, you will need to truncate the date part using DATEADD
dateadd(d, 0, datediff(d, 0, VALUE_DATE))
To compare 2 dates ignoring the date part you could just use DATEDIFF
SELECT VALUE_DATE FROM DLG_DEAL
WHERE datediff(d, VALUE_DATE, getdate()) = -2
or
SELECT VALUE_DATE FROM DLG_DEAL
WHERE datediff(d, getdate(), VALUE_DATE) = 2
Try like this:
SELECT VALUE_DATE
FROM DLG_DEAL WHERE VALUE_DATE = convert(varchar(11),(Getdate()+2),105)
SQL FIDDLE DEMO
SELECT VALUE_DATE FROM DLG_DEAL WHERE datediff(d, VALUE_DATE, getdate()) = -2
** I think you should try this**
SELECT DATEADD(day,2,VALUE_DATE) AS DayAfterTomorrow
FROM DLG_DEAL WHERE VALUE_DATE= GETDATE();
DATEADD(choiceToAdd, interval, date)
This function allows you to add or substract day,month, year,etc from date. In this interval is nothing but numeric value which you want to add or substract.

How to select data from 30 days?

I have query:
SELECT name
FROM (
SELECT name FROM
Hist_answer
WHERE id_city='34324' AND datetime >= DATE_SUB(CURRENT_DATE, INTERVAL 1 MONTH)
UNION ALL
SELECT name FROM
Hist_internet
WHERE id_city='34324' AND datetime >= DATE_SUB(CURRENT_DATE, INTERVAL 1 MONTH)
) x
GROUP BY name ORDER BY name
But DATE_SUB is a MySQL function and I need function for MsSQL 2008
Tell me please how to select data from 30 days by using MsSQL 2008?
P.S.: Data type of datetime is smalldatetime
You should be using DATEADD is Sql server so if try this simple select you will see the affect
Select DATEADD(Month, -1, getdate())
Result
2013-04-20 14:08:07.177
in your case try this query
SELECT name
FROM (
SELECT name FROM
Hist_answer
WHERE id_city='34324' AND datetime >= DATEADD(month,-1,GETDATE())
UNION ALL
SELECT name FROM
Hist_internet
WHERE id_city='34324' AND datetime >= DATEADD(month,-1,GETDATE())
) x
GROUP BY name ORDER BY name
Try this : Using this you can select date by last 30 days,
SELECT DATEADD(DAY,-30,GETDATE())
For those who could not get DATEADD to work, try this instead: ( NOW( ) - INTERVAL 1 MONTH )
Short version for easy use:
SELECT *
FROM [TableName] t
WHERE t.[DateColumnName] >= DATEADD(month, -1, GETDATE())
DATEADD and GETDATE are available in SQL Server starting with 2008 version.
MSDN documentation: GETDATE and DATEADD.

Comparing results with today's date?

Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()

SQL date question

I have a question. I have a SQL Server 2008 table with a field column. I have for example the Following dates:
1/1/2001
5/5/2004
8/5/2009
10/7/2011
5/5/2012
1/13/2014
Id like to be able to show all dates >= the current date (7/29/2011) as well as largest table date that is < current date. In this example, the result would be all dates >= 8/5/2009.
Can someone help guide me please??
select max(date) [date] from table where date < getdate()
union
select date from table where date >= getdate()
If I understand correctly, you want to include the date prior to the current date. GETDATE() will get the current date (with time). If you're alright with that, then this should work. Otherwise, you may have to parse out just the date from GETDATE()
SELECT TheDate
FROM DateTable
WHERE TheDate >= (SELECT MAX(TheDate) FROM DateTable WHERE TheDate < GETDATE())
This gets all dates greater than or equal to the most recent date before the current date.
I am not entirely sure I understand, but this looks like a BETWEEN the relevant dates. Or is there something more I am missing?
Assuming your table is called DateTable and your field is called TheDate, do it like this:
SELECT TheDate
FROM DateTable
WHERE TheDate >= DATEADD(d, -2, GETDATE())
Good luck!
It depends on the SQL server you're using. In postgres, for example, you need something like
SELECT fields FROM table WHERE date_field >= CURRENT_DATE - 1
But other SQL servers have different ways to specify "yesterday"
SELECT d1.*
FROM dates d1
LEFT JOIN dates d2 ON d1.Date < d2.Date AND d2.Date < GETDATE()
WHERE d2.Date IS NULL
Explanation:
Select every date for which there does not exist a date that is both earlier than today and later than the one being inspected.
Lots of guessing here based on loose narrative and unknown data types.
DECLARE #t TABLE(d DATE);
INSERT #t SELECT '20010101'
UNION ALL SELECT '20040505'
UNION ALL SELECT '20090805'
UNION ALL SELECT '20111007'
UNION ALL SELECT '20120505'
UNION ALL SELECT '20140113';
DECLARE #now DATE = SYSDATETIME();
WITH t AS
(
SELECT d, rn = ROW_NUMBER() OVER (ORDER BY d)
FROM #t
)
SELECT t.d
FROM t LEFT OUTER JOIN t AS x
ON t.rn = x.rn - 1
WHERE COALESCE(x.d, #now) >= #now
ORDER BY t.d;