I have thing problem here is the debugging outputs
"?uƒn74tn5187r&key=6e6e0936c4e6c48be56a72eba8964df0"
should be
"?u=83n74tn5187r&key=6e6e0936c4e6c48be56a72eba8964df0"
I have tried solution from another similar question and it failed me.
Dim uni As Byte() = Encoding.GetEncoding(437).GetBytes("?uƒn74tn5187r&key=6e6e0936c4e6c48be56a72eba8964df0")
Dim Ascii As String = Encoding.ASCII.GetString(uni)
Ascii =
"?u?n74tn5187r&key=6e6e0936c4e6c48be56a72eba8964df0"
I'm guessing I have to guess the 437.. maybe a brute force attack on all numbers until the match of ?u=83 from ?uƒ
Really I am trying to read a Unicode-32 (Brasil formatted text from email (POP3). Now that I think about it =83 could be messed up using this function here.
But without this function, the body of the POP3 email will contain maybe useless like variant of urlencode() but.. instead of %20 it uses =20.
I wonder how to fix this.
Public Shared Function DecodeQuotedPrintable(ByVal Message As String, Optional ByVal QuickClean As Boolean = False) As String
'set up StringBuilder object with data stripped of any line continuation tags
Dim Msg As New StringBuilder(Message.Replace("=" & vbCrLf, vbNullString))
If QuickClean Then 'perform a quick clean (clean up common basics)
Return Msg.Replace("=" & vbCrLf, vbNullString).Replace("=0D", vbCr).Replace("=0A", _
vbLf).Replace("=20", " ").Replace("=3D", "=").ToString
Else 'perform total cleaning
'store 2-character hex values that require a leading "0"
Dim HxData As String = "X0102030405060708090A0B0C0D0E0F"
For Idx As Integer = 1 To &HF 'initially process codes 1-15, which require a leading zero
Msg.Replace("=" & Mid(HxData, Idx << 1, 2), Chr(Idx)) 'replace hex data with single character code (SHIFT is faster)
Next
For idx As Integer = &H10 To &HFF 'process the whole 8-bit extended ASCII gambit
Msg.Replace("=" & Hex(idx), Chr(idx)) 'replace hex data with single character code
Next
Return Msg.ToString 'return result string
End If
End Function
Edit:
My attempt at fixing the function (if it really causes the problem? I'll never know)
Public Shared Function DecodeQuotedPrintable(ByVal Message As String, Optional ByVal QuickClean As Boolean = False) As String
'set up StringBuilder object with data stripped of any line continuation tags
Dim Msg As New StringBuilder(Message.Replace("=" & vbCrLf, vbNullString))
If QuickClean Then 'perform a quick clean (clean up common basics)
Return Msg.Replace("=" & vbCrLf, vbNullString).Replace("=0D", vbCr).Replace("=0A", _
vbLf).Replace("=20", " ").Replace("=3D", "=").ToString
Else 'perform total cleaning
'store 2-character hex values that require a leading "0"
Msg.Replace("=" & vbCrLf, vbNullString).Replace("=0D", vbCr).Replace("=0A", _
vbLf).Replace("=20", " ").Replace("=3D", "%$##[EQUALS]##$%").ToString()
Dim HxData As String = "X0102030405060708090A0B0C0D0E0F"
For Idx As Integer = 1 To &HF 'initially process codes 1-15, which require a leading zero
Msg.Replace("=" & Mid(HxData, Idx << 1, 2), Chr(Idx)) 'replace hex data with single character code (SHIFT is faster)
Next
For idx As Integer = &H10 To &HFF 'process the whole 8-bit extended ASCII gambit
Msg.Replace("=" & Hex(idx), Chr(idx)) 'replace hex data with single character code
Next
Msg.Replace("%$##[EQUALS]##$%", "=")
Return Msg.ToString 'return result string
End If
End Function
"ƒ" is represented by =83 in Quoted Printable encoding in the Windows-1252 character set.
Related
I have MS Access form where the user pastes a string into a field {Vars}, and I want to reformat that string into a new field so that (a) it retains whole words, and (b) "fits" within 70 columns.
Specifically, the user will be cutting/pasting variable names from SPSS. So the string will go into the field as whole names---no spaces allowed---with line breaks between each variable. So the first bit of VBA code looks like this:
Vars = Replace(Vars, vbCrLf, " ")
which removes the line breaks. But from there, I'm stumped---ultimately I want the long string that is pasted in the Vars field to be put on consecutive multiple lines that each are no longer than 70 columns.
Any help is appreciated!
Okay, for posterity, here is a solution:
The field name on the form that captures the user input is VarList. The call to the SPSS_Syntax function below returns the list of variable names (in "Vars") that can then be used elsewhere:
Vars = SPSS_Syntax(me.VarList)
Recall that user input into Varlist comes in as each variable (word) with a line break in between each. The problem is that we want the list to be on one line (horizontal, not vertical) AND a line can be no more than 256 characters in length (I'm setting it to 70 characters below). Here's the function:
Public Function SPSS_Syntax(InputString As String)
InputString = Replace(InputString, vbNewLine, " ") 'Puts the string into one line, separated by a space.
MyLength = Len(InputString) 'Computes length of the string
If MyLength < 70 Then 'if the string is already short enough, just returns it as is.
SPSS_Syntax = InputString
Exit Function
End If
MyArray = Split(InputString, " ") 'Creates the array
Dim i As Long
For i = LBound(MyArray) To UBound(MyArray) 'for each element in the array
MyString = MyString & " " & MyArray(i) 'combines the string with a blank space in between
If Len(MyString) > 70 Then 'when the string gets to be more than 70 characters
Syntax = Syntax & " " & vbNewLine & MyString 'saves the string as a new line
MyString = "" 'erases string value for next iteration
End If
Next
SPSS_Syntax = Syntax
End Function
There's probably a better way to do it but this works. Cheers.
I created a macro for removing all whitespace in a string, specifically an email address. However it only removes about 95% of the whitespace, and leaves a few.
My code:
Sub NoSpaces()
Dim w As Range
For Each w In Selection.Cells
w = Replace(w, " ", "")
Next
End Sub
Things I have tried to solve the issue include:
~ Confirmed the spaces are indeed spaces with the Code function, it is character 32 (space)
~ Used a substitute macro in conjuction with the replace macro
~ Have additional macro utilizing Trim function to remove leading and trailing whitespace
~ Made a separate macro to test for non-breaking spaces (character 160)
~ Used the Find and Replace feature to search and replace spaces with nothing. Confirmed working.
I only have one cell selected when I run the macro. It selects and goes through all the cells because of the Selection.Cells part of the code.
A few examples:
1 STAR MOVING # ATT.NET
322 TRUCKING#GMAIL.COM
ALEZZZZ#AOL. COM.
These just contain regular whitespace, but are skipped over.
Just use a regular expression:
'Add a reference to Microsoft VBScript Regular Expressions 5.5
Public Function RemoveWhiteSpace(target As String) As String
With New RegExp
.Pattern = "\s"
.MultiLine = True
.Global = True
RemoveWhiteSpace = .Replace(target, vbNullString)
End With
End Function
Call it like this:
Sub NoSpaces()
Dim w As Range
For Each w In Selection.Cells
w.Value = RemoveWhiteSpace(w.Value)
Next
End Sub
Try this:
Sub NoSpaces()
Selection.Replace " ", ""
End Sub
Use "Substitute"
Example...
=SUBSTITUTE(C1:C18," ","")
Because you assume that Selection.Cells includes all cells on the sheet.
Cells.Replace " ", ""
And to add to the excellent advice from all the great contributors, try the
TRIM or LTRIM, or RTRIM and you can read more about these functions here:
https://msdn.microsoft.com/en-us/library/office/gg278916.aspx
Now this does not remove embedded spaces (spaces in between the letters) but it will remove any leading and trailing spaces.
Hope this helps.
Space Problem with Excel
ok, the only way i see this two types of space is by converting their Ascii code value of which I do it here
now to explain this function i made, it will just filter the string character by character checking if its equal to the two types of space i mentioned. if not it will concatenate that character into the string which will be the final value after the loop. hope this helps. Thanks.
Function spaceremove(strs) As String
Dim str As String
Dim nstr As String
Dim sstr As String
Dim x As Integer
str = strs
For x = 1 To VBA.Len(str)
sstr = Left(Mid(str, x), 1)
If sstr = " " Or sstr = " " Then
Else
nstr = nstr & "" & sstr
End If
Next x
spaceremove = nstr
End Function
I copied a HTML table with data and pasted in excel but the cells were filled with unwanted space and all methods posted here didn't work so I debugged and I discovered that it wasn't actually space chars (ASCII 32) it was Non-breaking space) (ASCII 160) or HTML
So to make it work with that Non-breaking space char I did this:
Sub NoSpaces()
Dim w As Range
For Each w In Selection.Cells
w.Value = Replace(w.Value, " ", vbNullString)
w.Value = Replace(w.Value, Chr(160), vbNullString)
Next
End Sub
I'm rooky for VBA. I have some problem about reversing my data on VBA-Excel. My data is "3>8 , 6>15 , 26>41 (each data on difference cells)" that i could reverse "3>8" to "8>3" follow my requirement by using function reverse. But i couldn't reverse "6>15" and "26>41" to "15>6" and "41>26". It will be "51>6" and "14>62" that failure, I want to be "15>6" and "41>26".
Reverse = StrReverse(Trim(str))
Help me for solve my issue please and thank for comment.
You first need to find the position of the ">" in the cell. you do this by taking the contents of the cell and treating it as a String and finding the ">"
This is done in the line beginning arrowPosition. This is the integer value of the position of the ">" in you original string
Next use Left to extract the text up to the ">" and Right to extract the text after the ">"
Then build a new String of rightstr & ">" & leftStr.
Note I input my data from Sheet1 B5 but you can just use any source as long as it is a String in the correct format.
Sub Test()
Dim myString As String
myString = Sheets("Sheet1").Range("B5")
Debug.Print myString
Debug.Print reverseString(myString)
End Sub
Function reverseString(inputString As String) As String
Dim leftStr As String
Dim rightStr As String
Dim arrowPosition As Integer
arrowPosition = InStr(1, inputString, ">")
leftStr = Left(inputString, arrowPosition - 1)
rightStr = Right(inputString, Len(inputString) - arrowPosition)
reverseString = rightStr & ">" & leftStr
End Function
just because you look for a VBA, you can add this function into your code:
Function rev(t As String) As String
s = Split(t, ">", 2)
rev = s(1) & ">" & s(0)
End Function
of course only if you have to reverse 2 number, otherwise you'll loop the "s", but the function would lose its usefulness
I have a text file on my website and I download the whole string via webclient.downloadstring.
The text file contains this :
cookies,dishes,candy,(new line)
back,forward,refresh,(new line)
mail,media,mute,
This is just an example it's not the actual string , but it will do for help purposes.
What I want is I want to download the whole string , find the line that contains the word that was entered by the user in a textbox, get that line into a string, then I want to use the string.split with as delimiter the "," and output each word that is in the string into an richtextbox.
Now here is the code that I have used (some fields are removed for privacy reasons).
If TextBox1.TextLength > 0 Then
words = web.DownloadString("webadress here")
If words.Contains(TextBox1.Text) Then
'retrieval code here
Dim length As Integer = TextBox1.TextLength
Dim word As String
word = words.Substring(length + 1) // the plus 1 is for the ","
Dim cred() As String
cred = word.Split(",")
RichTextBox1.Text = "Your word: " + cred(0) + vbCr + "Your other word: " + cred(1)
Else
MsgBox("Sorry, but we could not find the word you have entered", MsgBoxStyle.Critical)
End If
Else
MsgBox("Please fill in an word", MsgBoxStyle.Critical)
End If
Now it works and no errors , but it only works for line 1 and not on line 2 or 3
what am I doing wrong ?
It's because the string words also contains the new line characters that you seem to be omitting in your code. You should first split words with the delimiter \n (or \r\n, depending on the platform), like this:
Dim lines() As String = words.Split("\n")
After that, you have an array of strings, each element representing a single line. Loop it through like this:
For Each line As String In lines
If line.Contains(TextBox1.Text) Then
'retrieval code here
End If
Next
Smi's answer is correct, but since you're using VB you need to split on vbNewLine. \n and \r are for use in C#. I get tripped up by that a lot.
Another way to do this is to use regular expressions. A regular expression match can both find the word you want and return the line that contains it in a single step.
Barely tested sample below. I couldn't quite figure out if your code was doing what you said it should be doing so I improvised based on your description.
Imports System.Text.RegularExpressions
Public Class Form1
Private Sub ButtonFind_Click(sender As System.Object, e As System.EventArgs) Handles ButtonFind.Click
Dim downloadedString As String
downloadedString = "cookies,dishes,candy," _
& vbNewLine & "back,forward,refresh," _
& vbNewLine & "mail,media,mute,"
'Use the regular expression anchor characters (^$) to match a line that contains the given text.
Dim wordToFind As String = TextBox1.Text & "," 'Include the comma that comes after each word to avoid partial matches.
Dim pattern As String = "^.*" & wordToFind & ".*$"
Dim rx As Regex = New Regex(pattern, RegexOptions.Multiline + RegexOptions.IgnoreCase)
Dim M As Match = rx.Match(downloadedString)
'M will either be Match.Empty (no matching word was found),
'or it will be the matching line.
If M IsNot Match.Empty Then
Dim words() As String = M.Value.Split(","c)
RichTextBox1.Clear()
For Each word As String In words
If Not String.IsNullOrEmpty(word) Then
RichTextBox1.AppendText(word & vbNewLine)
End If
Next
Else
RichTextBox1.Text = "No match found."
End If
End Sub
End Class
I have a strange problem here. In my code, variable b string, has the value "Test Test Test". This value we can see while debugging the variable as well as in the text visualizer.
Now the problem is, if I show the same string using Messagebox, the value is just "Test". What can I do here to get the complete value.
I am converting from an ebcdic encoded bytes to corresponding utf8 string and doing the above operation. Any thoughts. below is my sample code.
Dim hex As String = "e385a2a300000000e385a2a3000000e385a2a3"
Dim raw As Byte() = New Byte((hex.Length / 2) - 1) {}
Dim i As Integer
For i = 0 To raw.Length - 1
raw(i) = Convert.ToByte(hex.Substring((i * 2), 2), &H10)
Next i
Dim w As String = System.Text.Encoding.GetEncoding(37).GetString(raw)
Dim raw1 As Byte() = Encoding.UTF8.GetBytes(w)
Dim b As String = Encoding.UTF8.GetString(raw1)
MessageBox.Show(b)
Look at the byte array. You have 4 ASCII 0's after each "Test". ASCII character code 0 corresponds to nul, which is a string termination sequence. If you want spaces instead of nulls there...
Dim b As String = Encoding.UTF8.GetString(raw1).Replace(Chr(0), " ")
It is possible that the string "b" might contains some control character.
To test a control char in string.
For Each p As Char In b
MsgBox(p & " " & Char.IsControl(p) & " " & AscW(p))
Next
Use String#Replace to replace control chars.
b = b.Replace(ChrW(0), " ")
MsgBox(b)